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Program to convert Java list of characters to Seq in Scala
  • Last Updated : 14 Jan, 2020
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A java list of characters can be converted to sequence in Scala by utilizing toSeq method of Java in Scala. Here, we need to import Scala’s JavaConversions object in order to make this conversions work else an error will occur.
Now, lets see some examples and then discuss how it works in details.
Example:1#




// Scala program to convert Java list 
// to Sequence in Scala
  
// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._
  
  
// Creating object
object GfG
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating list of characters in Java
        val list = new java.util.ArrayList[Char]()
          
        // Adding characters to the list
        list.add('e')
        list.add('f')
          
        // Converting list to Sequence 
        val seq= list.toSeq
          
        // Displays seq
        println(seq)
      
    }
}
Output:
Buffer(e, f)

Example:2#




// Scala program to convert Java list 
// to Sequence in Scala
  
// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._
  
  
// Creating object
object GfG
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating list of characters in Java
        val list = new java.util.ArrayList[Char]()
          
        // Adding characters to the list
        list.add('d')
        list.add('f')
        list.add('e')
          
        // Converting list to Sequence 
        val seq= list.toSeq
          
        // Displays seq
        println(seq)
      
    }
}
Output:
Buffer(d, f, e)

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