Program to convert Java list of characters to Seq in Scala
A java list of characters can be converted to sequence in Scala by utilizing toSeq method of Java in Scala. Here, we need to import Scala’s JavaConversions object in order to make this conversions work else an error will occur.
Now, lets see some examples and then discuss how it works in details.
Example:1#
// Scala program to convert Java list // to Sequence in Scala // Importing Scala's JavaConversions object import scala.collection.JavaConversions. _ // Creating object object GfG { // Main method def main(args : Array[String]) { // Creating list of characters in Java val list = new java.util.ArrayList[Char]() // Adding characters to the list list.add( 'e' ) list.add( 'f' ) // Converting list to Sequence val seq = list.toSeq // Displays seq println(seq) } } |
Output:
Buffer(e, f)
Example:2#
// Scala program to convert Java list // to Sequence in Scala // Importing Scala's JavaConversions object import scala.collection.JavaConversions. _ // Creating object object GfG { // Main method def main(args : Array[String]) { // Creating list of characters in Java val list = new java.util.ArrayList[Char]() // Adding characters to the list list.add( 'd' ) list.add( 'f' ) list.add( 'e' ) // Converting list to Sequence val seq = list.toSeq // Displays seq println(seq) } } |
Output:
Buffer(d, f, e)
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