Program to convert Java list of character to Traversable in Scala
A java list of characters can be converted to a Traversable collection in Scala by utilizing toTraversable method of Java in Scala. Here, you need to import Scala’s JavaConversions object in order to make this conversions work.
Now, lets see some examples and then discuss how it works in details.
Example:1#
// Scala program to convert Java list // to a Traversable in Scala // Importing Scala's JavaConversions object import scala.collection.JavaConversions. _ // Creating object object GfG { // Main method def main(args : Array[String]) { // Creating list of character in Java val list = new java.util.ArrayList[Char]() // Adding characters to the list list.add( 'l' ) list.add( 'm' ) list.add( 'n' ) // Converting list to a Traversable val tra = list.toTraversable // Displays traversable println(tra) } } |
Output:
Buffer(l, m, n)
Here, the stated output is in same order as stated in the given list.
Example:2#
// Scala program to convert Java list // to a Traversable in Scala // Importing Scala's JavaConversions object import scala.collection.JavaConversions. _ // Creating object object GfG { // Main method def main(args : Array[String]) { // Creating list of character in Java val list = new java.util.ArrayList[Char]() // Adding characters to the list list.add( 'b' ) list.add( 'c' ) list.add( 'a' ) // Converting list to a Traversable val tra = list.toTraversable // Displays traversable println(tra) } } |
Output:
Buffer(b, c, a)
Here, all the stated characters are not stated in proper order so, the resultant output is also not in correct order.
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