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# Program to check the number is Palindrome or not

• Difficulty Level : Basic
• Last Updated : 14 Aug, 2021

Given an integer N, write a program that returns true if the given number is a palindrome, else return false.
Examples:

```Input: N = 2002
Output: true

Input: N = 1234
Output: false```

Approach:
A simple method for this problem is to first reverse digits of n, then compare the reverse of n with n. If both are same, then return true, else false.
Below is the implementation of the above approach:

## C++

 `// C program to check whether a number``// is Palindrome or not.` `#include ` `/* Iterative function to reverse digits of num*/``int` `reverseDigits(``int` `num)``{``    ``int` `rev_num = 0;``    ``while` `(num > 0) {``        ``rev_num = rev_num * 10 + num % 10;``        ``num = num / 10;``    ``}``    ``return` `rev_num;``}` `/* Function to check if n is Palindrome*/``int` `isPalindrome(``int` `n)``{` `    ``// get the reverse of n``    ``int` `rev_n = reverseDigits(n);` `    ``// Check if rev_n and n are same or not.``    ``if` `(rev_n == n)``        ``return` `1;``    ``else``        ``return` `0;``}` `/*Driver program to test reversDigits*/``int` `main()``{``    ``int` `n = 4562;``    ``printf``(``"Is %d a Palindrome number? -> %s\n"``, n,``           ``isPalindrome(n) == 1 ? ``"true"` `: ``"false"``);` `    ``n = 2002;``    ``printf``(``"Is %d a Palindrome number? -> %s\n"``, n,``           ``isPalindrome(n) == 1 ? ``"true"` `: ``"false"``);``    ``return` `0;``}`

## Java

 `// Java program to check whether a number``// is Palindrome or not.` `class` `GFG``{``    ``/* Iterative function to reverse digits of num*/``    ``static` `int` `reverseDigits(``int` `num)``    ``{``        ``int` `rev_num = ``0``;``        ``while` `(num > ``0``) {``            ``rev_num = rev_num * ``10` `+ num % ``10``;``            ``num = num / ``10``;``        ``}``        ``return` `rev_num;``    ``}``    ` `    ``/* Function to check if n is Palindrome*/``    ``static` `int` `isPalindrome(``int` `n)``    ``{``    ` `        ``// get the reverse of n``        ``int` `rev_n = reverseDigits(n);``    ` `        ``// Check if rev_n and n are same or not.``        ``if` `(rev_n == n)``            ``return` `1``;``        ``else``            ``return` `0``;``    ``}``    ` `    ``/*Driver program to test reversDigits*/``    ``public` `static` `void`  `main(String []args)``    ``{``        ``int` `n = ``4562``;``        ``System.out.println(``"Is"` `+ n + ``"a Palindrome number? -> "` `+``            ``(isPalindrome(n) == ``1` `? ``"true"` `: ``"false"``));``    ` `        ``n = ``2002``;``        ` `        ``System.out.println(``"Is"` `+ n + ``"a Palindrome number? -> "` `+``            ``(isPalindrome(n) == ``1` `? ``"true"` `: ``"false"``));` `    ``}` `}` `// This code is contributed``// by Hritik Raj ( ihritik )`

## Python3

 `# Python3 program to check whether a``# number is Palindrome or not.` `# Iterative function to reverse``# digits of num``def` `reverseDigits(num) :` `    ``rev_num ``=` `0``;``    ``while` `(num > ``0``) :``        ``rev_num ``=` `rev_num ``*` `10` `+` `num ``%` `10``        ``num ``=` `num ``/``/` `10``    ` `    ``return` `rev_num` `# Function to check if n is Palindrome``def` `isPalindrome(n) :` `    ``# get the reverse of n``    ``rev_n ``=` `reverseDigits(n);` `    ``# Check if rev_n and n are same or not.``    ``if` `(rev_n ``=``=` `n) :``        ``return` `1``    ``else` `:``        ``return` `0` `# Driver Code``if` `__name__ ``=``=` `"__main__"` `:` `    ``n ``=` `4562``    ` `    ``if` `isPalindrome(n) ``=``=` `1` `:``        ``print``(``"Is"``, n, ``"a Palindrome number? ->"``, ``True``)``        ` `    ``else` `:``        ``print``(``"Is"``, n, ``"a Palindrome number? ->"``, ``False``)` `    ``n ``=` `2002``    ` `    ``if` `isPalindrome(n) ``=``=` `1` `:``        ``print``(``"Is"``, n, ``"a Palindrome number? ->"``, ``True``)``        ` `    ``else` `:``        ``print``(``"Is"``, n, ``"a Palindrome number? ->"``, ``False``)` `# This code is contributed by Ryuga`

## C#

 `// C# program to check whether a number``// is Palindrome or not.` `using` `System;``class` `GFG``{``    ``/* Iterative function to reverse digits of num*/``    ``static` `int` `reverseDigits(``int` `num)``    ``{``        ``int` `rev_num = 0;``        ``while` `(num > 0) {``            ``rev_num = rev_num * 10 + num % 10;``            ``num = num / 10;``        ``}``        ``return` `rev_num;``    ``}``    ` `    ``/* Function to check if n is Palindrome*/``    ``static` `int` `isPalindrome(``int` `n)``    ``{``    ` `        ``// get the reverse of n``        ``int` `rev_n = reverseDigits(n);``    ` `        ``// Check if rev_n and n are same or not.``        ``if` `(rev_n == n)``            ``return` `1;``        ``else``            ``return` `0;``    ``}``    ` `    ``/*Driver program to test reversDigits*/``    ``public` `static` `void`  `Main()``    ``{``        ``int` `n = 4562;``        ``Console.WriteLine(``"Is"` `+ n + ``"a Palindrome number? -> "` `+``            ``(isPalindrome(n) == 1 ? ``"true"` `: ``"false"``));``    ` `        ``n = 2002;``        ` `        ``Console.WriteLine(``"Is"` `+ n + ``"a Palindrome number? -> "` `+``            ``(isPalindrome(n) == 1 ? ``"true"` `: ``"false"``));` `    ``}` `}` `// This code is contributed``// by Hritik Raj ( ihritik )`

## PHP

 ` 0)``    ``{``        ``\$rev_num` `= ``\$rev_num` `* 10 +``                   ``\$num` `% 10;``        ``\$num` `= ``\$num` `/ 10;``    ``}``    ``return` `\$rev_num``;``}` `// Function to check if n is Palindrome``function` `isPalindrome(``\$n``)``{` `    ``// get the reverse of n``    ``\$rev_n` `= reverseDigits(``\$n``);` `    ``// Check if rev_n and n are same or not.``    ``if` `(``\$rev_n` `== ``\$n``)``        ``return` `1;``    ``else``        ``return` `0;``}` `// Driver Code``\$n` `= 4562;``echo` `"Is "``, ``\$n` `, ``" a Palindrome number? ->"``;` `if``(isPalindrome(``\$n``) == 1)``    ``echo` `"true"` `;``else``    ``echo` `"false"``;``echo` `"\n"``;` `\$n` `= 2002;``echo` `"Is "``, ``\$n` `, ``" a Palindrome number? ->"``;``if``(isPalindrome(!``\$n``))``    ``echo` `"true"` `;``else``    ``echo` `"false"``;` `// This code is contributed by jit_t``?>`

## Javascript

 ``
Output:
```Is 4562 a Palindrome number? -> false
Is 2002 a Palindrome number? -> true```

Time Complexity: O(logN)
Auxiliary Space: O(1)

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