# Program to check if an Array is Palindrome or not using STL in C++

• Last Updated : 19 Mar, 2019

Given an array, the task is to determine whether an array is a palindrome or not, using STL in C++.

Examples:

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```Input: arr[] = {3, 6, 0, 6, 3}
Output: Palindrome

Input: arr[] = {1, 2, 3, 4, 5}
Output: Not Palindrome
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

• Get the reverse of the Array using reverse() method, provided in STL.
• Initialise flag to unset int flag = 0.
• Loop the array till size n and check if the original array and the reversed array are same. If not set flag = 1
• After the loop has ended, If flag is set the print “Not Palindrome” else print “Palindrome”

Below is the implementation of above Approach:

 `// C++ program to check if an Array``// is Palindrome or not using STL`` ` `#include ``using` `namespace` `std;`` ` `void` `palindrome(``int` `arr[], ``int` `n)``{``    ``// Initialise flag to zero.``    ``int` `flag = 0;`` ` `    ``// Create another array``    ``// to store the original array``    ``int` `arr2[n];``    ``memcpy``(arr2, arr, n * ``sizeof``(``int``));`` ` `    ``// Reverse the array``    ``reverse(arr, arr + n);`` ` `    ``// Check if the array is Palindrome``    ``for` `(``int` `i = 0; i < n; i++)``        ``if` `(arr[i] != arr2[i]) {``            ``flag = 1;``            ``break``;``        ``}`` ` `    ``// Print the result``    ``if` `(flag == 0)``        ``cout << ``"Palindrome\n"``;``    ``else``        ``cout << ``"Not Palindrome\n"``;``}`` ` `int` `main()``{``    ``// Get the array``    ``int` `arr[] = { 1, 2, 3, 2, 1 };`` ` `    ``// Compute the size``    ``int` `n = ``sizeof``(arr) / ``sizeof``(arr);`` ` `    ``palindrome(arr, n);`` ` `    ``return` `0;``}`
Output:
```Palindrome
```

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