Open In App

Program to check if a matrix is Binary matrix or not

Improve
Improve
Improve
Like Article
Like
Save Article
Save
Share
Report issue
Report

Given a matrix, the task is to check if that matrix is a Binary Matrix. A Binary Matrix is a matrix in which all the elements are either 0 or 1. It is also called Logical Matrix, Boolean Matrix, Relation Matrix.

Examples: 

Input: 
{{1, 0, 1, 1},
{0, 1, 0, 1}
{1, 1, 1, 0}}
Output: Yes

Input:
{{1, 0, 1, 1},
{1, 2, 0, 1},
{0, 0, 1, 1}}
Output: No

Approach: Traverse the matrix and check if every element is either 0 or 1. If there is any element other than 0 and 1, print No else print Yes.

Below is the implementation of above approach: 

C++




// C++ code to check if a matrix
// is binary matrix or not.
#include <bits/stdc++.h>
using namespace std;
 
#define M 3
#define N 4
 
// function to check if a matrix
// is binary matrix or not
bool isBinaryMatrix(int mat[][N])
{
    for (int i = 0; i < M; i++) {
        for (int j = 0; j < N; j++) {
            // Returns false if element is other than 0 or 1.
            if (!(mat[i][j] == 0 || mat[i][j] == 1))
                return false;
        }
    }
 
    // Returns true if all the elements
    // are either 0 or 1.
    return true;
}
 
// Driver code
int main()
{
    int mat[M][N] = { { 1, 0, 1, 1 },
                      { 0, 1, 0, 1 },
                      { 1, 1, 1, 0 } };
 
    if (isBinaryMatrix(mat))
        cout << "Yes";
    else
        cout << "No";
 
    return 0;
}


Java




// JAVA code to check if a matrix
// is binary matrix or not.
 
import java.io.*;
class GFG {
    static int M = 3;
    static int N = 4;
 
    // function to check if a matrix is binary matrix
    // or not
    static boolean isBinaryMatrix(int mat[][])
    {
        for (int i = 0; i < M; i++) {
            for (int j = 0; j < N; j++) {
                // Returns false if element is other than 0 or 1.
                if (!(mat[i][j] == 0 || mat[i][j] == 1))
                    return false;
            }
        }
 
        // Returns true if all the elements
        // are either 0 or 1.
        return true;
    }
 
    // Driver code
    public static void main(String args[])
    {
        int mat[][] = { { 1, 0, 1, 1 },
                        { 0, 1, 0, 1 },
                        { 1, 1, 1, 0 } };
 
        if (isBinaryMatrix(mat))
            System.out.println("Yes");
        else
            System.out.println("No");
    }
}


Python3




# Python3 code to check if a matrix
# is binary matrix or not.
 
M = 3;
N = 4;
 
# function to check if a matrix
# is binary matrix or not
def isBinaryMatrix(mat):
    for i in range(M):
        for j in range(N):
            # Returns false if element
            # is other than 0 or 1.
            if ((mat[i][j] == 0 or mat[i][j] == 1)==False):
                return False;
 
    # Returns true if all the
    # elements are either 0 or 1.
    return True;
 
# Driver code
if __name__=='__main__':
    mat = [[ 1, 0, 1, 1 ],[0, 1, 0, 1 ],[ 1, 1, 1, 0 ]];
 
    if (isBinaryMatrix(mat)):
        print("Yes");
    else:
        print("No");
 
# This code is contributed by mits


C#




// C# code to check if a matrix
// is binary matrix or not.
 
using System;
class GFG {
    static int M = 3;
    static int N = 4;
 
    // function to check if a matrix is binary matrix
    // or not
    static bool isBinaryMatrix(int [,]mat)
    {
        for (int i = 0; i < M; i++) {
            for (int j = 0; j < N; j++) {
                // Returns false if element is other than 0 or 1.
                if (!(mat[i,j] == 0 || mat[i,j] == 1))
                    return false;
            }
        }
 
        // Returns true if all the elements
        // are either 0 or 1.
        return true;
    }
 
    // Driver code
    public static void Main()
    {
        int [,]mat = { { 1, 0, 1, 1 },
                        { 0, 1, 0, 1 },
                        { 1, 1, 1, 0 } };
 
        if (isBinaryMatrix(mat))
            Console.WriteLine("Yes");
        else
            Console.WriteLine("No");
    }
}
// This code is contributed by anuj_67.


PHP




<?php
// PHP code to check if a matrix
// is binary matrix or not.
 
$M = 3;
$N = 4;
 
// function to check if a matrix
// is binary matrix or not
function isBinaryMatrix($mat)
{
    global $M, $N;
    for ($i = 0; $i < $M; $i++)
    {
        for ($j = 0; $j < $N; $j++)
        {
            // Returns false if element
            // is other than 0 or 1.
            if (!($mat[$i][$j] == 0 ||
                  $mat[$i][$j] == 1))
                return false;
        }
    }
 
    // Returns true if all the
    // elements are either 0 or 1.
    return true;
}
 
// Driver code
$mat = array(array( 1, 0, 1, 1 ),
             array( 0, 1, 0, 1 ),
             array( 1, 1, 1, 0 ));
 
if (isBinaryMatrix($mat))
    echo "Yes";
else
    echo "No";
 
// This code is contributed by mits
?>


Javascript




<script>
 
// JAVA SCRIPT  code to check if a matrix
// is binary matrix or not.
 
 
    let M = 3;
   let N = 4;
 
    // function to check if a matrix is binary matrix
    // or not
    function isBinaryMatrix(mat)
    {
        for (let i = 0; i < M; i++) {
            for (let j = 0; j < N; j++) {
                // Returns false if element is other than 0 or 1.
                if (!(mat[i][j] == 0 || mat[i][j] == 1))
                    return false;
            }
        }
 
        // Returns true if all the elements
        // are either 0 or 1.
        return true;
    }
 
    // Driver code
    let mat = [[ 1, 0, 1, 1 ],
                        [ 0, 1, 0, 1 ],
                        [ 1, 1, 1, 0 ]];
 
        if (isBinaryMatrix(mat))
            document.write("Yes");
        else
            document.write("No");
         
// this code is  contributed by mohan pavan pulamolu
</script>


Output

Yes

Complexity Analysis:

  • Time complexity: O( M X N) 
  • Space Complexity: O(1)


Last Updated : 01 Sep, 2022
Like Article
Save Article
Previous
Next
Share your thoughts in the comments
Similar Reads