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Program to check a number is divisible by 5 or not

Last Updated : 26 Feb, 2024
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Given number N, the task is to check whether it is divisible by 5. Print “Yes” if N is divisible by 5; otherwise, print “No“.

Examples:

Input: N = 155
Output: Yes
Explanation: If we divide 155 by 5, we get the remainder as 0, therefore 155 is divisible by 5.

Input: N = 17
Output: No
Explanation: If we divide 17 by 5, we get the remainder by 2, therefore 17 is divisible by 5.

Program to check a number is divisible by 5 or not using Divisibility of 5:

If observed carefully, all the multiples of 5 have either 0 or 5 as its last digit hence to check the divisibility, below two cases can be formed:

  • if (Last digit of N == 0 or last digit of N == 5): N is divisible by 5
  • Else N is not divisible by 5.

Note: To get the last Digit we can use the formula last Digit = N%10

Step-by-step approach:

  • Find the last digit of N by performing N % 10.
  • If the last digit is 5 or 0, then N is divisible by 5.
  • Else, N is not divisible by 5.

Below is the implementation of the above approach:

C++




#include <iostream>
using namespace std;
 
int main()
{
    int N = 17;
 
    // Extract the last digit using N % 10
    int lastDigit = N % 10;
 
    // Check for last digit
    if (lastDigit == 0 || lastDigit == 5) {
        cout << N << " is divisible by 5";
    }
    else {
        cout << N << " is not divisible by 5";
    }
}


Java




public class Main {
    public static void main(String[] args) {
        int N = 17;
 
        // Extract the last digit using N % 10
        int lastDigit = N % 10;
 
        // Check for last digit
        if (lastDigit == 0 || lastDigit == 5) {
            System.out.println(N + " is divisible by 5");
        } else {
            System.out.println(N + " is not divisible by 5");
        }
    }
}
 
// This code is contributed by shivamgupta0987654321


Python3




class GFG:
    @staticmethod
    def main():
        N = 17
 
        # Extract the last digit using N % 10
        last_digit = N % 10
 
        # Check for the last digit
        if last_digit == 0 or last_digit == 5:
            print(str(N) + " is divisible by 5")
        else:
            print(str(N) + " is not divisible by 5")
 
# Call the main method
GFG.main()


C#




using System;
 
public class GFG {
 
    static public void Main()
    {
 
        int N = 17;
 
        // Extract the last digit using N % 10
        int lastDigit = N % 10;
 
        // Check for the last digit
        if (lastDigit == 0 || lastDigit == 5) {
            Console.WriteLine(N + " is divisible by 5");
        }
        else {
            Console.WriteLine(N + " is not divisible by 5");
        }
    }
}


Javascript




let N = 17;
 
// Extract the last digit using N % 10
let lastDigit = N % 10;
 
// Check for last digit
if (lastDigit === 0 || lastDigit === 5) {
    console.log(N + " is divisible by 5");
} else {
    console.log(N + " is not divisible by 5");
}


Output

17 is not divisible by 5




Time Complexity: O(1)
Auxiliary Space: O(1)

Program to check a number is divisible by 5 or not using Modulo Operator (%):

When you divide one integer by another, the remainder can be 0 (indicating exact divisibility) or a non-zero value (indicating that there is a remainder). If the remainder is 0, it means that the dividend is divisible by the divisor.

Step-by-step approach:

  • Check If N % 5 equals 0, then N is divisible by 5.
  • Else, N is not divisible by 5.

Below is the implementation of the approach:

C++




#include <iostream>
using namespace std;
 
int main()
{
    int N = 155;
    // Divisibility Check using Modulo Operator
    if (N % 5 == 0) {
        cout << N << " is divisible by 5";
    }
    else {
        cout << N << " is not divisible by 5";
    }
}


Java




/*code by flutterfly*/
public class Main {
    public static void main(String[] args) {
        int N = 155;
         // Divisibility Check using Modulo Operator
        if (N % 5 == 0) {
            System.out.println(N + " is divisible by 5");
        } else {
            System.out.println(N + " is not divisible by 5");
        }
    }
}


Python3




# code by flutterfly
def main():
    N = 155
 
    # Divisibility Check using Modulo Operator
    if N % 5 == 0:
        print(f"{N} is divisible by 5")
    else:
        print(f"{N} is not divisible by 5")
 
# Run the main function
if __name__ == "__main__":
    main()


C#




//code by flutterfly
using System;
 
class MainClass
{
    public static void Main(string[] args)
    {
        int N = 155;
 
        // Divisibility Check using Modulo Operator
        if (N % 5 == 0)
        {
            Console.WriteLine($"{N} is divisible by 5");
        }
        else
        {
            Console.WriteLine($"{N} is not divisible by 5");
        }
    }
}


Javascript




const N = 155;
 
// Divisibility Check using Modulo Operator
if (N % 5 === 0) {
    console.log(`${N} is divisible by 5`);
} else {
    console.log(`${N} is not divisible by 5`);
}


Output

155 is divisible by 5







Time Complexity: O(1)
Auxiliary Space: O(1)



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