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Program to calculate the length of the diagonal in a rectangle

Last Updated : 18 Jan, 2024
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Write a program to calculate the length of the diagonal in a rectangle with the given length and breadth.

Examples:

Input: Length = 5, Width = 3
Output: Diagonal Length = 5.83095

Input: Length = 8, Width = 6
Output: Diagonal Length = 10

Approach: To solve the problem, follow the below idea:

The diagonal of a rectangle forms a right-angled triangle with the length and width of the rectangle. We can use the Pythagoras theorem to calculate the length of the diagonal. So, we can use this formula Diagonal2 = Length2 + Breadth2 to calculate the length of the diagonal.

Step-by-step algorithm:

  • Square the length and width.
  • Sum the squares.
  • Take the square root of the sum.

Below is the implementation of the algorithm:

C++




#include <cmath>
#include <iostream>
 
using namespace std;
 
int main()
{
    double L = 5, W = 3;
    double diagonal = sqrt(L * L + W * W);
    cout << "Diagonal Length: " << diagonal << endl;
    return 0;
}


C




#include <math.h>
#include <stdio.h>
 
int main()
{
    double L = 5, W = 3;
    double diagonal = sqrt(L * L + W * W);
    printf("Diagonal Length: %lf\n", diagonal);
    return 0;
}


Java




public class DiagonalLength {
    public static void main(String[] args)
    {
        double L = 5, W = 3;
        double diagonal
            = Math.sqrt(Math.pow(L, 2) + Math.pow(W, 2));
        System.out.println("Diagonal Length: " + diagonal);
    }
}


Python3




import math
 
L, W = 5, 3
diagonal = math.sqrt(L**2 + W**2)
print(f"Diagonal Length: {diagonal}")


C#




using System;
 
class Program {
    static void Main()
    {
        double L = 5, W = 3;
        double diagonal
            = Math.Sqrt(Math.Pow(L, 2) + Math.Pow(W, 2));
        Console.WriteLine("Diagonal Length: " + diagonal);
    }
}


Javascript




let L = 5, W = 3;
let diagonal = Math.sqrt(L ** 2 + W ** 2);
console.log("Diagonal Length: " + diagonal);


Output

Diagonal Length: 5.83095

Time Complexity: O(1)
Auxiliary Space: O(1)



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