Skip to content
Related Articles

Related Articles

Improve Article

Program to calculate Surface Area of Ellipsoid

  • Last Updated : 17 Aug, 2021

Given the length of the three semi-axes as A, B, and C, the task is to find the surface area of the given Ellipsoid.

Ellipsoid is a closed surface of which all plane cross-sections are either ellipses or circles. An ellipsoid is symmetrical about the three mutually perpendicular axes that intersect at the center. It is a three-dimensional, closed geometric shape, all planar sections of which are ellipses or circles.

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.  To complete your preparation from learning a language to DS Algo and many more,  please refer Complete Interview Preparation Course.

In case you wish to attend live classes with experts, please refer DSA Live Classes for Working Professionals and Competitive Programming Live for Students.

An ellipsoid has three independent axes, and is usually specified by the lengths a, b, c of the three semi-axes. If an ellipsoid is made by rotating an ellipse about one of its axes, then two axes of the ellipsoid are the same, and it is called an ellipsoid of revolution, or spheroid. If the lengths of all three of its axes are the same, it is a sphere.



Examples:

Input: A = 1, B = 1, C = 1
Output: 12.57

Input: A = 11, B = 12, C = 13
Output: 1807.89

Approach: The given problem can be solved by using the formula for Surface Area of the Ellipsoid as:

Below is the implementation of the above approach:

C++




// C++ program for the above approach
 
#include <iomanip>
#include <iostream>
#include <math.h>
using namespace std;
 
// Function to find the surface area of
// the given Ellipsoid
void findArea(double a, double b, double c)
{
 
    // Formula to find surface area
    // of an Ellipsoid
    double area = 4 * 3.141592653
                  * pow((pow(a * b, 1.6) + pow(a * c, 1.6)
                         + pow(b * c, 1.6))
                            / 3,
                        1 / 1.6);
 
    // Print the area
    cout << fixed << setprecision(2)
         << area;
}
 
// Driver Code
int main()
{
    double A = 11, B = 12, C = 13;
    findArea(A, B, C);
 
    return 0;
}

Java




// Java program of the above approach
import java.util.*;
 
class GFG{
 
// Function to find the surface area of
// the given Ellipsoid
static void findArea(double a, double b, double c)
{
     
    // Formula to find surface area
    // of an Ellipsoid
    double area = 4 * 3.141592653 * Math.pow((Math.pow(a * b, 1.6) +
                       Math.pow(a * c, 1.6) + Math.pow(b * c, 1.6)) /
                             3, 1 / 1.6);
 
    // Print the area
    System.out.print(String.format("%.2f", area));
}
 
// Driver Code
public static void main(String[] args)
{
    double A = 11, B = 12, C = 13;
     
    findArea(A, B, C);
}
}
 
// This code is contributed by code_hunt

Python3




# Python3 program for the above approach
from math import pow
 
# Function to find the surface area of
# the given Ellipsoid
def findArea(a, b, c):
     
    # Formula to find surface area
    # of an Ellipsoid
    area = (4 * 3.141592653 * pow((pow(a * b, 1.6) +
            pow(a * c, 1.6) + pow(b * c, 1.6)) / 3, 1 / 1.6))
 
    # Print the area
    print("{:.2f}".format(round(area, 2)))
 
# Driver Code
if __name__ == '__main__':
     
    A = 11
    B = 12
    C = 13
     
    findArea(A, B, C)
     
# This code is contributed by SURENDRA_GANGWAR

C#




// C# program of the above approach
using System;
 
class GFG{
 
// Function to find the surface area of
// the given Ellipsoid
static void findArea(double a, double b, double c)
{
     
    // Formula to find surface area
    // of an Ellipsoid
    double area = 4 * 3.141592653 * Math.Pow((Math.Pow(a * b, 1.6) +
                       Math.Pow(a * c, 1.6) + Math.Pow(b * c, 1.6)) /
                             3, 1 / 1.6);
 
    // Print the area
    Console.Write(Math.Round(area, 2));
}
 
// Driver Code
public static void Main(String[] args)
{
    double A = 11, B = 12, C = 13;
     
    findArea(A, B, C);
}
}
 
// This code is contributed by shivanisinghss2110

Javascript




<script>
        // JavaScript Program to implement
        // the above approach
 
        // Function to find the surface area of
        // the given Ellipsoid
        function findArea(a, b, c) {
 
            // Formula to find surface area
            // of an Ellipsoid
            let area = 4 * 3.141592653
                * Math.pow((Math.pow(a * b, 1.6) + Math.pow(a * c, 1.6)
                    + Math.pow(b * c, 1.6))
                    / 3,
                    1 / 1.6);
 
            // Print the area
            document.write(area.toPrecision(6));
        }
 
        // Driver Code
        let A = 11, B = 12, C = 13;
        findArea(A, B, C);
 
// This code is contributed by Potta Lokesh
    </script>
Output: 
1807.89

 

Time Complexity: O(1)
Auxiliary Space: O(1)




My Personal Notes arrow_drop_up
Recommended Articles
Page :