# Program to calculate Root Mean Square

Last Updated : 18 Sep, 2022

Given an array of N numbers. The task is to calculate the Root Mean Square(RMS) of the given numbers.
Examples

Input: arr[] = {1, 2, 3, 4, 5}
Output: 3.31662

Input: arr[] = {10, 4, 6, 8}
Output: 7.34847

Approach: The Root Mean Square value of N numbers x1,x2,x3,…..xn can be given as,

RMS method first calculates the square of each number and then calculate the mean and finally calculate the square root of the mean.
Below is the program to find RMS of N numbers:

## C++

 // CPP program to calculate Root Mean Square #include using namespace std;   // Function that Calculate Root Mean Square float rmsValue(int arr[], int n) {     int square = 0;     float mean = 0.0, root = 0.0;       // Calculate square.     for (int i = 0; i < n; i++) {         square += pow(arr[i], 2);     }       // Calculate Mean.     mean = (square / (float)(n));       // Calculate Root.     root = sqrt(mean);       return root; }   // Driver code int main() {     int arr[] = { 10, 4, 6, 8 };     int n = sizeof(arr) / sizeof(arr[0]);       cout << rmsValue(arr, n);       return 0; }

## Java

 // Java program to calculate // Root Mean Square   class GFG {   // Function that Calculate Root // Mean Square static float rmsValue(int arr[], int n) {     int square = 0;     float mean = 0;     float root = 0;       // Calculate square.     for(int i = 0; i < n; i++)     {         square += Math.pow(arr[i], 2);     }           // Calculate Mean.     mean = (square / (float) (n));       // Calculate Root.     root = (float)Math.sqrt(mean);       return root; }     // Driver Code public static void main(String args[]) {     int arr[] = { 10, 4, 6, 8};           int n = arr.length;           System.out.println(rmsValue(arr, n)); } }   // This code is contributed by ANKITRAI1

## Python3

 #Python3 program to calculate Root Mean Square   import math #Function that Calculate Root Mean Square def rmsValue(arr, n):     square = 0     mean = 0.0     root = 0.0           #Calculate square     for i in range(0,n):         square += (arr[i]**2)           #Calculate Mean     mean = (square / (float)(n))           #Calculate Root     root = math.sqrt(mean)           return root   #Driver code if __name__=='__main__':     arr = [10, 4, 6, 8]     n = len(arr)     print(rmsValue(arr, n))   #This code is contributed by Shashank_Sharma

## C#

 // C# program to calculate // Root Mean Square using System; class GFG {   // Function that Calculate // Root Mean Square static float rmsValue(int[] arr, int n) {     int square = 0;     float mean = 0;     float root = 0;       // Calculate square.     for(int i = 0; i < n; i++)     {         square += (int)Math.Pow(arr[i], 2);     }           // Calculate Mean.     mean = (square / (float) (n));       // Calculate Root.     root = (float)Math.Sqrt(mean);       return root; }   // Driver Code public static void Main() {     int[] arr = {10, 4, 6, 8};           int n = arr.Length;           Console.Write(rmsValue(arr, n)); } }   // This code is contributed // by ChitraNayal



## Javascript



Output:

7.34847

Time Complexity: O(n) where n is size of given array, because for loop would run for all elements of array
Auxiliary Space: O(1)