Program to calculate Kinetic Energy and Potential Energy

• Difficulty Level : Basic
• Last Updated : 12 Jul, 2021

Given three float values M, H, and V representing the mass, velocity, and height of an object respectively the task is to calculate its Kinetic Energy as well as its Potential Energy
Note: The value of acceleration due to gravity (g) is 9.8 and ignore units.

Examples:

Input: M = 25, H = 10, V = 15
Output:
Kinetic Energy = 2812.5
Potential Energy = 2450
Explanation : The kinetic energy of the particle is 2812.5 and the potential energy is 2450.

Input : M=5.5, H=23.5, V= 10.5
Output :
303.188
1266.65

Approach: The required values of Kinetic Energy and Potential Energy can be calculated using the following two formulas:

Kinetic Energy = 0.5 * Mass ( M ) * Velocity ( V ) 2

Potential Energy = Mass ( M ) * Height ( H ) * Acceleration due to gravity ( g )

Below is the implementation of the above approach:

C++14

 // C++ Program to implement// the above approach #include using namespace std; // Function to calculate Kinetic Energyfloat kineticEnergy(float M, float V){    // Stores the Kinetic Energy    float KineticEnergy;     KineticEnergy = 0.5 * M * V * V;     return KineticEnergy;} // Function to calculate Potential Energyfloat potentialEnergy(float M, float H){    // Stores the Potential Energy    float PotentialEnergy;     PotentialEnergy = M * 9.8 * H;     return PotentialEnergy;} // Driver Codeint main(){    float M = 5.5, H = 23.5, V = 10.5;     cout << "Kinetic Energy = "         << kineticEnergy(M, V) << endl;    cout << "Potential Energy = "         << potentialEnergy(M, H) << endl;    return 0;}

Java

 // Java program to implement// the above approachclass GFG{  // Function to calculate Kinetic Energystatic double kineticEnergy(double M, double V){         // Stores the Kinetic Energy    double KineticEnergy;     KineticEnergy = 0.5 * M * V * V;     return KineticEnergy;} // Function to calculate Potential Energystatic double potentialEnergy(double M, double H){         // Stores the Potential Energy    double PotentialEnergy;     PotentialEnergy = M * 9.8 * H;     return PotentialEnergy;} // Driver Codepublic static void main(String []args){    double M = 5.5, H = 23.5, V = 10.5;     System.out.println("Kinetic Energy = " +                       kineticEnergy(M, V));    System.out.println("Potential Energy = " +                       potentialEnergy(M, H));}} // This code is contributed by AnkThon

Python3

 # Python3 program to implement# the above approach # Function to calculate Kinetic Energydef kineticEnergy(M, V):     # Stores the Kinetic Energy    KineticEnergy = 0.5 * M * V * V     return KineticEnergy # Function to calculate Potential Energydef potentialEnergy(M, H):     # Stores the Potential Energy    PotentialEnergy = M * 9.8 * H     return PotentialEnergy # Driver Codeif __name__ ==  "__main__":     M = 5.5    H = 23.5    V = 10.5     print("Kinetic Energy = ", kineticEnergy(M, V))    print("Potential Energy = ", potentialEnergy(M, H))     # This code is contributed by AnkThon

C#

 // C# program to implement// the above approachusing System;using System.Collections.Generic; class GFG{  /// Function to calculate Kinetic Energystatic double kineticEnergy(double M, double V){         // Stores the Kinetic Energy    double KineticEnergy;     KineticEnergy = 0.5 * M * V * V;     return KineticEnergy;} // Function to calculate Potential Energystatic double potentialEnergy(double M, double H){         // Stores the Potential Energy    double PotentialEnergy;     PotentialEnergy = M * 9.8 * H;     return PotentialEnergy;} // Driver Codepublic static void Main(){    double M = 5.5, H = 23.5, V = 10.5;     Console.WriteLine("Kinetic Energy = " +                      kineticEnergy(M, V));    Console.Write("Potential Energy = " +                  potentialEnergy(M, H));}} // This code is contributed by bgangwar59

Javascript


Output:
Kinetic Energy = 303.188
Potential Energy = 1266.65

Time Complexity: O(1)
Auxiliary Space: O(1)

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