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Program to calculate area of a rhombus whose one side and diagonal are given

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Given the length of diagonal ‘d1’ of a rhombus and a side ‘a’, the task is to find the area of that rhombus.
 

A rhombus is a polygon having 4 equal sides in which both the opposite sides are parallel, and opposite angles are equal.

 

Examples: 
 

Input: d = 15, a = 10
Output: 99.21567416492215

Input: d = 20, a = 18
Output: 299.3325909419153

 

Approach:
 

  • Get the diagonal ‘d1’ and side ‘a’ of the rhombus
  • We know that, 
     

  •  
  • But since we don’t know the other diagonal d2, we cannot use this formula yet
  • So we first find the second diagonal d2 with the help of d1 and a
     

  •  
  • Now we can use the area formula to compute the area of the Rhombus

 

C++




// C++ program to calculate the area of a rhombus
// whose one side and one diagonal is given
#include<bits/stdc++.h>
using namespace std;
 
// function to calculate the area of the rhombus
double area(double d1, double a)
{
     
    // Second diagonal
    double d2 = sqrt(4 * (a * a) - d1 * d1);
 
    // area of rhombus
    double area = 0.5 * d1 * d2;
 
    // return the area
    return area;
}
 
// Driver code
int main()
{
    double d = 7.07;
    double a = 5;
    printf("%0.8f", area(d, a));
}
 
// This code is contributed by Mohit Kumar


Java




// Java program to calculate the area of a rhombus
// whose one side and one diagonal is given
class GFG
{
 
    // function to calculate the area of the rhombus
    static double area(double d1, double a)
    {
         
        // Second diagonal
        double d2 = Math.sqrt(4 * (a * a) - d1 * d1);
     
        // area of rhombus
        double area = 0.5 * d1 * d2;
     
        // return the area
        return area;
    }
     
    // Driver code
    public static void main (String[] args)
    {
        double d = 7.07;
        double a = 5;
        System.out.println(area(d, a));
    }
}
 
// This code is contributed by AnkitRai01


Python3




# Python program to calculate
# the area of a rhombus
# whose one side and
# one diagonal is given
 
# function to calculate
# the area of the rhombus
def area(d1, a):
     
    # Second diagonal
    d2 = (4*(a**2) - d1**2)**0.5
     
    # area of rhombus
    area = 0.5 * d1 * d2
     
    # return the area
    return(area)
 
# driver code
d = 7.07
a = 5
print(area(d, a))


C#




// C# program to calculate the area of a rhombus
// whose one side and one diagonal is given
using System;
 
class GFG
{
 
    // function to calculate the area of the rhombus
    static double area(double d1, double a)
    {
         
        // Second diagonal
        double d2 = Math.Sqrt(4 * (a * a) - d1 * d1);
     
        // area of rhombus
        double area = 0.5 * d1 * d2;
     
        // return the area
        return area;
    }
     
    // Driver code
    public static void Main (String []args)
    {
        double d = 7.07;
        double a = 5;
        Console.WriteLine(area(d, a));
    }
}
 
// This code is contributed by Arnab Kundu


Javascript




<script>
// javascript program to calculate the area of a rhombus
// whose one side and one diagonal is given  
// function to calculate the area of the rhombus
function area(d1 , a)
{
     
    // Second diagonal
    var d2 = Math.sqrt(4 * (a * a) - d1 * d1);
 
    // area of rhombus
    var area = 0.5 * d1 * d2;
 
    // return the area
    return area;
}
 
// Driver code
var d = 7.07;
var a = 5;
document.write(area(d, a));
 
// This code is contributed by 29AjayKumar
</script>


Output: 

24.999998859949972

 

Time Complexity: O(log(n)) as inbuilt sqrt function is used

Auxiliary Space: O(1)



Last Updated : 07 Aug, 2022
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