How will you print numbers from 1 to 100 without using loop? | Set-2

If we take a look at this problem carefully, we can see that the idea of “loop” is to track some counter value e.g. “i=0” till “i <= 100". So if we aren't allowed to use loop, how else can be track something in C language!

It can be done in many ways to print numbers using any looping conditions such as for(), while(), do-while(). But the same can be done without using loops (using recursive functions, goto statement).

Printing numbers from 1 to 100 using recursive functions has already been discussed in Set-1 . In this post, other two methods have been discussed:

1. Using goto statement:
   

   C++

   filter_none

   edit
   close

   play_arrow

   link
   brightness_4
   code

   #include <iostream> using namespace std;    int main() {     int i = 0;        begin:     i = i + 1;     cout << i << " ";        if (i < 100)     {         goto begin;     }     return 0; }    // This code is contributed by ShubhamCoder

   chevron_right

   filter_none

   C

   filter_none

   edit
   close

   play_arrow

   link
   brightness_4
   code

   #include <stdio.h>    int main() {     int i = 0; begin:     i = i + 1;     printf("%d ", i);        if (i < 100)         goto begin;     return 0; }

   chevron_right

   filter_none

   C#

   filter_none

   edit
   close

   play_arrow

   link
   brightness_4
   code

   using System;    class GFG{    static public void Main () {     int i = 0;     begin:         i = i + 1;         Console.Write(" " + i + " ");            if (i < 100)         {             goto begin;         } } }    // This code is contributed by ShubhamCoder

   chevron_right

   filter_none

   Output:

   1 2 3 4 . . . 97 98 99 100
   

2. Using recursive main function:
   

   C++

   filter_none

   edit
   close

   play_arrow

   link
   brightness_4
   code

   #include <iostream> using namespace std;    int main() {     static int i = 1;            if (i <= 100)     {         cout << i++ << " ";         main();     }     return 0; }    // This code is contributed by ShubhamCoder

   chevron_right

   filter_none

   C

   filter_none

   edit
   close

   play_arrow

   link
   brightness_4
   code

   #include <stdio.h>    int main() {     static int i = 1;     if (i <= 100) {         printf("%d ", i++);         main();     }     return 0; }

   chevron_right

   filter_none

   Java

   filter_none

   edit
   close

   play_arrow

   link
   brightness_4
   code

   // Java program to count all pairs from both the // linked lists whose product is equal to // a given value class GFG  {     static int i = 1;        public static void main(String[] args)      {            if (i <= 100)         {             System.out.printf("%d ", i++);             main(null);         }     } }    // This code is contributed by Rajput-Ji

   chevron_right

   filter_none

   C#

   filter_none

   edit
   close

   play_arrow

   link
   brightness_4
   code

   // C# program to count all pairs from both the // linked lists whose product is equal to // a given value using System;    class GFG  {     static int i = 1;        public static void Main(String[] args)      {         if (i <= 100)         {             Console.Write("{0} ", i++);             Main(null);         }     } }    // This code is contributed by Rajput-Ji

   chevron_right

   filter_none

   Output:

   1 2 3 4 . . . 97 98 99 100
   

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.

Pushpanjali chauhan

Check out this Author's contributed articles.