How will you print numbers from 1 to 100 without using loop? | Set-2

If we take a look at this problem carefully, we can see that the idea of “loop” is to track some counter value e.g. “i=0” till “i <= 100". So if we aren't allowed to use loop, how else can be track something in C language!

It can be done in many ways to print numbers using any looping conditions such as for(), while(), do while(). But the same can be done without using loops (using recursive functions, goto statement).

Printing numbers from 1 to 100 using recursive functions has already been discussed in Set-1 . In this post, other two methods have been discussed:

1. Using goto statement:
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   #include <stdio.h>    int main() {     int i = 0; begin:     i = i + 1;     printf("%d ", i);        if (i < 100)         goto begin;     return 0; }

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   Output:

   
   

   
   

   1 2 3 4 . . . 97 98 99 100
   

2. Using recursive main function:
   

   C

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   #include <stdio.h>    int main() {     static int i = 1;     if (i <= 100) {         printf("%d ", i++);         main();     }     return 0; }

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   Java

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   // Java program to count all pairs from both the // linked lists whose product is equal to // a given value class GFG  {     static int i = 1;        public static void main(String[] args)      {            if (i <= 100)         {             System.out.printf("%d ", i++);             main(null);         }     } }    // This code is contributed by Rajput-Ji

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   C#

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   // C# program to count all pairs from both the // linked lists whose product is equal to // a given value using System;    class GFG  {     static int i = 1;        public static void Main(String[] args)      {         if (i <= 100)         {             Console.Write("{0} ", i++);             Main(null);         }     } }    // This code is contributed by Rajput-Ji

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   Output:

   1 2 3 4 . . . 97 98 99 100
   

Pushpanjali chauhan

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