# Program to print reverse character bridge pattern

For a given value N, denoting the number of Charters starting from the A, print reverse character bridge pattern.

Examples :

```Input : n = 5
Output :

ABCDEDCBA
ABCD DCBA
ABC   CBA
AB     BA
A       A

Input : n = 8
Output :

ABCDEFGHGFEDCBA
ABCDEFG GFEDCBA
ABCDEF   FEDCBA
ABCDE     EDCBA
ABCD       DCBA
ABC         CBA
AB           BA
A             A
```

## Recommended: Please solve it on PRACTICE first, before moving on to the solution.

• For a given value N, reflect the number of characters taking part in the pattern, starting from A. For N = 5, Participating character would be A B C D E.
• By using a nested for loop we would compute the logic. Where the outer loop of ‘i’ would range from 0 to N and the inner loop of ‘j’ would range from 65(Start) to 64 + 2*N.
• Under which we would check the required condition for the pattern design. For all the values of j which are less than ((64+n)+ i) it would print the (char)((64 + n)-( j % (64+n))) and for all the values of j <= ((64+n) -i) it would print (char)j.

## C++

 `// CPP program to print reverse character bridge pattern ` `#include ` `using` `namespace` `std; ` ` `  `// Function to print pattern ` `void` `ReverseCharBridge(``int` `n) ` `{ ` `    ``for` `(``int` `i = 0; i < n; i++)  ` `    ``{ ` `        ``for` `(``int` `j = ``'A'``; j < ``'A'` `+ (2 * n) - 1; j++)  ` `        ``{ ` `            ``if` `(j >= (``'A'` `+ n - 1) + i) ` `                ``cout << (``char``)((``'A'` `+ n - 1) -  ` `                               ``(j % (``'A'` `+ n - 1))); ` `            ``else` `if` `(j <= (``'A'` `+ n - 1) - i) ` `                ``cout << (``char``)j; ` `            ``else` `                ``cout << ``" "``; ` `        ``} ` `        ``cout << endl; ` `    ``} ` `} ` ` `  `// Driver Code ` `int` `main() ` `{ ` `    ``int` `n = 6; ` `    ``ReverseCharBridge(n); ` `    ``return` `0; ` `} `

## Java

 `// Java program to print reverse ` `// character bridge pattern ` `import` `java.io.*; ` ` `  `class` `GFG { ` `     `  `    ``// Function to print pattern ` `    ``static` `void` `ReverseCharBridge(``int` `n) ` `    ``{ ` `        ``for` `(``int` `i = ``0``; i < n; i++)  ` `        ``{ ` `            ``for` `(``int` `j = ``'A'``; j < ``'A'` `+ (``2` `* n) - ``1``; j++)  ` `            ``{ ` `              ``if` `(j >= (``'A'` `+ n - ``1``) + i) ` `                ``System.out.print((``char``)((``'A'` `+ n - ``1``) -  ` `                                 ``(j % (``'A'` `+ n - ``1``)))); ` `                ``else` `if` `(j <= (``'A'` `+ n - ``1``) - i) ` `                    ``System.out.print((``char``)j); ` `                ``else` `                    ``System.out.print(``" "``); ` `            ``} ` `            ``System.out.println(); ` `        ``} ` `    ``} ` `     `  `    ``// Driver Code ` `    ``public` `static` `void` `main(String args[]) ` `    ``{ ` `        ``int` `n = ``6``; ` `        ``ReverseCharBridge(n); ` `    ``} ` `} ` ` `  `/*This code is contributed by Nikita Tiwari.*/`

## Python3

 `# Python3 code to print reverse  ` `# character bridge pattern ` ` `  `# Function to print pattern ` `def` `ReverseCharBridge( n ): ` `    ``for` `i ``in` `range``( n ): ` `        ``for` `j ``in` `range``( ``ord``(``'A'``), ``ord``(``'A'``) ``+`  `                              ``(``2` `*` `n) ``-` `1``): ` `            ``if` `j >``=` `(``ord``( ``'A'` `) ``+` `n ``-` `1``) ``+` `i: ` `                ``print``(``chr``((``ord``(``'A'``) ``+` `n ``-` `1``) ``-`  `                  ``(j ``%` `(``ord``(``'A'``) ``+` `n ``-` `1``))), end ``=` `'') ` `             `  `            ``elif` `j <``=` `(``ord``(``'A'``) ``+` `n ``-` `1``) ``-` `i: ` `                ``print``(``chr``(j), end ``=` `'') ` `            ``else``: ` `                ``print``(end ``=` `" "``) ` `        ``print``(``"\n"``, end ``=` `'') ` `         `  `# Driver Code ` `n ``=` `6` `ReverseCharBridge(n) ` ` `  `# This code is contributed by "Sharad_Bhardwaj". `

## C#

 `// C# program to print reverse ` `// character bridge pattern ` `using` `System; ` ` `  `class` `GFG { ` ` `  `    ``// Function to print pattern ` `    ``static` `void` `ReverseCharBridge(``int` `n) ` `    ``{ ` `        ``for` `(``int` `i = 0; i < n; i++)  ` `        ``{ ` `            ``for` `(``int` `j = ``'A'``; j < ``'A'` `+ (2 * n) - 1; j++) ` `            ``{ ` `                ``if` `(j >= (``'A'` `+ n - 1) + i) ` `                    ``Console.Write((``char``)((``'A'` `+ n - 1) ` `                    ``- (j % (``'A'` `+ n - 1)))); ` `                 `  `                ``else` `if` `(j <= (``'A'` `+ n - 1) - i) ` `                    ``Console.Write((``char``)j); ` `                 `  `                ``else` `                    ``Console.Write(``" "``); ` `            ``} ` `            ``Console.WriteLine(); ` `        ``} ` `    ``} ` ` `  `    ``// Driver Code ` `    ``public` `static` `void` `Main() ` `    ``{ ` `        ``int` `n = 6; ` `        ``ReverseCharBridge(n); ` `    ``} ` `} ` ` `  `// This code is contributed by vt_m. `

## PHP

 `= (65 + ``\$n` `- 1) + ``\$i``) ` `                ``echo` `chr``((65 + ``\$n` `- 1) -  ` `                    ``(``\$j` `% (65 + ``\$n` `- 1))); ` `                     `  `            ``else` `if` `(``\$j` `<= (65 + ``\$n` `- 1) - ``\$i``) ` `                ``echo` `chr``(``\$j``); ` `            ``else` `                ``echo` `" "``; ` `        ``} ` `        ``echo` `"\n"``; ` `    ``} ` `} ` ` `  `// Driver Code ` `\$n` `= 6; ` `ReverseCharBridge(``\$n``); ` ` `  `// This code is contributed by mits  ` `?> `

Output :

```ABCDEFEDCBA
ABCDE EDCBA
ABCD   DCBA
ABC     CBA
AB       BA
A         A```

My Personal Notes arrow_drop_up Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.

Improved By : Mithun Kumar