# Program to Print Matrix in Z form

Given a square matrix of order n*n, we need to print elements of the matrix in Z form

```Examples:
Input : mat[][] =  {1, 2, 3,
4, 5, 6,
7, 8, 9}
Output : 1 2 3 5 7 8 9

Input : mat[][] = {5, 19, 8, 7,
4, 1, 14, 8,
2, 20, 1, 9,
1, 2, 55, 4}
Output: 5 19 8 7 14 20 1 2 55 4
``` Complexity O(n)

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

We need to traverse first row of matrix then second diagonal and then last row.

## CPP

 `// CPP program to print a square matrix in Z form ` `#include ` `using` `namespace` `std; ` `const` `int` `MAX = 100; ` ` `  `// Function to print a square matrix in Z form ` `void` `printZform(``int` `mat[][MAX], ``int` `n) ` `{ ` `    ``// print first row ` `    ``for` `(``int` `i = 0; i < n; i++) ` `        ``cout << mat[i] << ``" "``; ` ` `  `    ``// Print diagonal ` `    ``int` `i = 1, j = n - 2; ` `    ``while` `(i < n && j >= 0) ``// print diagonal ` `    ``{ ` `        ``cout << mat[i][j] << ``" "``; ` `        ``i++; ` `        ``j--; ` `    ``} ` ` `  `    ``// Print last row ` `    ``for` `(``int` `i = 1; i < n; i++) ` `        ``cout << mat[n - 1][i] << ``" "``; ` `} ` ` `  `// Driver function ` `int` `main() ` `{ ` `    ``int` `mat[][MAX] = { { 4, 5, 6, 8 }, ` `                       ``{ 1, 2, 3, 1 }, ` `                       ``{ 7, 8, 9, 4 }, ` `                       ``{ 1, 8, 7, 5 } }; ` `    ``printZform(mat, 4); ` `    ``return` `0; ` `} `

## Java

 `// Java program to print a ` `// square matrix in Z form ` ` `  `import` `java.lang.*; ` `import` `java.io.*; ` ` `  `class` `GFG { ` `    ``public` `static` `void` `diag(``int` `arr[][], ``int` `n) ` `    ``{ ` `        ``int` `i = ``0``, j, k; ` ` `  `        ``// print first row ` `        ``for` `(j = ``0``; j < n - ``1``; j++) { ` `            ``System.out.print(arr[i][j] + ``" "``); ` `        ``} ` ` `  `        ``// Print diagonal ` `        ``k = ``1``; ` `        ``for` `(i = ``0``; i < n - ``1``; i++) { ` `            ``for` `(j = ``0``; j < n; j++) { ` `                ``if` `(j == n - k) { ` `                    ``System.out.print(arr[i][j] + ``" "``); ` `                    ``break``; ` `                ``} ` `            ``} ` `            ``k++; ` `        ``} ` `        ``// Print last row ` `        ``i = n - ``1``; ` `        ``for` `(j = ``0``; j < n; j++) ` `            ``System.out.print(arr[i][j] + ``" "``); ` ` `  `        ``System.out.print(``"\n"``); ` `    ``} ` ` `  `    ``public` `static` `void` `main(String[] args) ` `    ``{ ` `        ``int` `a[][] = { { ``4``, ``5``, ``6``, ``8` `}, ` `                      ``{ ``1``, ``2``, ``3``, ``1` `}, ` `                      ``{ ``7``, ``8``, ``9``, ``4` `}, ` `                      ``{ ``1``, ``8``, ``7``, ``5` `} }; ` ` `  `        ``diag(a, ``4``); ` `    ``} ` `} ` ` `  `// Code contributed by Mohit Gupta_OMG <(0_o)> `

## Python3

 `# Python program to print a  ` `# square matrix in Z form ` ` `  `arr ``=` `[[``4``, ``5``, ``6``, ``8``],  ` `        ``[``1``, ``2``, ``3``, ``1``],  ` `        ``[``7``, ``8``, ``9``, ``4``],  ` `        ``[``1``, ``8``, ``7``, ``5``]] ` ` `  `n ``=` `len``(arr[``0``]) ` `                  `  `i ``=` `0` `for` `j ``in` `range``(``0``, n``-``1``): ` `    ``print``(arr[i][j], end ``=` `' '``)  ` `         `  `k ``=` `1` `for` `i ``in` `range``(``0``, n): ` `    ``for` `j ``in` `range``(n, ``0``, ``-``1``): ` `        ``if``(j ``=``=` `n``-``k): ` `            ``print``(arr[i][j], end ``=` `' '``)  ` `            ``break``;  ` `    ``k``+``=` `1` ` `  `# Print last row ` `i ``=` `n``-``1``;  ` `for` `j ``in` `range``(``0``, n): ` `    ``print``(arr[i][j], end ``=` `' '``) ` ` `  `# Code contributed by Mohit Gupta_OMG <(0_o)> `

## C#

 `// C# program to print a square  ` `// matrix in Z form ` `using` `System; ` ` `  `class` `GFG { ` `     `  `    ``public` `static` `void` `printZform(``int``[, ] mat, ``int` `n) ` `    ``{ ` ` `  `        ``int` `i, j; ` `         `  `        ``// print first row ` `        ``for` `(i = 0; i < n; i++) { ` `            ``Console.Write(mat[0, i] + ``" "``); ` `        ``} ` ` `  `        ``// Print diagonal ` `        ``i = 1; ` `        ``j = n - 2; ` `     `  `        ``while` `(i < n && j >= 0) ``// print diagonal ` `        ``{ ` `            ``Console.Write(mat[i,j] + ``" "``); ` `            ``i++; ` `            ``j--; ` `        ``} ` `     `  `        ``// Print last row ` `        ``for` `(i = 1; i < n; i++) ` `            ``Console.Write(mat[n - 1,i] + ``" "``); ` `    ``} ` ` `  `    ``// Driver code ` `    ``public` `static` `void` `Main() ` `    ``{ ` `        ``int``[, ] mat = { { 4, 5, 6, 8 }, ` `                    ``{ 1, 2, 3, 1 }, ` `                    ``{ 7, 8, 9, 4 }, ` `                    ``{ 1, 8, 7, 5 } }; ` ` `  `        ``printZform(mat, 4); ` `    ``} ` `} ` ` `  `// This code is contributed by vt_m. `

## PHP

 `= 0)  ` `    ``{ ` `        ``echo` `\$mat``[``\$i``][``\$j``] , ``" "``; ` `        ``\$i``++; ` `        ``\$j``--; ` `    ``} ` ` `  `    ``// Print last row ` `    ``for` `( ``\$i` `= 1; ``\$i` `< ``\$n``; ``\$i``++) ` `        ``echo` `\$mat``[``\$n` `- 1][``\$i``] , ``" "``; ` `} ` `     `  `    ``// Driver Code ` `    ``\$mat` `= ``array``(``array``(4, 5, 6, 8), ` `                 ``array``(1, 2, 3, 1), ` `                 ``array``(7, 8, 9, 4), ` `                 ``array``(1, 8, 7, 5)); ` `    ``printZform(``\$mat``, 4); ` `     `  `// This code is contributed by anuj_67. ` `?> `

Output:

```4 5 6 8 3 8 1 8 7 5
```

Alternate Simpler Implementation:
Thanks to Aathishithan for suggesting this.

 `// Java program to print a  ` `// square matrix in Z form  ` `  `  `import` `java.lang.*;  ` `import` `java.io.*;  ` `  `  `class` `GFG {  ` `    ``public` `static` `void` `diag(``int` `arr[][], ``int` `n)  ` `    ``{  ` `        ``int` `i = ``0``, j, k;  ` `        ``for``(i = ``0``;i < n;i++){ ` `           ``for``(j = ``0``;j < n;j++){ ` `              ``if``(i == ``0``){ ` `                ``System.out.print(arr[i][j]+``" "``); ` `              ``} ``else` `if``(i == j){ ` `                   ``System.out.print(arr[i][j]+``" "``); ` `              ``} ``else` `if``(i == n-``1``){ ` `                   ``System.out.print(arr[i][j]+``" "``); ` `              ``} ` `           ``} ` `        ``} ` `          `  `    ``}  ` `  `  `    ``public` `static` `void` `main(String[] args)  ` `    ``{  ` `        ``int` `a[][] = { { ``4``, ``5``, ``6``, ``8` `},  ` `                    ``{ ``1``, ``2``, ``3``, ``1` `},  ` `                    ``{ ``7``, ``8``, ``9``, ``4` `},  ` `                    ``{ ``1``, ``8``, ``7``, ``5` `} };  ` `  `  `        ``diag(a, ``4``);  ` `    ``}  ` `}  `

Output:

```4 5 6 8 2 9 1 8 7 5
```

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Improved By : vt_m, Aathishithan

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