Given first term (a), common difference (d) and a integer n of the Arithmetic Progression series, the task is to print the series.
Examples :
Input : a = 5, d = 2, n = 10
Output : 5 7 9 11 13 15 17 19 21 23
Approach :
We know the Arithmetic Progression series is like = 2, 5, 8, 11, 14 …. …
In this series 2 is the starting term of the series .
Common difference = 5 – 2 = 3 (Difference common in the series).
so we can write the series as :
t1 = a1
t2 = a1 + (2-1) * d
t3 = a1 + (3-1) * d
.
.
.
tn = a1 + (n-1) * d
CPP
// CPP Program to print an arithmetic // progression series #include <bits/stdc++.h> using namespace std;
void printAP( int a, int d, int n)
{ // Printing AP by simply adding d // to previous term. int curr_term;
curr_term=a; for ( int i = 1; i <= n; i++)
{ cout << curr_term << " " ;
curr_term =curr_term + d;
} } // Driver code int main()
{ // starting number
int a = 2;
// Common difference
int d = 1;
// N th term to be find
int n = 5;
printAP(a, d, n);
return 0;
} |
Java
// Java Program to print an arithmetic // progression series class GFG
{ static void printAP( int a, int d, int n)
{ // Printing AP by simply adding d
// to previous term.
int curr_term;
curr_term=a; for ( int i = 1 ; i <= n; i++)
{ System.out.print(curr_term + " " );
curr_term =curr_term + d;
}
} // Driver code public static void main(String[] args)
{ // starting number int a = 2 ;
// Common difference int d = 1 ;
// N th term to be find int n = 5 ;
printAP(a, d, n); } } // This code is contributed by Anant Agarwal. |
Python3
# Python 3 Program to # print an arithmetic # progression series def printAP(a, d, n):
# Printing AP by simply adding d
# to previous term.
curr_term = a
for i in range ( 1 , n + 1 ):
print (curr_term, end = ' ' )
curr_term = curr_term + d
# Driver code a = 2 # starting number
d = 1 # Common difference
n = 5 # N th term to be find
printAP(a, d, n) # This code is contributed # by Azkia Anam and Updated by Ameya Bavkar. |
C#
// C# Program to print an arithmetic // progression series using System;
class GFG
{ static void printAP( int a, int d, int n)
{
// Printing AP by simply adding
// d to previous term.
int curr_term;
curr_term=a; for ( int i = 1; i <= n; i++)
{
Console.Write(curr_term + " " );
curr_term += d; }
}
// Driver code
public static void Main()
{
// starting number
int a = 2;
// Common difference
int d = 1;
// N th term to be find
int n = 5;
printAP(a, d, n);
}
} // This code is contributed by vgt_m. |
Javascript
<script> // JavaScript Program to print an arithmetic // progression series function printAP(a, d, n)
{
// Printing AP by simply adding d
// to previous term.
let curr_term;
curr_term=a;
for (let i = 1; i <= n; i++)
{ document.write(curr_term + " " );
curr_term =curr_term + d;
}
}
// Driver code
// starting number
let a = 2;
// Common difference
let d = 1;
// N th term to be find
let n = 5;
printAP(a, d, n);
// This code is contributed by Surbhi Tyagi </script> |
PHP
<?php // PHP Program to print an arithmetic // progression series function printAP( $a , $d , $n )
{ // Printing AP by simply adding d
// to previous term.
$curr_term = $a ;
for ( $i = 1; $i <= $n ; $i ++)
{ echo ( $curr_term . " " );
$curr_term += $d ;
}
} // Driver code // starting number $a = 2;
// Common difference $d = 1;
// N th term to be find $n = 5;
printAP( $a , $d , $n );
// This code is contributed by Ajit and Updated by Ameya Bavkar. ?> |
Output
2 3 4 5 6
Time complexity: O(n) where n is the total number of terms of a given A.P
Auxiliary Space: O(1)