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Program for product of array
  • Difficulty Level : Easy
  • Last Updated : 25 May, 2018

Given an array, find product of all array elements.

Examples :

Input  : ar[] = {1, 2, 3, 4, 5}
Output : 120
Product of array elements is 1 x 2
x 3 x 4 x 5 = 120.

Input  : ar[] = {1, 6, 3}
Output : 18

C




// C program to find product of array
// elements.
#include <stdio.h>
  
int product(int ar[], int n)
{
    int result = 1;
    for (int i = 0; i < n; i++)
        result = result * ar[i];
    return result;
}
  
// driver code for the above program
int main()
{
    int ar[] = { 1, 2, 3, 4, 5 };
    int n = sizeof(ar) / sizeof(ar[0]);
    printf("%d", product(a, n));
    return 0;
}


Java




// Java program to find product of array
// elements.
class GFG{
  
    static int product(int ar[], int n)
    {
        int result = 1;
        for (int i = 0; i < n; i++)
            result = result * ar[i];
        return result;
    }
       
    // driver code for the above program
    public static void main(String[] args)
    {
        int ar[] = { 1, 2, 3, 4, 5 };
        int n = ar.length;
        System.out.printf("%d", product(ar, n));
    }
}
  
// This code is contributed by Smitha Dinesh Semwal


Python3




# Python3 program to find 
# product of array elements.
def product(ar, n):
  
    result = 1
    for i in range(0, n):
        result = result * ar[i]
    return result
  
  
# Driver Code
ar = [ 1, 2, 3, 4, 5 ]
n = len(ar)
  
print(product(ar, n))
  
# This code is contributed by Smitha Dinesh Semwal.


C#




// C# program to find product of array
// elements.
using System;
  
class GFG {
  
    static int product(int []ar, int n)
    {
        int result = 1;
          
        for (int i = 0; i < n; i++)
            result = result * ar[i];
              
        return result;
    }
      
    // driver code for the above program
    public static void Main()
    {
        int []ar = { 1, 2, 3, 4, 5 };
        int n = ar.Length;
          
        Console.WriteLine(product(ar, n));
    }
}
  
// This code is contributed by vt_m.


PHP




<?php
// PHP program to find product 
// of array elements.
  
function product($ar, $n)
{
    $result = 1;
    for ($i = 0; $i < $n; $i++)
        $result = $result * $ar[$i];
    return $result;
}
  
// Driver Code
$ar = array( 1, 2, 3, 4, 5 );
$n = count($ar);
print((int)product($ar, $n));
  
// This code is contributed by Sam007
?>



Output :

120

The above code may cause overflow. Therefore it is always desired to compute product under modulo. The reason of its working is simple distributive property of modulo.

( a * b) % c = ( ( a % c ) * ( b % c ) ) % c

Below is program to find to find and print the product of all the number in this array of Modulo (10^9 +7).



C




// C code for above program to find product
// under modulo.
#include <stdio.h>
  
const int MOD = 1000000007;
  
int product(int ar[], int n)
{
    int result = 1;
    for (int i = 0; i < n; i++)
        result = (result * ar[i]) % MOD;
    return result;
}
  
// driver code for the above program
int main()
{
    int ar[] = { 1, 2, 3, 4, 5 };
    int n = sizeof(ar) / sizeof(ar[0]);
    printf("%d", product(ar, n));
    return 0;
}


Java




// Java code for above program to find product
// under modulo.
class GFG {
      
    static final int MOD = 1000000007;
  
    static int product(int ar[], int n)
    {
        int result = 1;
        for (int i = 0; i < n; i++)
            result = (result * ar[i]) % MOD;
              
        return result;
    }
  
    // driver code for the above program
    public static void main(String[] args)
    {
        int ar[] = { 1, 2, 3, 4, 5 };
        int n = ar.length;
          
        System.out.printf("%d", product(ar, n));
    }
}
  
// This code is contributed by  Smitha Dinesh Semwal.


Python3




# Python 3 code for above
# program to find product
# under modulo.
  
MOD = 1000000007
  
def product(ar, n):
  
    result = 1
    for i in range(0, n):
        result = (result * ar[i]) % MOD
    return result
  
  
# driver code for the
# above program
ar = [1, 2, 3, 4, 5
n = len(ar) 
  
print(product(ar, n))
  
# This code is contributed by
# Smitha Dinesh Semwal


C#




  // C# code for above program to find product
// under modulo.
using System;
class GFG {
      
    static  int MOD = 1000000007;
  
    static int product(int []ar, int n)
    {
        int result = 1;
        for (int i = 0; i < n; i++)
            result = (result * ar[i]) % MOD;
              
        return result;
    }
  
    // driver code for the above program
    public static void Main()
    {
        int []ar = { 1, 2, 3, 4, 5 };
        int n = ar.Length;
          
        Console.WriteLine(product(ar, n));
    }
}
  
// This code is contributed by vt_m.


PHP




<?php
// PHP code for above program 
// to find product under modulo.
  
function product($ar, $n)
{
    $result = 1;
    for ($i = 0; $i < $n; $i++)
        $result = ($result
                   $ar[$i]) % 1000000007;
    return $result;
}
  
// Driver Code
$ar = array( 1, 2, 3, 4, 5 );
$n = count($ar);
print(product($ar, $n));
  
// This code is contributed by Sam007
?>



Output :

120

This article is contributed by Shivani Baghel. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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