Program to find the sum of a Series (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + … + (n*n)

You have been given a series (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + … + (n*n), find out the sum of the series till nth term.
Examples :

Input : n = 3
Output : 14
Explanation : 1 + 1/2^2 + 1/3^3

Input : n = 5
Output : 55
Explanation : (1*1) + (2*2) + (3*3) + (4*4) + (5*5)

C++

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// CPP program to calculate the following series
#include<iostream>
using namespace std;
  
// Function to calculate the following series
int Series(int n)
{
    int i;
    int sums = 0;
    for (i = 1; i <= n; i++)
        sums += (i * i);
    return sums;
}
  
// Driver Code
int main()
{
    int n = 3;
    int res = Series(n);
    cout<<res<<endl;
}

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C














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// C program to calculate the following series 


#include <stdio.h> 


  


// Function to calculate the following series 


int Series(int n) 


{ 


    int i; 


    int sums = 0; 


    for (i = 1; i <= n; i++) 


        sums += (i * i); 


    return sums; 


} 


  


// Driver Code 


int main() 


{ 


    int n = 3; 


    int res = Series(n); 


    printf("%d", res); 


} 



















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Java














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// Java program to calculate the following series 


import java.io.*; 


class GFG { 


  


    // Function to calculate the following series 


    static int Series(int n) 


    { 


        int i; 


        int sums = 0; 


        for (i = 1; i <= n; i++) 


            sums += (i * i); 


        return sums; 


    } 


  


    // Driver Code 


    public static void main(String[] args) 


    { 


        int n = 3; 


        int res = Series(n); 


        System.out.println(res); 


    } 


} 



















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Python














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# Python program to calculate the following series 


def Series(n): 


    sums = 0


    for i in range(1, n + 1): 


        sums += (i * i); 


    return sums 


  


# Driver Code 


n = 3


res = Series(n) 


print(res) 



















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C#














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// C# program to calculate the following series 


using System; 


class GFG { 


  


    // Function to calculate the following series 


    static int Series(int n) 


    { 


        int i; 


        int sums = 0; 


        for (i = 1; i <= n; i++) 


            sums += (i * i); 


        return sums; 


    } 


  


    // Driver Code 


    public static void Main() 


    { 


        int n = 3; 


        int res = Series(n); 


        Console.Write(res); 


    } 


} 


  


// This code is contributed by vt_m. 



















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PHP














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<?php 


// PHP program to calculate 


// the following series 


  


// Function to calculate the 


// following series 


function Series($n) 


{ 


    $i; 


    $sums = 0; 


    for ($i = 1; $i <= $n; $i++) 


        $sums += ($i * $i); 


    return $sums; 


} 


  


// Driver Code 


$n = 3; 


$res = Series($n); 


echo($res); 


  


// This code is contributed by Ajit. 


?> 



















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Output :


14



Time Complexity: O(n)


Please refer below post for O(1) solution.

Sum of squares of first n natural numbers


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