Program to find slope of a line

Difficulty Level : Basic
Last Updated : 12 Mar, 2021

Given two co-ordinates, find the slope of a straight line.
Examples:

Input  : x1 = 4, y1 = 2, 
         x2 = 2, y2 = 5 
Output : Slope is -1.5

Approach: To calculate the slope of a line you need only two points from that line, (x1, y1) and (x2, y2). The equation used to calculate the slope from two points is:

Below is the implementation of the above approach:

c++

// C program for slope of line
#include <bits/stdc++.h>
using namespace std;
 
// function to find the slope of a straight line
float slope(float x1, float y1, float x2, float y2)
{
    return (y2 - y1) / (x2 - x1);
}
 
// driver code to check the above function
int main()
{
    float x1 = 4, y1 = 2;
    float x2 = 2, y2 = 5;
    cout << "Slope is: "
         << slope(x1, y1, x2, y2);
    return 0;
}

Java

// Java program for slope of line
import java.io.*;
 
class GFG {
    static float slope(float x1, float y1,
                       float x2, float y2)
    {
        return (y2 - y1) / (x2 - x1);
    }
    public static void main(String[] args)
    {
        float x1 = 4, y1 = 2;
        float x2 = 2, y2 = 5;
        System.out.println("Slope is " +
                    slope(x1, y1, x2, y2));
    }
}

Python

# Python program for slope of line
def slope(x1, y1, x2, y2):
    return (float)(y2-y1)/(x2-x1)
 
# driver code   
x1 = 4
y1 = 2
x2 = 2
y2 = 5
print "Slope is :", slope(x1, y1, x2, y2)

C#

// C# program for slope of line
using System;
 
class GFG
{
    static float slope(float x1, float y1,
                       float x2, float y2)
    {
        return (y2 - y1) / (x2 - x1);
    }
     
    // Driver code
    public static void Main()
    {
        float x1 = 4, y1 = 2;
        float x2 = 2, y2 = 5;
        Console.WriteLine("Slope is " +
                    slope(x1, y1, x2, y2));
    }
}
 
// This code is contributed by vt_m.

PHP

<?php
// PHP program for
// slope of line
 
// function to find the
// slope of a straight line
function slope($x1, $y1, $x2, $y2)
{
    return ($y2 - $y1) /
           ($x2 - $x1);
}
 
    // Driver Code
    $x1 = 4;
    $y1 = 2;
    $x2 = 2;
    $y2 = 5;
    echo "Slope is: "
         , slope($x1, $y1,
                 $x2, $y2);
 
// This code is contributed by anuj_67.
?>

Output:

Slope is: -1.5

Time Complexity: O(1)

Auxiliary Space: O(1)

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