Program to check whether the given number is Buzz Number or not
A number is said to be Buzz Number if it ends with 7 OR is divisible by 7.
The task is to check whether the given number is buzz number or not.
Examples:
Input : 63 Output : Buzz Number Explanation: 63 is divisible by 7, one of the condition is satisfied. Input : 72 Output : Not a Buzz Number Explanation: 72 % 7 != 0, 72 is neither divisible by 7 nor it ends with 7 so it is not a Buzz Number.
C++
// C++ program to check whether the // given number is Buzz Number or not. #include <cmath> #include <iostream> using namespace std; // function to check BUzz number. bool isBuzz(int num) { // checking if the number // ends with 7 and is divisible by 7 return (num % 10 == 7 || num % 7 == 0); } // Driver method int main(void) { int i = 67, j = 19; if (isBuzz(i)) cout << "Buzz Number\n"; else cout << "Not a Buzz Number\n"; if (isBuzz(j)) cout << "Buzz Number\n"; else cout << "Not a Buzz Number\n"; } |
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Java
// Java program to check whether the // given number is Buzz number or not import java.io.*; import java.util.*; class GFG { // function to check BUzz number. static boolean isBuzz(int num) { // checking if the number // ends with 7 and is divisible by 7 return (num % 10 == 7 || num % 7 == 0); } // Driver method public static void main(String args[]) { int i = 67, j = 19; if (isBuzz(i)) System.out.println("Buzz Number"); else System.out.println("Not a Buzz Number"); if (isBuzz(j)) System.out.println("Buzz Number"); else System.out.println("Not a Buzz Number"); } } // This code is contributed by Nikita Tiwari. |
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Python
# Python program to check whether the # given number is Buzz Number or not. # function to check BUzz number. def isBuzz(num) : # checking if the number # ends with 7 and is divisible by 7 return (num % 10 == 7 or num % 7 == 0) # Driver method i = 67j = 19if (isBuzz(i)) : print "Buzz Number"else : print "Not a Buzz Number"if (isBuzz(j)) : print "Buzz Number"else : print "Not a Buzz Number" |
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PHP
<?php // PHP code to check Buzz Number // Function for Buzz Number function isBuzz($num) { // checking if the number // ends with 7 and is divisible by 7 return($num % 10 == 7 || $num % 7 == 0); } // Driver Code $i = 67; $j = 43; if(isBuzz($i)) print("Buzz Number\n"); elseprint("Not Buzz Number\n"); if(isBuzz($j)) print("Buzz Number\n"); elseprint("Not Buzz Number\n"); // This code is contributed by akash7981 ?> |
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C#
// C# program to check whether the // given number is Buzz number or not using System; class GFG { // function to check BUzz number. static bool isBuzz(int num) { // checking if the number // ends with 7 and is // divisible by 7 return (num % 10 == 7 || num % 7 == 0); } // Driver method public static void Main() { int i = 67, j = 19; if (isBuzz(i)) Console.WriteLine("Buzz Number"); else Console.Write("Not a Buzz Number"); if (isBuzz(j)) Console.Write("Buzz Number"); else Console.Write("Not a Buzz Number"); } } // This code is contributed by Nitin mittal. |
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Output:
Buzz Number Not a Buzz Number
Time complexity : O(1) as there are atomic statements and no loops.
This article is contributed by Nikita Tiwari. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
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