# Program to check whether the given number is Buzz Number or not

A number is said to be Buzz Number if it ends with 7 OR is divisible by 7.
The task is to check whether the given number is buzz number or not.

Examples:

```Input : 63
Output : Buzz Number
Explanation: 63 is divisible by 7, one
of the condition is satisfied.

Input : 72
Output : Not a Buzz Number
Explanation: 72 % 7 != 0, 72 is neither
divisible by 7 nor it ends with 7 so
it is not a Buzz Number.```

## C++

 `// C++ program to check whether the ` `// given number is Buzz Number or not. ` `#include ` `#include ` `using` `namespace` `std; ` ` `  `// function to check BUzz number. ` `bool` `isBuzz(``int` `num) ` `{ ` `    ``// checking if the number ` `    ``// ends with 7 and is divisible by 7 ` `    ``return` `(num % 10 == 7 || num % 7 == 0); ` `} ` ` `  `// Driver method ` `int` `main(``void``) ` `{ ` `    ``int` `i = 67, j = 19; ` `    ``if` `(isBuzz(i)) ` `        ``cout << ``"Buzz Number\n"``; ` `    ``else` `        ``cout << ``"Not a Buzz Number\n"``; ` `    ``if` `(isBuzz(j)) ` `        ``cout << ``"Buzz Number\n"``; ` `    ``else` `        ``cout << ``"Not a Buzz Number\n"``; ` `} `

## Java

 `// Java program to check whether the ` `// given number is Buzz number or not ` `import` `java.io.*; ` `import` `java.util.*; ` `class` `GFG { ` ` `  `    ``// function to check BUzz number. ` `    ``static` `boolean` `isBuzz(``int` `num) ` `    ``{ ` `        ``// checking if the number ` `        ``// ends with 7 and is divisible by 7 ` `        ``return` `(num % ``10` `== ``7` `|| num % ``7` `== ``0``); ` `    ``} ` ` `  `    ``// Driver method ` `    ``public` `static` `void` `main(String args[]) ` `    ``{ ` `        ``int` `i = ``67``, j = ``19``; ` `        ``if` `(isBuzz(i)) ` `            ``System.out.println(``"Buzz Number"``); ` `        ``else` `            ``System.out.println(``"Not a Buzz Number"``); ` `        ``if` `(isBuzz(j)) ` `            ``System.out.println(``"Buzz Number"``); ` `        ``else` `            ``System.out.println(``"Not a Buzz Number"``); ` `    ``} ` `} ` `// This code is contributed by Nikita Tiwari. `

## Python

 `# Python program to check whether the ` `# given number is Buzz Number or not. ` ` `  `# function to check BUzz number. ` `def` `isBuzz(num) : ` `     `  `    ``# checking if the number  ` `    ``# ends with 7 and is divisible by 7  ` `    ``return` `(num ``%` `10` `=``=` `7` `or` `num ``%` `7` `=``=` `0``)  ` ` `  `# Driver method ` `i ``=` `67` `j ``=` `19` `if` `(isBuzz(i)) : ` `    ``print` `"Buzz Number"` `else` `: ` `    ``print` `"Not a Buzz Number"` `if` `(isBuzz(j)) : ` `    ``print` `"Buzz Number"` `else` `: ` `    ``print` `"Not a Buzz Number"`

## PHP

 ` `

## C#

 `// C# program to check whether the ` `// given number is Buzz number or not ` `using` `System; ` ` `  `class` `GFG { ` ` `  `    ``// function to check BUzz number. ` `    ``static` `bool` `isBuzz(``int` `num) ` `    ``{ ` `         `  `        ``// checking if the number ` `        ``// ends with 7 and is  ` `        ``// divisible by 7 ` `        ``return` `(num % 10 == 7 || num % 7 == 0); ` `    ``} ` ` `  `    ``// Driver method ` `    ``public` `static` `void` `Main() ` `    ``{ ` `        ``int` `i = 67, j = 19; ` `         `  `        ``if` `(isBuzz(i)) ` `            ``Console.WriteLine(``"Buzz Number"``); ` `        ``else` `            ``Console.Write(``"Not a Buzz Number"``); ` `             `  `        ``if` `(isBuzz(j)) ` `            ``Console.Write(``"Buzz Number"``); ` `        ``else` `            ``Console.Write(``"Not a Buzz Number"``); ` `    ``} ` `} ` ` `  `// This code is contributed by Nitin mittal. `

Output:

```Buzz Number
Not a Buzz Number```

Time complexity : O(1) as there are atomic statements and no loops.

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