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Program to check whether the given number is Buzz Number or not
• Last Updated : 04 Apr, 2018

A number is said to be Buzz Number if it ends with 7 OR is divisible by 7.
The task is to check whether the given number is buzz number or not.

Examples:

Input : 63
Output : Buzz Number
Explanation: 63 is divisible by 7, one
of the condition is satisfied.

Input : 72
Output : Not a Buzz Number
Explanation: 72 % 7 != 0, 72 is neither
divisible by 7 nor it ends with 7 so
it is not a Buzz Number.

## C++

 // C++ program to check whether the // given number is Buzz Number or not. #include #include using namespace std;    // function to check BUzz number. bool isBuzz(int num) {     // checking if the number     // ends with 7 and is divisible by 7     return (num % 10 == 7 || num % 7 == 0); }    // Driver method int main(void) {     int i = 67, j = 19;     if (isBuzz(i))         cout << "Buzz Number\n";     else         cout << "Not a Buzz Number\n";     if (isBuzz(j))         cout << "Buzz Number\n";     else         cout << "Not a Buzz Number\n"; }

## Java

 // Java program to check whether the // given number is Buzz number or not import java.io.*; import java.util.*; class GFG {        // function to check BUzz number.     static boolean isBuzz(int num)     {         // checking if the number         // ends with 7 and is divisible by 7         return (num % 10 == 7 || num % 7 == 0);     }        // Driver method     public static void main(String args[])     {         int i = 67, j = 19;         if (isBuzz(i))             System.out.println("Buzz Number");         else             System.out.println("Not a Buzz Number");         if (isBuzz(j))             System.out.println("Buzz Number");         else             System.out.println("Not a Buzz Number");     } } // This code is contributed by Nikita Tiwari.

## Python

 # Python program to check whether the # given number is Buzz Number or not.    # function to check BUzz number. def isBuzz(num) :            # checking if the number      # ends with 7 and is divisible by 7      return (num % 10 == 7 or num % 7 == 0)     # Driver method i = 67 j = 19 if (isBuzz(i)) :     print "Buzz Number" else :     print "Not a Buzz Number" if (isBuzz(j)) :     print "Buzz Number" else :     print "Not a Buzz Number"



## C#

 // C# program to check whether the // given number is Buzz number or not using System;    class GFG {        // function to check BUzz number.     static bool isBuzz(int num)     {                    // checking if the number         // ends with 7 and is          // divisible by 7         return (num % 10 == 7 || num % 7 == 0);     }        // Driver method     public static void Main()     {         int i = 67, j = 19;                    if (isBuzz(i))             Console.WriteLine("Buzz Number");         else             Console.Write("Not a Buzz Number");                        if (isBuzz(j))             Console.Write("Buzz Number");         else             Console.Write("Not a Buzz Number");     } }    // This code is contributed by Nitin mittal.

Output:

Buzz Number
Not a Buzz Number

Time complexity : O(1) as there are atomic statements and no loops.

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