Program to check Plus Perfect Number

Given a ‘n’ digit number x, check if it is a plus perfect number or not. A number is plus perfect number if it is equal to the sum of its digits raised to the nth power.

Examples :

Input : x  = 371
Output : Yes
Explanation :  
Number of digits n = 3
(3*3*3) + (7*7*7) + (1*1*1) = 371

Input : x = 9474
Output : Yes
Explanation : 
Number of digits n = 4
(9*9*9*9) + (4*4*4*4) + (7*7*7*7) + 
(4*4*4*4) = 9474

Input : x = 9473
Output : No
Explanation : 
Number of digits n = 4
(9*9*9*9) + (4*4*4*4) + (7*7*7*7) +
(3*3*3*3) != 9474

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Below is the implementation to check if a number is plus perfect number or not.

C++

// CPP implementation to check 
// if the number is plus perfect  
// or not 
#include <bits/stdc++.h> 
using namespace std; 
  
// function to check plus perfect number 
bool checkplusperfect(int x) 
{ 
    int temp = x; 
      
    // calculating number of digits 
    int n = 0; 
    while (x != 0) { 
        x /= 10; 
        n++; 
    }    
      
    // calculating plus perfect number 
    x = temp; 
    int sum = 0; 
    while (x != 0) { 
        sum += pow(x % 10, n); 
        x /= 10; 
    } 
      
    // checking whether number  
    // is plus perfect or not 
    return (sum == temp); 
} 
  
// driver program 
int main() 
{     
    int x = 9474; 
    if (checkplusperfect(x)) 
        cout << "Yes"; 
    else
        cout << "No";         
    return 0; 
}  

Java

// java implementation to check 
// if the number is plus perfect  
// or not 
import java.io.*; 
  
class GFG { 
      
    // function to check plus perfect number 
    static boolean checkplusperfect(int x) 
    { 
        int temp = x; 
          
        // calculating number of digits 
        int n = 0; 
        while (x != 0)  
        { 
            x /= 10; 
            n++; 
        }  
          
        // calculating plus perfect number 
        x = temp; 
        int sum = 0; 
        while (x != 0)  
        { 
            sum += Math.pow(x % 10, n); 
            x /= 10; 
        } 
          
        // checking whether number  
        // is plus perfect or not 
        return (sum == temp); 
    } 
      
    // Driver program 
    public static void main (String[] args)  
    { 
        int x = 9474; 
        if (checkplusperfect(x)) 
            System.out.println ( "Yes"); 
        else
            System.out.println ( "No");  
      
    } 
} 
  
// This code is contributed by vt_m 

Python3

# Python 3 implementation to check 
# if the number is plus perfect  
# or not 
import math 
  
# function to check plus perfect number 
def checkplusperfect(x) : 
    temp = x 
      
    # calculating number of digits 
    n = 0
    while (x != 0) : 
        x = x // 10
        n = n + 1
      
      
    # calculating plus perfect number 
    x = temp 
    sm = 0
    while (x != 0) : 
        sm = sm + (int)(math.pow(x % 10, n)) 
        x = x // 10
      
      
    # checking whether number  
    # is plus perfect or not 
    return (sm == temp) 
  
  
# driver program 
x = 9474
if (checkplusperfect(x)) : 
    print("Yes") 
else : 
    print("No") 
      
  
# This code is contributed by Nikita Tiwari. 

C#

// C# implementation to check 
// if the number is plus perfect  
// or not 
using System; 
  
class GFG { 
      
    // function to check plus perfect number 
    static bool checkplusperfect(int x) 
    { 
        int temp = x; 
          
        // calculating number of digits 
        int n = 0; 
        while (x != 0)  
        { 
            x /= 10; 
            n++; 
        }  
          
        // calculating plus perfect number 
        x = temp; 
        int sum = 0; 
        while (x != 0)  
        { 
            sum += (int)Math.Pow(x % 10, n); 
            x /= 10; 
        } 
          
        // checking whether number  
        // is plus perfect or not 
        return (sum == temp); 
    } 
      
    // Driver program 
    public static void Main ()  
    { 
        int x = 9474; 
        if (checkplusperfect(x)) 
            Console.WriteLine ( "Yes"); 
        else
            Console.WriteLine ( "No");  
      
    } 
} 
  
// This code is contributed by vt_m 

PHP

<?php 
// PHP implementation to check 
// if the number is plus perfect  
// or not 
  
// function to check plus 
// perfect number 
function checkplusperfect($x) 
{ 
    $temp = $x; 
      
    // calculating number 
    // of digits 
    $n = 0; 
    while ($x != 0) 
    { 
        $x /= 10; 
        $n++; 
    }  
      
    // calculating plus  
    // perfect number 
    $x = $temp; 
    $sum = 0; 
    while ($x != 0) 
    { 
        $sum += pow($x % 10, $n); 
        $x /= 10; 
    } 
      
    // checking whether number  
    // is plus perfect or not 
    return ($sum == $temp); 
} 
  
    // Driver Code 
    $x = 9474; 
    if (checkplusperfect(!$x)) 
        echo "Yes"; 
    else
        echo "No";  
      
// This code is contributed by ajit  
?> 

Output :

Yes

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My Personal Notes

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

C++

Java

Python3

C#

PHP

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