Program to check if a number is Positive, Negative, Odd, Even, Zero

Prerequisite : Loops in Python

To check whether a number is positive, negative, odd, even or zero. This problem is solved using if…elif…else and nested if…else statement.
Approach :

A number is positive if it is greater than zero. We check this in the expression of if.
If it is False, the number will either be zero or negative.
This is also tested in subsequent expression.
In case of odd and even A number is even if it is perfectly divisible by 2.
- When the number is divided by 2, we use the remainder operator % to compute the remainder.
- If the remainder is not zero, the number is odd.

Examples:

Input : 10
Output :
Positive number
10 is Even

Input : 0
Output : 0 is Even

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

# Python Code to check if a number is 
# Positive, Negative, Odd, Even, Zero  
# Using if...elif...else 
num = 10
if num > 0: 
   print("Positive number") 
elif num == 0: 
   print("Zero") 
else: 
   print("Negative number") 
  
# Checking for odd and even 
if (num % 2) == 0: 
   print("{0} is Even".format(num)) 
else: 
   print("{0} is Odd".format(num)) 

Output:
Positive number
10 is Even

# Python Code to check if a number is 
# Positive, Negative, Odd, Even, Zero 
# Using Nested if 
num = 20
if num >= 0: 
   if num == 0: 
       print("Zero") 
   else: 
       print("Positive number") 
else: 
   print("Negative number") 
  
# Cchecking for odd and even 
if (num % 2) == 0: 
   print("{0} is Even".format(num)) 
else: 
   print("{0} is Odd".format(num)) 

Output:
Positive number
20 is Even

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My Personal Notes

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

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