Product of middle row and column in an odd square matrix

Given an integer square matrix of odd dimensions (3 * 3, 5 * 5). The task is to find the product of the middle row & middle column elements.

Examples:

Input: mat[][] = 
{{2, 1, 7},
 {3, 7, 2},
 {5, 4, 9}}
Output: Product of middle row = 42
         Product of middle column = 28
Explanation : Product of Middle row elements (3*7*2)
Product of Middle Column elements (1*7*4)
Input: mat[][] =
{ {1, 3, 5, 6, 7},
  {3, 5, 3, 2, 1},
  {1, 2, 3, 4, 5},
  {7, 9, 2, 1, 6},
  {9, 1, 5, 3, 2}}
Output: Product of middle row = 120
         Product of middle column = 450

Approach: As the given matrix is of odd dimensions so the middle row and column will be at n/2 th index always. So, Run a loop from i = 0 to N and product all the elements of middle row i.e. row_prod *= mat[n / 2][i]. Similarly, product of elements of middle column will be col_prod *= mat[i][n / 2].

Below is the implementation of the above approach:

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// C++ program to find product of
// middle row and middle column in matrix
#include <iostream>
using namespace std;
const int MAX = 100;
  
void middleProduct(int mat[][MAX], int n)
{
  
    // loop for product of row and column
    int row_prod = 1, col_prod = 1;
    for (int i = 0; i < n; i++) {
        row_prod *= mat[n / 2][i];
        col_prod *= mat[i][n / 2];
    }
  
    // Print result
    cout << "Product of middle row = "
         << row_prod << endl;
  
    cout << "Product of middle column = "
         << col_prod;
}
  
// Driver code
int main()
{
    int mat[][MAX] = { { 2, 1, 7 },
                       { 3, 7, 2 },
                       { 5, 4, 9 } };
  
    middleProduct(mat, 3);
  
    return 0;
}
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// Java program to find product of
// middle row and middle column in matrix
import java.io.*;
  
class GFG {
  
  
static int MAX = 100;
  
static void middleProduct(int mat[][], int n)
{
  
    // loop for product of row and column
    int row_prod = 1, col_prod = 1;
    for (int i = 0; i < n; i++) {
        row_prod *= mat[n / 2][i];
        col_prod *= mat[i][n / 2];
    }
  
    // Print result
    System.out.print("Product of middle row = "
        + row_prod);
  
    System.out.print( "Product of middle column = "
        + col_prod);
}
  
    // Driver code
    public static void main (String[] args) {
            int mat[][] = { { 2, 1, 7 },
                    { 3, 7, 2 },
                    { 5, 4, 9 } };
  
    middleProduct(mat, 3);
    }
}
// This code is contributed by shs
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# Python3 program to find product of
# middle row and middle column in matrix
  
MAX = 100
  
def middleProduct(mat, n):
  
    # loop for product of row and column
    row_prod = 1
    col_prod = 1
    for i in range(n) :
        row_prod *= mat[n // 2][i]
        col_prod *= mat[i][n // 2]
  
    # Print result
    print ("Product of middle row = "
                             row_prod)
  
    print ("Product of middle column = "
                                col_prod)
                                  
# Driver code
if __name__ == "__main__":
  
    mat = [[ 2, 1, 7 ],
           [ 3, 7, 2 ],
           [ 5, 4, 9 ]]
  
    middleProduct(mat, 3)
  
# This code is contributed by ita_c    
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// C# program to find product of
// middle row and middle column in matrix
using System;
  
class GFG {
  
  
//static int MAX = 100;
  
static void middleProduct(int [,]mat, int n)
{
  
    // loop for product of row and column
    int row_prod = 1, col_prod = 1;
    for (int i = 0; i < n; i++) {
        row_prod *= mat[n / 2,i];
        col_prod *= mat[i,n / 2];
    }
  
    // Print result
    Console.WriteLine("Product of middle row = "
        + row_prod);
  
    Console.WriteLine( "Product of middle column = "
        + col_prod);
}
  
    // Driver code
    public static void Main () {
            int [,]mat = { { 2, 1, 7 },
                    { 3, 7, 2 },
                    { 5, 4, 9 } };
  
    middleProduct(mat, 3);
    }
}
// This code is contributed by shs
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<?php
// PHP program to find product of
// middle row and middle column in matrix
  
$MAX = 100;
  
function middleProduct($mat, $n)
{
  
    // loop for product of row and column
    $row_prod = 1; $col_prod = 1;
    for ($i = 0; $i < $n; $i++) 
    {
        $row_prod *= $mat[$n / 2][$i];
        $col_prod *= $mat[$i][$n / 2];
    }
  
    // Print result
    echo "Product of middle row = " .
                    $row_prod . "\n";
  
    echo "Product of middle column = " .
                              $col_prod;
}
  
// Driver code
$mat= array(array( 2, 1, 7 ),
            array( 3, 7, 2 ),
            array( 5, 4, 9 ));
  
middleProduct($mat, 3);
  
// This code is contributed
// by Akanksha Rai
?>
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Output:
Product of middle row = 42
Product of middle column = 28

Time Complexity: O(n)

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