Given a doubly linked list containing N nodes. The task is to find the product of all prime nodes.
Example:
Input: List = 15 <=> 16 <=> 6 <=> 7 <=> 17
Output: Product of Prime Nodes: 119Input: List = 5 <=> 3 <=> 4 <=> 2 <=> 9
Output: Product of Prime Nodes: 30
Approach:
- Initialize a pointer temp with the head of the linked list and a product variable with 1.
- Start traversing the linked list using a loop until all the nodes get traversed.
- If node value is prime then multiply the value of the current node to the product i.e. product *= current_node-> data.
- Increment the pointer to the next node of linked list i.e. temp = temp -> next.
- Return the product.
Below is the implementation of the above approach:
C++
// C++ implementation to product all // prime nodes from the doubly // linked list #include <bits/stdc++.h> using namespace std;
// Node of the doubly linked list struct Node {
int data;
Node *prev, *next;
}; // function to insert a node at the beginning // of the Doubly Linked List void push(Node** head_ref, int new_data)
{ // allocate node
Node* new_node = (Node*) malloc ( sizeof ( struct Node));
// put in the data
new_node->data = new_data;
// since we are adding at the beginning,
// prev is always NULL
new_node->prev = NULL;
// link the old list of the new node
new_node->next = (*head_ref);
// change prev of head node to new node
if ((*head_ref) != NULL)
(*head_ref)->prev = new_node;
// move the head to point to the new node
(*head_ref) = new_node;
} // Function to check if a number is prime bool isPrime( int n)
{ // Corner cases
if (n <= 1)
return false ;
if (n <= 3)
return true ;
// This is checked so that we can skip
// middle five numbers in below loop
if (n % 2 == 0 || n % 3 == 0)
return false ;
for ( int i = 5; i * i <= n; i = i + 6)
if (n % i == 0 || n % (i + 2) == 0)
return false ;
return true ;
} // function to product all prime nodes // from the doubly linked list int prodOfPrime(Node** head_ref)
{ Node* ptr = *head_ref;
Node* next;
// variable prod = 1 for multiplying nodes value
int prod = 1;
// traverse list till last node
while (ptr != NULL) {
next = ptr->next;
// if number is prime then
// multiply to product
if (isPrime(ptr->data))
prod = prod * ptr->data;
ptr = next;
}
// return product
return prod;
} // Driver program int main()
{ // start with the empty list
Node* head = NULL;
// create the doubly linked list
// 15 <-> 16 <-> 7 <-> 6 <-> 17
push(&head, 17);
push(&head, 6);
push(&head, 7);
push(&head, 16);
push(&head, 15);
int prod = prodOfPrime(&head);
cout << "Product of Prime Nodes : " << prod;
return 0;
} |
Java
// Java implementation to product all // prime nodes from the doubly // linked list // Node of the doubly linked list class Node
{ int data;
Node next, prev;
Node( int d)
{
data = d;
next = null ;
prev = null ;
}
} class DLL
{ // function to insert a node at the beginning
// of the Doubly Linked List
static Node push(Node head, int data)
{
Node newNode = new Node(data);
newNode.next = head;
newNode.prev = null ;
if (head != null )
head.prev = newNode;
head = newNode;
return head;
}
// Function to check if a number is prime
static boolean isPrime( int n)
{
// Corner cases
if (n <= 1 )
return false ;
if (n <= 3 )
return true ;
// This is checked so that we can skip
// middle five numbers in below loop
if (n % 2 == 0 || n % 3 == 0 )
return false ;
for ( int i = 5 ; i * i <= n; i = i + 6 )
if (n % i == 0 || n % (i + 2 ) == 0 )
return false ;
return true ;
}
// function to product all prime nodes
// from the doubly linked list
static int prodOfPrime(Node node)
{
// variable prod = 1 for multiplying nodes value
int prod = 1 ;
// traverse list till last node
while (node != null )
{
// check is node value is Prime
// if true then multiply to prod
if (isPrime(node.data))
prod *= node.data;
node = node.next;
}
// return product
return prod;
}
// Driver Program
public static void main(String[] args)
{
// Start with empty list
Node head = null ;
// create the doubly linked list
// 15 <-> 16 <-> 7 <-> 6 <-> 17
head = push(head, 17 );
head = push(head, 7 );
head = push(head, 6 );
head = push(head, 9 );
head = push(head, 10 );
head = push(head, 16 );
head = push(head, 15 );
int prod = prodOfPrime(head);
System.out.println( "Product of Prime Nodes: " + prod);
}
} // This code is contributed by Vivekkumar Singh |
Python3
# Python3 implementation to product all # prime nodes from the doubly # linked list # Node of the doubly linked list class Node:
def __init__( self , data):
self .data = data
self .prev = None
self . next = None
# function to insert a node at the beginning # of the Doubly Linked List def push(head_ref, new_data):
# allocate node
new_node = Node( 0 )
# put in the data
new_node.data = new_data
# since we are multiplying at the beginning,
# prev is always None
new_node.prev = None
# link the old list of the new node
new_node. next = (head_ref)
# change prev of head node to new node
if ((head_ref) ! = None ):
(head_ref).prev = new_node
# move the head to point to the new node
(head_ref) = new_node
return head_ref
# Function to check if a number is prime def isPrime(n):
# Corner cases
if (n < = 1 ):
return False
if (n < = 3 ):
return True
# This is checked so that we can skip
# middle five numbers in below loop
if (n % 2 = = 0 or n % 3 = = 0 ):
return False
i = 5
while ( i * i < = n ):
if (n % i = = 0 or n % (i + 2 ) = = 0 ):
return False
i + = 6 ;
return True
# function to product all prime nodes # from the doubly linked list def prodOfPrime(head_ref):
ptr = head_ref
next = None
# variable prod = 1 for multiplying nodes value
prod = 1
# traverse list till last node
while (ptr ! = None ):
next = ptr. next
# if number is prime then
# multiply to product
if (isPrime(ptr.data)):
prod = prod * ptr.data
ptr = next
# return product
return prod
# Driver Code if __name__ = = "__main__" :
# start with the empty list
head = None
# create the doubly linked list
# 15 <. 16 <. 7 <. 6 <. 17
head = push(head, 17 )
head = push(head, 6 )
head = push(head, 7 )
head = push(head, 16 )
head = push(head, 15 )
prod = prodOfPrime(head)
print ( "Product of Prime Nodes : " , prod)
# This code is contributed by Arnab Kundu |
C#
// C# implementation to product all // prime nodes from the doubly // linked list using System;
// Node of the doubly linked list public class Node
{ public int data;
public Node next, prev;
public Node( int d)
{
data = d;
next = null ;
prev = null ;
}
} class DLL
{ // function to insert a node at the beginning
// of the Doubly Linked List
static Node push(Node head, int data)
{
Node newNode = new Node(data);
newNode.next = head;
newNode.prev = null ;
if (head != null )
head.prev = newNode;
head = newNode;
return head;
}
// Function to check if a number is prime
static Boolean isPrime( int n)
{
// Corner cases
if (n <= 1)
return false ;
if (n <= 3)
return true ;
// This is checked so that we can skip
// middle five numbers in below loop
if (n % 2 == 0 || n % 3 == 0)
return false ;
for ( int i = 5; i * i <= n; i = i + 6)
if (n % i == 0 || n % (i + 2) == 0)
return false ;
return true ;
}
// function to product all prime nodes
// from the doubly linked list
static int prodOfPrime(Node node)
{
// variable prod = 1 for multiplying nodes value
int prod = 1;
// traverse list till last node
while (node != null )
{
// check is node value is Prime
// if true then multiply to prod
if (isPrime(node.data))
prod *= node.data;
node = node.next;
}
// return product
return prod;
}
// Driver code
public static void Main(String []args)
{
// Start with empty list
Node head = null ;
// create the doubly linked list
// 15 <-> 16 <-> 7 <-> 6 <-> 17
head = push(head, 17);
head = push(head, 7);
head = push(head, 6);
head = push(head, 9);
head = push(head, 10);
head = push(head, 16);
head = push(head, 15);
int prod = prodOfPrime(head);
Console.WriteLine( "Product of Prime Nodes: " + prod);
}
} // This code is contributed by Arnab Kundu |
Javascript
<script> // JavaScript implementation to product all // prime nodes from the doubly // linked list // Node of the doubly linked list class Node { constructor(val) {
this .data = val;
this .prev = null ;
this .next = null ;
}
} // function to insert a node at the beginning
// of the Doubly Linked List
function push(head , data) {
var newNode = new Node(data);
newNode.next = head;
newNode.prev = null ;
if (head != null )
head.prev = newNode;
head = newNode;
return head;
}
// Function to check if a number is prime
function isPrime(n) {
// Corner cases
if (n <= 1)
return false ;
if (n <= 3)
return true ;
// This is checked so that we can skip
// middle five numbers in below loop
if (n % 2 == 0 || n % 3 == 0)
return false ;
for (i = 5; i * i <= n; i = i + 6)
if (n % i == 0 || n % (i + 2) == 0)
return false ;
return true ;
}
// function to product all prime nodes
// from the doubly linked list
function prodOfPrime(node) {
// variable prod = 1 for multiplying nodes value
var prod = 1;
// traverse list till last node
while (node != null ) {
// check is node value is Prime
// if true then multiply to prod
if (isPrime(node.data))
prod *= node.data;
node = node.next;
}
// return product
return prod;
}
// Driver Program
// Start with empty list
var head = null ;
// create the doubly linked list
// 15 <-> 16 <-> 7 <-> 6 <-> 17
head = push(head, 17);
head = push(head, 7);
head = push(head, 6);
head = push(head, 9);
head = push(head, 10);
head = push(head, 16);
head = push(head, 15);
var prod = prodOfPrime(head);
document.write( "Product of Prime Nodes: " + prod);
// This code contributed by umadevi9616 </script> |
Output
Product of Prime Nodes : 119
Complexity Analysis:
- Time Complexity: O(N), where N is the number of nodes.
- Space Complexity: O(1) because using constant variables