Product of all pairwise consecutive elements in an Array

• Difficulty Level : Basic
• Last Updated : 23 Apr, 2021

Given an array of integers of N elements. The task is to print the product of all of the pairwise consecutive elements.
Pairwise consecutive pairs of an array of size N are (a[i], a[i+1]) for all ranging from 0 to N-2
Examples

```Input  : arr[] = {8, 5, 4, 3, 15, 20}
Output : 40, 20, 12, 45, 300

Input  : arr[] = {5, 10, 15, 20}
Output : 50, 150, 300```

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The solution is to traverse the array and calculate and print the product of every pair (arr[i], arr[i+1]).
Below is the implementation of this approach:

C++

 `// C++ program to print the``// product of the consecutive elements.``#include ``using` `namespace` `std;` `// Function to print pairwise``// consecutive product``void` `pairwiseProduct(``int` `arr[], ``int` `n)``{``    ``int` `prod = 1;``    ``for` `(``int` `i = 0; i < n - 1; i++) {` `        ``// multiply the alternate numbers``        ``prod = arr[i] * arr[i + 1];``        ``printf``(``" %d "``, prod);``    ``}``}` `// Driver Code``int` `main()``{``    ``int` `arr[] = { 4, 10, 15, 5, 6 };``    ``int` `n = ``sizeof``(arr) / ``sizeof``(arr[0]);` `    ``pairwiseProduct(arr, n);` `    ``return` `0;``}`

Java

 `// Java program to print the product``// of the consecutive elements.``import` `java .io.*;` `class` `GFG``{``// Function to print pairwise``// consecutive product``static` `void` `pairwiseProduct(``int``[] arr,``                            ``int` `n)``{``    ``int` `prod = ``1``;``    ``for` `(``int` `i = ``0``; i < n - ``1``; i++)``    ``{` `        ``// multiply the alternate numbers``        ``prod = arr[i] * arr[i + ``1``];``        ``System.out.print(prod + ``" "``);``    ``}``}` `// Driver Code``public` `static` `void` `main(String[] args)``{``    ``int``[] arr = { ``4``, ``10``, ``15``, ``5``, ``6` `};``    ``int` `n = arr.length;` `    ``pairwiseProduct(arr, n);``}``}` `// This code is contributed``// by anuj_67..`

Python 3

 `# Python 3 program to print the``# product of the consecutive elements.` `# Function to print pairwise``# consecutive product``def` `pairwiseProduct( arr, n):` `    ``prod ``=` `1``    ``for` `i ``in` `range``(n ``-` `1``) :` `        ``# multiply the alternate numbers``        ``prod ``=` `arr[i] ``*` `arr[i ``+` `1``]``        ``print``(prod, end ``=` `" "``)``    ` `# Driver Code``if` `__name__``=``=``"__main__"``:` `    ``arr ``=` `[ ``4``, ``10``, ``15``, ``5``, ``6` `]``    ``n ``=` `len``(arr)` `    ``pairwiseProduct(arr, n)` `# This code is contributed``# by ChitraNayal`

C#

 `// C# program to print the product``// of the consecutive elements.``using` `System;` `class` `GFG``{``// Function to print pairwise``// consecutive product``static` `void` `pairwiseProduct(``int``[] arr,``                            ``int` `n)``{``    ``int` `prod = 1;``    ``for` `(``int` `i = 0; i < n - 1; i++)``    ``{` `        ``// multiply the alternate numbers``        ``prod = arr[i] * arr[i + 1];``        ``Console.Write(prod + ``" "``);``    ``}``}` `// Driver Code``public` `static` `void` `Main()``{``    ``int``[] arr = { 4, 10, 15, 5, 6 };``    ``int` `n = arr.Length;` `    ``pairwiseProduct(arr, n);``}``}` `// This code is contributed``// by Akanksha Rai(Abby_akku)`

PHP

 ``

Javascript

 ``
Output:
`40  150  75  30`

Time complexity : O(n)

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