Given 3 integers K, P and N. Where, K is the number of problems given to the person every day and P is the maximum number of problems he can solve in a day. Find the total number of problems not solved after the N-th day.
Examples:
Input : K = 2, P = 1, N = 3 Output : 3 On each day 1 problem is left so 3*1 = 3 problems left after Nth day. Input : K = 4, P = 1, N = 10 Output : 30
If P is greater than or equal to K then all problems will be solved on that day or (K-P) problems will be solved on each day so the answer will be 0 if K<=P else the answer will be (K-P)*N.
Below is the implementation of the above approach:
C++
// C++ program to find problems not // solved at the end of Nth day #include <bits/stdc++.h> using namespace std; // Function to find problems not // solved at the end of Nth day int problemsLeft( int K, int P, int N) { if (K <= P) return 0; else return (K - P) * N; } // Driver Code int main() { int K, P, N; K = 4; P = 1; N = 10; cout << problemsLeft(K, P, N); return 0; } |
Java
// Java program to find problems not // solved at the end of Nth day class Gfg { // Function to find problems not // solved at the end of Nth day public static int problemsLeft( int K, int P, int N) { if (K <= P) return 0 ; else return ((K - P) * N); } // Driver Code public static void main(String args[]) { int K, P, N; K = 4 ; P = 1 ; N = 10 ; System.out.println(problemsLeft(K, P, N)); } } |
Python3
# Python program to find problems not # solved at the end of Nth day def problemsLeft(K, P, N): if (K< = P): return 0 else : return ((K - P) * N) # Driver Code K, P, N = 4 , 1 , 10 print (problemsLeft(K, P, N)) |
C#
// C# program to find problems not // solved at the end of Nth day using System; class GFG { // Function to find problems not // solved at the end of Nth day public static int problemsLeft( int K, int P, int N) { if (K <= P) return 0; else return ((K - P) * N); } // Driver Code public static void Main() { int K, P, N; K = 4; P = 1; N = 10; Console.WriteLine(problemsLeft(K, P, N)); } } // This code is contributed by vt_m |
PHP
<?php // PHP program to find problems not // solved at the end of Nth day // Function to find problems not // solved at the end of Nth day function problemsLeft( $K , $P , $N ) { if ( $K <= $P ) return 0; else return ( $K - $P ) * $N ; } // Driver Code $K = 4; $P = 1; $N = 10; echo problemsLeft( $K , $P , $N ); // This code is contributed by anuj_67 ?> |
30
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