When we use final specifier with a method, the method cannot be overridden in any of the inheriting classes. Methods are made final due to design reasons.
Since private methods are inaccessible, they are implicitly final in Java. So adding final specifier to a private method doesn’t add any value. It may in-fact cause unnecessary confusion.
For example, both ‘program 1’ and ‘program 2’ below produce same compiler error “foo() has private access in Base”.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
- Private Methods in Java 9 Interfaces
- Can we override private methods in Java?
- Unreachable statement using final and non-final variable in Java
- Static methods vs Instance methods in Java
- Private Constructors and Singleton Classes in Java
- Replacing 'public' with 'private' in "main" in Java
- Final arrays in Java
- final keyword in java
- Blank Final in Java
- final variables in Java
- final vs Immutability in Java
- Using final with Inheritance in Java
- Java | final keyword | Question 4
- Java | final keyword | Question 3
- Final local variables in Java