Printing Heart Pattern in C
How to print below heart pattern in C?
AAAAAAA AAAAAA
AAAAAAAAA AAAAAAAA
AAAAAAAAAAA AAAAAAAAAA
AAAAAAAAAAAAA AAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAA
BBBBBBBBBBBBBBBBBBBBBBBBBBBBB
BBBBBBBBBBBBBBBBBBBBBBBBBBB
BBBBBBBBBBBBBBBBBBBBBBBBB
BBBBBBBBBBBBBBBBBBBBBBB
BBBBBBBBBBBBBBBBBBBBB
BBBBBBBBBBBBBBBBBBB
BBBBBBBBBBBBBBBBB
BBBBBBBBBBBBBBB
BBBBBBBBBBBBB
BBBBBBBBBBB
BBBBBBBBB
BBBBBBB
BBBBB
BBB
B
C++
#include<iostream>
using namespace std;
int main()
{
int a, b, size = 15;
for (a = size/2; a <= size; a = a+2)
{
for (b = 1; b < size-a; b = b+2)
cout<< " " ;
for (b = 1; b <= a; b++)
cout<< "A" ;
for (b = 1; b <= size-a; b++)
cout<< " " ;
for (b = 1; b <= a-1; b++)
cout<< "A" ;
cout<<endl;
}
for (a = size; a >= 0; a--)
{
for (b = a; b < size; b++)
cout<< " " ;
for (b = 1; b <= ((a * 2) - 1); b++)
cout<< "B" ;
cout<<endl;
}
}
|
C
#include<stdio.h>
int main()
{
int a, b, size = 15;
for (a = size/2; a <= size; a = a+2)
{
for (b = 1; b < size-a; b = b+2)
printf ( " " );
for (b = 1; b <= a; b++)
printf ( "A" );
for (b = 1; b <= size-a; b++)
printf ( " " );
for (b = 1; b <= a-1; b++)
printf ( "A" );
printf ( "\n" );
}
for (a = size; a >= 0; a--)
{
for (b = a; b < size; b++)
printf ( " " );
for (b = 1; b <= ((a * 2) - 1); b++)
printf ( "B" );
printf ( "\n" );
}
}
|
Java
class GFG {
public static void main(String arg[]) {
int a, b, size = 15 ;
for (a = size / 2 ; a <= size; a = a + 2 ) {
for (b = 1 ; b < size - a; b = b + 2 )
System.out.print( " " );
for (b = 1 ; b <= a; b++)
System.out.print( "A" );
for (b = 1 ; b <= size - a; b++)
System.out.print( " " );
for (b = 1 ; b <= a - 1 ; b++)
System.out.print( "A" );
System.out.print( "\n" );
}
for (a = size; a >= 0 ; a--) {
for (b = a; b < size; b++)
System.out.print( " " );
for (b = 1 ; b <= ((a * 2 ) - 1 ); b++)
System.out.print( "B" );
System.out.print( "\n" );
}
}
}
|
Python3
size = 15
for a in range ( int (size / 2 ), size + 1 , 2 ):
for b in range ( 1 , size - a, 2 ):
print ( " " , end = "")
for b in range ( 1 , a + 1 ):
print ( "A" ,end = "")
for b in range ( 1 , (size - a) + 1 ):
print ( " " , end = "")
for b in range ( 1 , a):
print ( "A" , end = "")
print ("")
for a in range (size, - 1 , - 1 ):
for b in range (a, size):
print ( " " , end = "")
for b in range ( 1 , (a * 2 )):
print ( "B" , end = "")
print ("")
|
C#
using System;
class GFG {
public static void Main() {
int a, b, size = 15;
for (a = size / 2; a <= size; a = a + 2) {
for (b = 1; b < size - a; b = b + 2)
Console.Write( " " );
for (b = 1; b <= a; b++)
Console.Write( "A" );
for (b = 1; b <= size - a; b++)
Console.Write( " " );
for (b = 1; b <= a - 1; b++)
Console.Write( "A" );
Console.WriteLine();
}
for (a = size; a >= 0; a--) {
for (b = a; b < size; b++)
Console.Write( " " );
for (b = 1; b <= ((a * 2) - 1); b++)
Console.Write( "B" );
Console.WriteLine( "" );
}
}
}
|
PHP
<?php
$size = 15;
for ( $a = floor ( $size / 2); $a <= $size ;
$a = $a + 2)
{
for ( $b = 1; $b < $size - $a ;
$b = $b + 2)
printf( " " );
for ( $b = 1; $b <= $a ; $b ++)
printf( "A" );
for ( $b = 1; $b <= $size - $a ; $b ++)
printf( " " );
for ( $b = 1; $b <= $a - 1; $b ++)
printf( "A" );
printf( "\n" );
}
for ( $a = $size ; $a >= 0; $a --)
{
for ( $b = $a ; $b < $size ; $b ++)
printf( " " );
for ( $b = 1; $b <= (( $a * 2) - 1); $b ++)
printf( "B" );
printf( "\n" );
}
?>
|
Javascript
<script>
var a, b, size = 15;
for (a = parseInt(size / 2); a <= size; a = a + 2) {
for (b = 1; b < size - a; b = b + 2)
document.write( " " );
for (b = 1; b <= a; b++)
document.write( "A" );
for (b = 1; b <= size - a; b++)
document.write( " " );
for (b = 1; b <= a - 1; b++)
document.write( "A" );
document.write( "<br>" );
}
for (a = size; a >= 0; a--) {
for (b = a; b < size; b++)
document.write( " " );
for (b = 1; b <= ((a * 2) - 1); b++)
document.write( "B" );
document.write( "<br>" );
}
</script>
|
Output :
AAAAAAA AAAAAA
AAAAAAAAA AAAAAAAA
AAAAAAAAAAA AAAAAAAAAA
AAAAAAAAAAAAA AAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAA
BBBBBBBBBBBBBBBBBBBBBBBBBBBBB
BBBBBBBBBBBBBBBBBBBBBBBBBBB
BBBBBBBBBBBBBBBBBBBBBBBBB
BBBBBBBBBBBBBBBBBBBBBBB
BBBBBBBBBBBBBBBBBBBBB
BBBBBBBBBBBBBBBBBBB
BBBBBBBBBBBBBBBBB
BBBBBBBBBBBBBBB
BBBBBBBBBBBBB
BBBBBBBBBBB
BBBBBBBBB
BBBBBBB
BBBBB
BBB
B
Time complexity: O(S2) for given input size S
Auxiliary Space: O(1)
Last Updated :
20 Feb, 2023
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