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Print all unique words of a String

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Write a function that takes a String as an argument and prints all unique words in it.


Input : Java is great. Grails is also great
Output : Java

The idea is to use map to keep track of words already occurred. But first, we have to extract all words from a String, as a string may contain many sentences with punctuation marks.
For extracting words from a String, refer Extracting each word from a String.

Python: The idea is to use a Dictionary for calculating the count of each word. But first, we have to extract all words from a String because a string may contain punctuation marks. This is done using regex or regular expression. The word which has count 1 in the dictionary is a unique word.


// Java program to print unique words
// from a string
import java.util.HashMap;
import java.util.Iterator;
import java.util.Set;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Test
    // Prints unique words in a string
    static void printUniquedWords(String str)
        // Extracting words from string
        Pattern p = Pattern.compile("[a-zA-Z]+");
        Matcher m = p.matcher(str);
        // Map to store count of a word
        HashMap<String, Integer> hm = new HashMap<>();
        // if a word found
        while (m.find())
            String word =;
            // If this is first occurrence of word
                hm.put(word, 1);
                // increment counter of word
                hm.put(word, hm.get(word) + 1);
        // Traverse map and print all words whose count
        // is  1
        Set<String> s = hm.keySet();
        Iterator<String> itr = s.iterator();
            String w =;
            if (hm.get(w) == 1)
    // Driver Method
    public static void main(String[] args)
        String str = "Java is great. Grails is also great";


# Python program to print unique word
# in a string.
# Using re (Regular Expression module)
# It is used here to match a pattern
# in the given string
import re
# Declare a dictionary
dict = {}
# Method to check whether the word
# exists in dictionary or not
def uniqueWord(Word):
    if Word in dict:
        # If the word exists in dictionary then
        # simply increase its count
        dict[words] += 1
        # If the word does not exists in
        # dictionary update the dictionary
        # and make its count 1
        dict.update({words: 1})
# Driver code
if __name__ == '__main__':
    string = "Java is great. Grails is also great"
    # re.split() method is used to split
    # all the words in a string separated
    # by non-alphanumeric characters (\W)
    ListOfWords = re.split("[\W]+", string)
    # Extract each word from ListOfWords
    # and pass it to the method uniqueWord()
    for words in ListOfWords:
    # Iterate over dictionary if the value
    # of the key is 1, then print the element
    for elements in dict:
        if dict[elements] == 1:



This article is contributed by Gaurav Ahirwar and Gaurav Miglani. If you like GeeksforGeeks and would like to contribute, you can also write an article using or mail your article to See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above. 

Method 2:using set()


In this approach, we store the string in the form of a set of individual words and print the words. To solve this problem in this method, first we need to know about

Below is the implementation of the above approach:


# python program to print all
# the unique words in a string
# in python using set() method
# function to print unique words
def printWords(l):
    # for loop for iterating
    for i in l:
# Driver code
str = "geeks for geeks"
# storing string in the form of list of words
s = set(str.split(" "))
# passing list to print words function



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Last Updated : 27 Jan, 2022
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