Print a String in wave pattern

Given a string, you need to transform this string in the form of a wave pattern

Examples:

Input : GeeksforGeeks, 2
Output :
G  e  s  o  G  e  s 
 e  k  f  r  e  k  

Input : GeeksforGeeks, 4
Output :
G      o      s 
 e    f  r    k  
  e  s    G  e   
   k      e

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

C++

// CPP program to print wave pattern  
// of a given string 
// This is a modified code of 
// https://www.geeksforgeeks.org/print-concatenation-of-zig-zag-string-form-in-n-rows/ 
  
#include<bits/stdc++.h> 
using namespace std; 
  
// Function that takes string and zigzag offset 
void fun(string s, int n)  
{ 
    // if offset is 1 
    if (n==1)              
    { 
        // simply print the strin and return 
        cout << s;              
        return; 
    } 
  
    // Get length of the string 
    int len = s.length();  
      
    // Create a 2d character array 
    char a[len][len] = { }; 
      
    // for counting the rows of the ZigZag 
    int row = 0;          
    bool down; 
      
    for (int i=0; i<len; i++) 
    { 
        // put characters in the matrix 
        a[row][i] = s[i];  
          
        // You have reached the bottom 
        if (row==n-1) 
            down = false;      
        else if (row==0) 
            down = true;     
              
        (down)?(row++):(row--); 
    } 
      
    // Print the Zig-Zag String 
    for (int i=0; i<n; i++) 
    {  
        for (int j=0; j<len; j++) 
        { 
            cout<<a[i][j]<<" "; 
        } 
        cout<<endl; 
    } 
} 
  
// Driver function 
int main() 
{ 
    string s = "GeeksforGeeks"; 
    int n = 3; 
    fun(s, n); 
} 

Java

// Java program to print wave   
// pattern of a given string 
import java.lang.*; 
import java.util.*; 
class GFG  
{ 
  
    // Function that takes  
    // string and zigzag offset 
    static void fun(String s, int n)  
    { 
          
    // if offset is 1 
    if (n == 1)              
    { 
        // simply print the 
        // strin and return 
        System.out.print(s);              
        return; 
    } 
  
    // Get length of the string 
    int len = s.length();  
      
    // Create a 2d character array 
    char [][]a = new char[len][len]; 
    char []c = s.toCharArray(); 
      
    // for counting the  
    // rows of the ZigZag 
    int row = 0;          
    boolean down = true; 
      
    for (int i = 0; i < len; i++) 
    { 
        // put characters in 
        // the matrix 
        a[row][i] = c[i];  
          
        // You have reached 
        // the bottom 
        if (row == n - 1) 
            down = false;      
        else if (row == 0) 
            down = true;  
              
        if(down) 
            row++; 
        else
            row--; 
    } 
      
    // Print the Zig-Zag String 
    for (int i = 0; i < n; i++) 
    {  
        for (int j = 0; j < len; j++) 
        { 
            System.out.print(a[i][j] + " "); 
        } 
        System.out.println(); 
    } 
    } 
      
    // Driver Code 
    public static void main(String[] args) 
    { 
        String s = "GeeksforGeeks"; 
        int n = 3; 
        fun(s, n); 
    } 
} 
  
// This code is contributed  
// by ChitraNayal 

Python 3

# Function that takes string 
# and zigzag offset 
def fun(s, n): 
      
    # if offset is 1 
    if (n == 1): 
          
        # simply print the 
        # string and return 
        print(s)              
        return
  
    # Get length of the string 
    l = len(s) 
      
    # Create a 2d character array 
    a = [[" " for x in range(l)] for y in range(l)]  
  
    # for counting the  
    # rows of the ZigZag 
    row = 0
    for i in range(l): 
          
        # put characters in the matrix 
        a[row][i] = s[i];  
      
        # You have reached the bottom 
        if row == n - 1: 
            down = False    
        elif row == 0: 
            down = True
        if down == True: 
            row = row + 1
        else: 
            row = row - 1
  
    # Print the Zig-Zag String 
    for i in range(n): 
        for j in range(l): 
            print(str(a[i][j]), end = " ") 
        print() 
      
# Driver Code 
s = "GeeksforGeeks"
n = 3
fun(s, n) 
  
# This code is contributed  
# by ChitraNayal 

C#

// C# program to print wave  
// pattern of a given string 
using System; 
  
class GFG  
{ 
  
    // Function that takes  
    // string and zigzag offset 
    static void fun(string s, int n)  
    { 
          
    // if offset is 1 
    if (n == 1)              
    { 
        // simply print the  
        // string and return 
        Console.Write(s);              
        return; 
    } 
  
    // Get length of the string 
    int len = s.Length;  
      
    // Create a 2d character array 
    char[,] a = new char[len,len]; 
    char[] c = s.ToCharArray(); 
      
    // for counting the 
    // rows of the ZigZag 
    int row = 0;          
    bool down = true; 
      
    for (int i = 0; i < len; i++) 
    { 
        // put characters  
        // in the matrix 
        a[row, i] = c[i];  
          
        // You have reached the bottom 
        if (row == n - 1) 
            down = false;      
        else if (row == 0) 
            down = true;  
              
        if(down) 
            row++; 
        else
            row--; 
    } 
      
    // Print the Zig-Zag String 
    for (int i = 0; i < n; i++) 
    {  
        for (int j = 0; j < len; j++) 
        { 
            Console.Write(a[i, j] + " "); 
        } 
        Console.Write("\n"); 
    } 
    } 
      
    // Driver Code 
    public static void Main()  
    { 
        string s = "GeeksforGeeks"; 
        int n = 3; 
        fun(s, n); 
    } 
} 
  
// This code is contributed 
// by ChitraNayal 

PHP

<?php 
// php program to print wave  
// pattern of a given string 
  
// Function that takes string 
// and zigzag offset 
function fun($s, $n)  
{ 
      
    // if offset is 1 
    if ($n == 1)      
    { 
          
        // simply print the  
        // strin and return 
        echo $s;          
        return; 
    } 
  
    // Get length of the string 
    $len = strlen($s);  
      
    // for counting the rows  
    // of the ZigZag 
    $row = 0;      
    $down; 
      
    for ($i = 0; $i < $len; $i++) 
        for ($j = 0; $j < $len; $j++) 
        $a[$i][$j]=" "; 
      
    for ($i = 0; $i < $len; $i++) 
    { 
          
        // put characters 
        // in the matrix 
        $a[$row][$i] = $s[$i];  
          
        // You have reached  
        // the bottom 
        if ($row == $n - 1) 
            $down = false;  
        else if ($row == 0) 
            $down = true; 
              
        ($down)? ($row++): ($row--); 
    } 
      
    // Print the Zig-Zag String 
    for ($i = 0; $i < $n; $i++) 
    {  
        for ($j = 0; $j < $len; $j++) 
        { 
            echo $a[$i][$j]." "; 
        } 
        echo "\n"; 
    } 
} 
  
    // Driver code 
    $s = "GeeksforGeeks"; 
    $n = 3; 
    fun($s, $n); 
  
//This code is contributed by mits  
?> 

Output:

G       s       G       s 
  e   k   f   r   e   k   
    e       o       e

This article is contributed by Nikhil Rawat. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

My Personal Notes

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

C++

Java

Python 3

C#

PHP

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