Print a String in wave pattern

Given a string, you need to transform this string in the form of a wave pattern

Examples:

Input : GeeksforGeeks, 2
Output :
G  e  s  o  G  e  s 
 e  k  f  r  e  k  

Input : GeeksforGeeks, 4
Output :
G      o      s 
 e    f  r    k  
  e  s    G  e   
   k      e

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

C++

// CPP program to print wave pattern  
// of a given string 
// This is a modified code of 
// https://www.geeksforgeeks.org/print-concatenation-of-zig-zag-string-form-in-n-rows/ 
  
#include<bits/stdc++.h> 
using namespace std; 
  
// Function that takes string and zigzag offset 
void fun(string s, int n)  
{ 
    // if offset is 1 
    if (n==1)              
    { 
        // simply print the strin and return 
        cout << s;              
        return; 
    } 
  
    // Get length of the string 
    int len = s.length();  
      
    // Create a 2d character array 
    char a[len][len] = { }; 
      
    // for counting the rows of the ZigZag 
    int row = 0;          
    bool down; 
      
    for (int i=0; i<len; i++) 
    { 
        // put characters in the matrix 
        a[row][i] = s[i];  
          
        // You have reached the bottom 
        if (row==n-1) 
            down = false;      
        else if (row==0) 
            down = true;     
              
        (down)?(row++):(row--); 
    } 
      
    // Print the Zig-Zag String 
    for (int i=0; i<n; i++) 
    {  
        for (int j=0; j<len; j++) 
        { 
            cout<<a[i][j]<<" "; 
        } 
        cout<<endl; 
    } 
} 
  
// Driver function 
int main() 
{ 
    string s = "GeeksforGeeks"; 
    int n = 3; 
    fun(s, n); 
} 

Java

// Java program to print wave   
// pattern of a given string 
import java.lang.*; 
import java.util.*; 
class GFG  
{ 
  
    // Function that takes  
    // string and zigzag offset 
    static void fun(String s, int n)  
    { 
          
    // if offset is 1 
    if (n == 1)              
    { 
        // simply print the 
        // strin and return 
        System.out.print(s);              
        return; 
    } 
  
    // Get length of the string 
    int len = s.length();  
      
    // Create a 2d character array 
    char [][]a = new char[len][len]; 
    char []c = s.toCharArray(); 
      
    // for counting the  
    // rows of the ZigZag 
    int row = 0;          
    boolean down = true; 
      
    for (int i = 0; i < len; i++) 
    { 
        // put characters in 
        // the matrix 
        a[row][i] = c[i];  
          
        // You have reached 
        // the bottom 
        if (row == n - 1) 
            down = false;      
        else if (row == 0) 
            down = true;  
              
        if(down) 
            row++; 
        else
            row--; 
    } 
      
    // Print the Zig-Zag String 
    for (int i = 0; i < n; i++) 
    {  
        for (int j = 0; j < len; j++) 
        { 
            System.out.print(a[i][j] + " "); 
        } 
        System.out.println(); 
    } 
    } 
      
    // Driver Code 
    public static void main(String[] args) 
    { 
        String s = "GeeksforGeeks"; 
        int n = 3; 
        fun(s, n); 
    } 
} 
  
// This code is contributed  
// by ChitraNayal 

Python 3

# Function that takes string 
# and zigzag offset 
def fun(s, n): 
      
    # if offset is 1 
    if (n == 1): 
          
        # simply print the 
        # string and return 
        print(s)              
        return
  
    # Get length of the string 
    l = len(s) 
      
    # Create a 2d character array 
    a = [[" " for x in range(l)] for y in range(l)]  
  
    # for counting the  
    # rows of the ZigZag 
    row = 0
    for i in range(l): 
          
        # put characters in the matrix 
        a[row][i] = s[i];  
      
        # You have reached the bottom 
        if row == n - 1: 
            down = False    
        elif row == 0: 
            down = True
        if down == True: 
            row = row + 1
        else: 
            row = row - 1
  
    # Print the Zig-Zag String 
    for i in range(n): 
        for j in range(l): 
            print(str(a[i][j]), end = " ") 
        print() 
      
# Driver Code 
s = "GeeksforGeeks"
n = 3
fun(s, n) 
  
# This code is contributed  
# by ChitraNayal 

C#

// C# program to print wave  
// pattern of a given string 
using System; 
  
class GFG  
{ 
  
    // Function that takes  
    // string and zigzag offset 
    static void fun(string s, int n)  
    { 
          
    // if offset is 1 
    if (n == 1)              
    { 
        // simply print the  
        // string and return 
        Console.Write(s);              
        return; 
    } 
  
    // Get length of the string 
    int len = s.Length;  
      
    // Create a 2d character array 
    char[,] a = new char[len,len]; 
    char[] c = s.ToCharArray(); 
      
    // for counting the 
    // rows of the ZigZag 
    int row = 0;          
    bool down = true; 
      
    for (int i = 0; i < len; i++) 
    { 
        // put characters  
        // in the matrix 
        a[row, i] = c[i];  
          
        // You have reached the bottom 
        if (row == n - 1) 
            down = false;      
        else if (row == 0) 
            down = true;  
              
        if(down) 
            row++; 
        else
            row--; 
    } 
      
    // Print the Zig-Zag String 
    for (int i = 0; i < n; i++) 
    {  
        for (int j = 0; j < len; j++) 
        { 
            Console.Write(a[i, j] + " "); 
        } 
        Console.Write("\n"); 
    } 
    } 
      
    // Driver Code 
    public static void Main()  
    { 
        string s = "GeeksforGeeks"; 
        int n = 3; 
        fun(s, n); 
    } 
} 
  
// This code is contributed 
// by ChitraNayal 

PHP

<?php 
// php program to print wave  
// pattern of a given string 
  
// Function that takes string 
// and zigzag offset 
function fun($s, $n)  
{ 
      
    // if offset is 1 
    if ($n == 1)      
    { 
          
        // simply print the  
        // strin and return 
        echo $s;          
        return; 
    } 
  
    // Get length of the string 
    $len = strlen($s);  
      
    // for counting the rows  
    // of the ZigZag 
    $row = 0;      
    $down; 
      
    for ($i = 0; $i < $len; $i++) 
        for ($j = 0; $j < $len; $j++) 
        $a[$i][$j]=" "; 
      
    for ($i = 0; $i < $len; $i++) 
    { 
          
        // put characters 
        // in the matrix 
        $a[$row][$i] = $s[$i];  
          
        // You have reached  
        // the bottom 
        if ($row == $n - 1) 
            $down = false;  
        else if ($row == 0) 
            $down = true; 
              
        ($down)? ($row++): ($row--); 
    } 
      
    // Print the Zig-Zag String 
    for ($i = 0; $i < $n; $i++) 
    {  
        for ($j = 0; $j < $len; $j++) 
        { 
            echo $a[$i][$j]." "; 
        } 
        echo "\n"; 
    } 
} 
  
    // Driver code 
    $s = "GeeksforGeeks"; 
    $n = 3; 
    fun($s, $n); 
  
//This code is contributed by mits  
?> 

Output:

G       s       G       s 
  e   k   f   r   e   k   
    e       o       e

This article is contributed by Nikhil Rawat. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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Recommended: Please try your approach on {IDE} first, before moving on to the solution.

C++

Java

Python 3

C#

PHP

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