Given a string of both uppercase and lowercase alphabets, the task is to print the string with alternate occurrences of any character dropped(including space and consider upper and lowercase as same).
Examples:
Input : It is a long day Dear. Output : It sa longdy ear. Print first I and then ignore next i. Similarly print first space then ignore next space. Input : Geeks for geeks Output : Geks fore
Asked in: Microsoft
As we have to print characters in alternate manner, so start traversing the string and perform following two steps:-
- Increment the count of occurrence of current character in a hash table.
- Check if the count becomes odd, then print the current character, else not.
C/C++
// C++ program to print the string in given pattern #include <bits/stdc++.h> using namespace std; // Function to print the string void printStringAlternate(string str) { unordered_map< char , int > occ; // Start traversing the string for ( int i = 0; i < str.length(); i++) { // Convert uppercase to lowercase char temp = tolower (str[i]); // Increment occurrence count occ[temp]++; // If count is odd then print the character if (occ[temp] & 1) cout << str[i]; } cout << endl; } // Drivers code int main() { string str = "Geeks for geeks" ; string str2 = "It is a long day Dear" ; printStringAlternate(str); printStringAlternate(str2); return 0; } |
Java
// Java program to print the string in given pattern import java.io.*; class GFG { // Function to print the string static void printStringAlternate(String str) { int [] occ = new int [ 122 ]; // Convert uppercase to lowercase String s = str.toLowerCase(); // Start traversing the string for ( int i = 0 ; i < str.length(); i++) { char temp = s.charAt(i); // Increment occurrence count occ[temp]++; // If count is odd then print the character if (occ[temp]% 2 != 0 ) System.out.print(str.charAt(i)); } System.out.println(); } // driver program public static void main (String[] args) { String str1 = "Geeks for geeks" ; String str2 = "It is a long day Dear" ; printStringAlternate(str1); printStringAlternate(str2); } } // Contributed by Pramod Kumar |
Python3
# Python3 program to print the string # in given pattern # Function to print the string def printStringAlternate(string): occ = {} # Start traversing the string for i in range ( 0 , len (string)): # Convert uppercase to lowercase temp = string[i].lower() # Increment occurrence count occ[temp] = occ.get(temp, 0 ) + 1 # If count is odd then print the character if occ[temp] & 1 : print (string[i], end = "") print () # Driver code if __name__ = = "__main__" : string = "Geeks for geeks" string2 = "It is a long day Dear" printStringAlternate(string) printStringAlternate(string2) # This code is contributed by Rituraj Jain |
C#
// C# program to print the // string in given pattern using System; public class GFG { // Function to print the string static void printStringAlternate(String str) { int [] occ = new int [122]; // Convert uppercase to lowercase string s = str.ToLower(); // Start traversing the string for ( int i = 0; i < str.Length; i++) { char temp = s[i]; // Increment occurrence count occ[temp]++; // If count is odd then print // the character if (occ[temp] % 2 != 0) Console.Write(str[i]); } Console.WriteLine(); } // Driver Code public static void Main () { string str1 = "Geeks for geeks" ; string str2 = "It is a long day Dear" ; printStringAlternate(str1); printStringAlternate(str2); } } // This code is contributed by Sam007. |
PHP
<?php // PHP program to print the string // in given pattern // Function to print the string function printStringAlternate( $str ) { $occ = array (); // Convert uppercase to lowercase $s = strtolower ( $str ); // Start traversing the string for ( $i = 0; $i < strlen ( $str ); $i ++) { $temp = $s [ $i ]; // Increment occurrence count $occ [( $temp )]++; // If count is odd // then print the character if ( $occ [ $temp ] % 2 != 0) echo ( $str [ $i ]); } echo "\n" ; } // Driver Code $str1 = "Geeks for geeks" ; $str2 = "It is a long day Dear" ; printStringAlternate( $str1 ); printStringAlternate( $str2 ); // This code is contributed by Code_Mech. ?> |
Output:
Geks fore It sa longdy ear
This article is contributed by Sahil Chhabra. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.