# Print sorted distinct elements of array

Given an array that might contain duplicates, print all distinct elements in sorted order.

Examples:

```Input  : 1, 3, 2, 2, 1
Output : 1 2 3

Input  : 1, 1, 1, 2, 2, 3
Output : 1 2 3
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Simple Solution is to sort the array first, then traverse the array and print only first occurrences of elements.

Another Approach is to use set in C++ STL.

## C++

 `// CPP program to print sorted distinct ` `// elements. ` `#include ` `using` `namespace` `std; ` ` `  `void` `printRepeating(``int` `arr[], ``int` `size) ` `{ ` `    ``// Create a set using array elements ` `    ``set<``int``> s(arr, arr + size); ` ` `  `    ``// Print contents of the set. ` `    ``for` `(``auto` `x : s)  ` `        ``cout << x << ``" "``; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `arr[] = { 1, 3, 2, 2, 1 }; ` `    ``int` `n = ``sizeof``(arr) / ``sizeof``(arr); ` `    ``printRepeating(arr, n); ` `    ``return` `0; ` `} `

## Java

 `// Java program to print sorted distinct ` `// elements. ` `import` `java.io.*; ` `import` `java.util.*; ` ` `  `public` `class` `GFG { ` `      `  `    ``static` `void` `printRepeating(Integer []arr, ``int` `size) ` `    ``{ ` `        ``// Create a set using array elements ` `        ``SortedSet s = ``new` `TreeSet<>(); ` `        ``Collections.addAll(s, arr); ` `         `  `        ``// Print contents of the set. ` `        ``System.out.print(s); ` `    ``} ` `      `  `    ``// Driver code ` `    ``public` `static` `void` `main(String args[]) ` `    ``{ ` `        ``Integer []arr = {``1``, ``3``, ``2``, ``2``, ``1``}; ` `        ``int` `n = arr.length; ` `        ``printRepeating(arr, n); ` `    ``} ` `} ` `  `  `// This code is contributed by ` `// Manish Shaw (manishshaw1) `

## Python3

 `# Python3 program to print  ` `# sorted distinct elements. ` ` `  `def` `printRepeating(arr,size): ` ` `  `    ``# Create a set using array elements  ` `    ``s ``=` `set``() ` `    ``for` `i ``in` `range``(size): ` `        ``if` `arr[i] ``not` `in` `s: ` `            ``s.add(arr[i]) ` ` `  `    ``# Print contents of the set. ` `    ``for` `i ``in` `s: ` `        ``print``(i,end``=``" "``) ` ` `  `# Driver code ` `if` `__name__``=``=``'__main__'``: ` `    ``arr ``=` `[``1``,``3``,``2``,``2``,``1``] ` `    ``size ``=` `len``(arr) ` `    ``printRepeating(arr,size) ` ` `  `# This code is contributed by  ` `# Shrikant13 `

## C#

 `// C# program to print sorted distinct ` `// elements. ` `using` `System; ` `using` `System.Collections.Generic; ` `using` `System.Linq; ` ` `  `class` `GFG { ` `     `  `    ``static` `void` `printRepeating(``int` `[]arr, ``int` `size) ` `    ``{ ` `        ``// Create a set using array elements ` `        ``SortedSet<``int``> s = ``new` `SortedSet<``int``>(arr); ` `     `  `        ``// Print contents of the set. ` `        ``foreach` `(``var` `n ``in` `s) ` `        ``{ ` `            ``Console.Write(n + ``" "``); ` `        ``}  ` `    ``} ` `     `  `    ``// Driver code ` `    ``public` `static` `void` `Main() ` `    ``{ ` `        ``int` `[]arr = {1, 3, 2, 2, 1}; ` `        ``int` `n = arr.Length; ` `        ``printRepeating(arr, n); ` `    ``} ` `} ` ` `  `// This code is contributed by ` `// Manish Shaw (manishshaw1) `

Output:

```1 2 3
```

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