# Print all paths from a given source to a destination using BFS

Given a directed graph, a source vertex ‘src’ and a destination vertex ‘dst’, print all paths from given ‘src’ to ‘dst’.

Consider the following directed graph. Let the src be 2 and dst be 3. There are 3 different paths from 2 to 3.

We have already discussed Print all paths from a given source to a destination using DFS.

Below is BFS based solution.

**Algorithm :**

create a queue which will store path(s) of type vector initialise the queue with first path starting from src Now run a loop till queue is not empty get the frontmost path from queue check if the lastnode of this path is destination if true then print the path run a loop for all the vertices connected to the current vertex i.e. lastnode extracted from path if the vertex is not visited in current path a) create a new path from earlier path and append this vertex b) insert this new path to queue

`// CPP program to print all paths of source to ` `// destination in given graph ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// utility function for printing ` `// the found path in graph ` `void` `printpath(vector<` `int` `>& path) ` `{ ` ` ` `int` `size = path.size(); ` ` ` `for` `(` `int` `i = 0; i < size; i++) ` ` ` `cout << path[i] << ` `" "` `; ` ` ` `cout << endl; ` `} ` ` ` `// utility function to check if current ` `// vertex is already present in path ` `int` `isNotVisited(` `int` `x, vector<` `int` `>& path) ` `{ ` ` ` `int` `size = path.size(); ` ` ` `for` `(` `int` `i = 0; i < size; i++) ` ` ` `if` `(path[i] == x) ` ` ` `return` `0; ` ` ` `return` `1; ` `} ` ` ` `// utility function for finding paths in graph ` `// from source to destination ` `void` `findpaths(vector<vector<` `int` `> >&g, ` `int` `src, ` ` ` `int` `dst, ` `int` `v) ` `{ ` ` ` `// create a queue which stores ` ` ` `// the paths ` ` ` `queue<vector<` `int` `> > q; ` ` ` ` ` `// path vector to store the current path ` ` ` `vector<` `int` `> path; ` ` ` `path.push_back(src); ` ` ` `q.push(path); ` ` ` `while` `(!q.empty()) { ` ` ` `path = q.front(); ` ` ` `q.pop(); ` ` ` `int` `last = path[path.size() - 1]; ` ` ` ` ` `// if last vertex is the desired destination ` ` ` `// then print the path ` ` ` `if` `(last == dst) ` ` ` `printpath(path); ` ` ` ` ` `// traverse to all the nodes connected to ` ` ` `// current vertex and push new path to queue ` ` ` `for` `(` `int` `i = 0; i < g[last].size(); i++) { ` ` ` `if` `(isNotVisited(g[last][i], path)) { ` ` ` `vector<` `int` `> newpath(path); ` ` ` `newpath.push_back(g[last][i]); ` ` ` `q.push(newpath); ` ` ` `} ` ` ` `} ` ` ` `} ` `} ` ` ` `// driver program ` `int` `main() ` `{ ` ` ` `vector<vector<` `int` `> > g; ` ` ` `// number of vertices ` ` ` `int` `v = 4; ` ` ` `g.resize(4); ` ` ` ` ` `// construct a graph ` ` ` `g[0].push_back(3); ` ` ` `g[0].push_back(1); ` ` ` `g[0].push_back(2); ` ` ` `g[1].push_back(3); ` ` ` `g[2].push_back(0); ` ` ` `g[2].push_back(1); ` ` ` ` ` `int` `src = 2, dst = 3; ` ` ` `cout << ` `"path from src "` `<< src ` ` ` `<< ` `" to dst "` `<< dst << ` `" are \n"` `; ` ` ` ` ` `// function for finding the paths ` ` ` `findpaths(g, src, dst, v); ` ` ` ` ` `return` `0; ` `} ` |

*chevron_right*

*filter_none*

Output:

path from src 2 to dst 3 are 2 0 3 2 1 3 2 0 1 3

This article is contributed by **Mandeep Singh**. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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