Print a matrix in a spiral form starting from a point

Given a matrix of size n*m, and a point P(c, r). Print the matrix in a spiral form(clockwise) starting from the point P.

Examples :

Input : mat[][] = {{1 2 3},
{4 5 6},
{7 8 9}}
Point P = (0, 2)
Output : 3 6 5 2 9 8 7 4 1
The starting point is top left which
is 3.

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

This problem is mainly an extension of print a matrix in spiral form.

C++

 // C++ program to print a matrix in spiral // form. #include using namespace std;    const int MAX = 100;    void printSpiral(int mat[][MAX], int r, int c) {        int i, a = 0, b = 2;        int low_row = (0 > a) ? 0 : a;     int low_column = (0 > b) ? 0 : b - 1;     int high_row = ((a + 1) >= r) ? r - 1 : a + 1;     int high_column = ((b + 1) >= c) ? c - 1 : b + 1;        while ((low_row > 0 - r && low_column > 0 - c)) {            for (i = low_column + 1; i <= high_column &&                           i < c && low_row >= 0; ++i)             cout << mat[low_row][i] << " ";         low_row -= 1;            for (i = low_row + 2; i <= high_row && i < r &&                                     high_column < c; ++i)             cout << mat[i][high_column] << " ";         high_column += 1;            for (i = high_column - 2; i >= low_column &&                                i >= 0 && high_row < r; --i)             cout << mat[high_row][i] << " ";         high_row += 1;            for (i = high_row - 2; i > low_row && i >= 0                                     && low_column >= 0; --i)             cout << mat[i][low_column] << " ";         low_column -= 1;     }     cout << endl; }    // Driver code int main() {     int mat[][MAX] = { { 1, 2, 3 }, { 4, 5, 6 }, { 7, 8, 9 } };     int r = 3, c = 3;        printSpiral(mat, r, c); }

Java

 // Java program to print a // matrix in spiral form import java.io.*;    class GFG {     static void printSpiral(int [][]mat, int r, int c) {     int i, a = 0, b = 2;        int low_row = (0 > a) ? 0 : a;     int low_column = (0 > b) ? 0 : b - 1;     int high_row = ((a + 1) >= r) ? r - 1 : a + 1;     int high_column = ((b + 1) >= c) ? c - 1 : b + 1;        while ((low_row > 0 - r && low_column > 0 - c))      {         for (i = low_column + 1; i <= high_column &&                           i < c && low_row >= 0; ++i)             System.out.print (mat[low_row][i] + " ");         low_row -= 1;            for (i = low_row + 2; i <= high_row && i < r &&                                    high_column < c; ++i)             System.out.print(mat[i][high_column] + " ");         high_column += 1;            for (i = high_column - 2; i >= low_column &&                         i >= 0 && high_row < r; --i)             System.out.print(mat[high_row][i] + " ");         high_row += 1;            for (i = high_row - 2; i > low_row && i >= 0                             && low_column >= 0; --i)             System.out.print(mat[i][low_column] +" ");         low_column -= 1;     }     System.out.println(); }    // Driver code     static public void main (String[] args)     {         int [][]mat = {{1, 2, 3},                        {4, 5, 6},                         {7, 8, 9}};         int r = 3, c = 3;            // Function calling         printSpiral(mat, r, c);     } }    // This code is contributed by vt_m.

Python 3

 # Python3 program to print a matrix  # in spiral form. MAX = 100    def printSpiral(mat, r, c):        a = 0     b = 2        low_row = 0 if (0 > a) else a     low_column = 0 if (0 > b) else b - 1     high_row = r-1 if ((a + 1) >= r) else a + 1     high_column = c-1 if ((b + 1) >= c) else b + 1        while ((low_row > 0 - r and low_column > 0 - c)):            i = low_column + 1         while (i <= high_column and                 i < c and low_row >= 0):             print( mat[low_row][i], end = " ")             i += 1         low_row -= 1            i = low_row + 2         while (i <= high_row and                i < r and high_column < c):             print(mat[i][high_column], end = " ")             i += 1         high_column += 1            i = high_column - 2         while (i >= low_column and                 i >= 0 and high_row < r):             print(mat[high_row][i], end = " ")             i -= 1         high_row += 1            i = high_row - 2         while (i > low_row and                 i >= 0 and low_column >= 0):             print(mat[i][low_column], end = " ")             i -= 1         low_column -= 1            print()    # Driver code if __name__ == "__main__":            mat = [[ 1, 2, 3 ],             [ 4, 5, 6 ],             [ 7, 8, 9 ]]     r = 3     c = 3     printSpiral(mat, r, c)    # This code is contributed by ita_c

C#

 // C# program to print a  // matrix in spiral form using System;    class GFG {    static void printSpiral(int [,]mat, int r, int c) {     int i, a = 0, b = 2;        int low_row = (0 > a) ? 0 : a;     int low_column = (0 > b) ? 0 : b - 1;     int high_row = ((a + 1) >= r) ? r - 1 : a + 1;     int high_column = ((b + 1) >= c) ? c - 1 : b + 1;        while ((low_row > 0 - r && low_column > 0 - c))     {         for (i = low_column + 1; i <= high_column &&                           i < c && low_row >= 0; ++i)             Console.Write (mat[low_row,i] + " ");         low_row -= 1;            for (i = low_row + 2; i <= high_row && i < r &&                                    high_column < c; ++i)             Console.Write(mat[i,high_column] + " ");         high_column += 1;            for (i = high_column - 2; i >= low_column &&                         i >= 0 && high_row < r; --i)             Console.Write(mat[high_row,i] + " ");         high_row += 1;            for (i = high_row - 2; i > low_row && i >= 0                              && low_column >= 0; --i)             Console.Write(mat[i,low_column] +" ");         low_column -= 1;     }     Console.WriteLine(); }        // Driver code     static public void Main ()     {         int [,]mat = {{1, 2, 3},                       {4, 5, 6},                        {7, 8, 9}};         int r = 3, c = 3;            // Function calling         printSpiral(mat, r, c);     } }    // This code is contributed by vt_m.

PHP

 \$a) ?                  0 : \$a;     \$low_column = (0 > \$b) ?                     0 : \$b - 1;     \$high_row = ((\$a + 1) >= \$r) ?                    \$r - 1 : \$a + 1;     \$high_column = ((\$b + 1) >= \$c) ?                       \$c - 1 : \$b + 1;        while ((\$low_row > 0 - \$r &&              \$low_column > 0 - \$c))     {            for (\$i = \$low_column + 1;               \$i <= \$high_column &&               \$i < \$c && \$low_row >= 0; ++\$i)             echo \$mat[\$low_row][\$i], " ";         \$low_row -= 1;            for (\$i = \$low_row + 2;               \$i <= \$high_row && \$i < \$r &&               \$high_column < \$c; ++\$i)         echo \$mat[\$i][\$high_column] , " ";         \$high_column += 1;            for (\$i = \$high_column - 2;               \$i >= \$low_column &&              \$i >= 0 && \$high_row < \$r; --\$i)             echo \$mat[\$high_row][\$i] , " ";         \$high_row += 1;            for (\$i = \$high_row - 2;               \$i > \$low_row && \$i >= 0 &&               \$low_column >= 0; --\$i)             echo \$mat[\$i][\$low_column] , " ";         \$low_column -= 1;     }     echo "\n"; }    // Driver code \$mat = array(array(1, 2, 3),              array(4, 5, 6),              array(7, 8, 9)); \$r = 3; \$c = 3;    printSpiral(\$mat, \$r, \$c);    // This code is contributed by aj_36 ?>

Output:

3 6 5 2 9 8 7 4 1

This article is contributed by Harsh Khatore. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

My Personal Notes arrow_drop_up

Improved By : vt_m, jit_t, chitranayal

Article Tags :
Practice Tags :

Be the First to upvote.

Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.