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# Print all full nodes in a Binary Tree

Given a binary tree, print all nodes will are full nodes. Full Nodes are nodes which has both left and right children as non-empty.

Examples:

```Input :    10
/  \
8    2
/ \   /
3   5 7
Output : 10 8

Input :   1
/ \
2   3
/ \
4   6
Output : 1 3```

This is a simple problem. We do any of the tra­ver­sals (Inorder, Pre­order, Pos­torder, level order traversal) and keep printing nodes that have mode left and right children as non-NULL.

Implementation:

## C++

 `// A C++ program to find the all full nodes in``// a given binary tree``#include ``using` `namespace` `std;`` ` `struct` `Node``{``    ``int` `data;``    ``struct` `Node *left, *right;``};`` ` `Node *newNode(``int` `data)``{``    ``Node *temp = ``new` `Node;``    ``temp->data = data;``    ``temp->left = temp->right = NULL;``    ``return` `temp;``}`` ` `// Traverses given tree in Inorder fashion and``// prints all nodes that have both children as``// non-empty.``void` `findFullNode(Node *root)``{``    ``if` `(root != NULL)``    ``{``        ``findFullNode(root->left);``        ``if` `(root->left != NULL && root->right != NULL)``            ``cout << root->data << ``" "``;``        ``findFullNode(root->right);``    ``}``}`` ` `// Driver program to test above function``int` `main()``{``    ``Node* root = newNode(1);``    ``root->left = newNode(2);``    ``root->right = newNode(3);``    ``root->left->left = newNode(4);``    ``root->right->left = newNode(5);``    ``root->right->right = newNode(6);``    ``root->right->left->right = newNode(7);``    ``root->right->right->right = newNode(8);``    ``root->right->left->right->left = newNode(9);``    ``findFullNode(root);``    ``return` `0;``}`

## Java

 `// Java program to find the all full nodes in ``// a given binary tree ``public` `class` `FullNodes {`` ` `    ``// Traverses given tree in Inorder fashion and ``    ``// prints all nodes that have both children as ``    ``// non-empty. ``    ``public` `static` `void` `findFullNode(Node root) ``    ``{ ``        ``if` `(root != ``null``) ``        ``{ ``            ``findFullNode(root.left); ``            ``if` `(root.left != ``null` `&& root.right != ``null``) ``                ``System.out.print(root.data+``" "``);``            ``findFullNode(root.right); ``        ``} ``    ``} `` ` `    ``public` `static` `void` `main(String args[]) {``        ``Node root = ``new` `Node(``1``); ``        ``root.left = ``new` `Node(``2``); ``        ``root.right = ``new` `Node(``3``); ``        ``root.left.left = ``new` `Node(``4``); ``        ``root.right.left = ``new` `Node(``5``); ``        ``root.right.right = ``new` `Node(``6``); ``        ``root.right.left.right = ``new` `Node(``7``); ``        ``root.right.right.right = ``new` `Node(``8``); ``        ``root.right.left.right.left = ``new` `Node(``9``); ``        ``findFullNode(root); ``    ``}``}`` ` `/* A binary tree node */``class` `Node ``{ ``    ``int` `data; ``    ``Node left, right; ``    ``Node(``int` `data)``    ``{``        ``left=right=``null``;``        ``this``.data=data;``    ``}``}; ``//This code is contributed by Gaurav Tiwari`

## Python3

 `# Python3 program to find the all ``# full nodes in a given binary tree`` ` `# Binary Tree Node ``""" utility that allocates a newNode ``with the given key """``class` `newNode: `` ` `    ``# Construct to create a newNode ``    ``def` `__init__(``self``, key): ``        ``self``.data ``=` `key``        ``self``.left ``=` `None``        ``self``.right ``=` `None`` ` `# Traverses given tree in Inorder ``# fashion and prints all nodes that ``# have both children as non-empty. ``def` `findFullNode(root) :`` ` `    ``if` `(root !``=` `None``) :``     ` `        ``findFullNode(root.left) ``        ``if` `(root.left !``=` `None` `and` `            ``root.right !``=` `None``) :``            ``print``(root.data, end ``=` `" "``) ``        ``findFullNode(root.right) `` ` `# Driver Code ``if` `__name__ ``=``=` `'__main__'``:`` ` `    ``root ``=` `newNode(``1``) ``    ``root.left ``=` `newNode(``2``) ``    ``root.right ``=` `newNode(``3``) ``    ``root.left.left ``=` `newNode(``4``) ``    ``root.right.left ``=` `newNode(``5``) ``    ``root.right.right ``=` `newNode(``6``) ``    ``root.right.left.right ``=` `newNode(``7``) ``    ``root.right.right.right ``=` `newNode(``8``) ``    ``root.right.left.right.left ``=` `newNode(``9``) ``    ``findFullNode(root)`` ` `# This code is contributed by``# Shubham Singh(SHUBHAMSINGH10)`

## C#

 `// C# program to find the all full nodes in ``// a given binary tree ``using` `System;`` ` `public` `class` `FullNodes``{`` ` `    ``// Traverses given tree in Inorder fashion and ``    ``// prints all nodes that have both children as ``    ``// non-empty. ``    ``static` `void` `findFullNode(Node root) ``    ``{ ``        ``if` `(root != ``null``) ``        ``{ ``            ``findFullNode(root.left); ``            ``if` `(root.left != ``null` `&& root.right != ``null``) ``                ``Console.Write(root.data + ``" "``);``            ``findFullNode(root.right); ``        ``} ``    ``} `` ` `    ``public` `static` `void` `Main(String []args) ``    ``{``        ``Node root = ``new` `Node(1); ``        ``root.left = ``new` `Node(2); ``        ``root.right = ``new` `Node(3); ``        ``root.left.left = ``new` `Node(4); ``        ``root.right.left = ``new` `Node(5); ``        ``root.right.right = ``new` `Node(6); ``        ``root.right.left.right = ``new` `Node(7); ``        ``root.right.right.right = ``new` `Node(8); ``        ``root.right.left.right.left = ``new` `Node(9); ``        ``findFullNode(root); ``    ``}``}`` ` `/* A binary tree node */``class` `Node ``{ ``    ``public` `int` `data; ``    ``public` `Node left, right; ``    ``public` `Node(``int` `data)``    ``{``        ``left = right = ``null``;``        ``this``.data = data;``    ``}``};`` ` `// This code is contributed by 29AjayKumar`

## Javascript

 ``

Output

`1 3 `

Time Complexity : O(n)
Space complexity: O(n) for Recursive Stack Space in case of Skewed Tree

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