Print consecutive characters together in a line

Given a sequence of characters, print consecutive sequence of characters in a line, otherwise
print it in a new line.

Examples:

Input  : ABCXYZACCD
Output : ABC
         XYZ
         A
         C
         CD

Input : ABCZYXACCD
Output: ABC
        ZYX
        A
        C
        CD

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

The idea is to traverse string from left to right. For every traversed character, print it in a line if it is consecutive to previous one, else print a new line character.

C++

// C++ program to print consecutive characters 
// together in a line. 
#include <iostream> 
using namespace std; 
  
void print(string str) 
{ 
    cout << str[0]; 
    for (int i=1; str[i]!='\0'; i++) 
    { 
        if ((str[i] == str[i-1]+1) || 
            (str[i] == str[i-1]-1)) 
            cout << str[i]; 
        else
            cout << "\n" << str[i];; 
    } 
} 
  
// Driver code 
int main() 
{ 
    string str = "ABCXYZACCD"; 
    print(str); 
    return 0; 
} 

Java

// Java program to print consecutive characters 
// together in a line. 
class GFG { 
  
    static void print(String str1) { 
        char str[] = str1.toCharArray(); 
        System.out.print(str[0]); 
        for (int i = 1; i < str.length; i++) { 
            if ((str[i] == str[i - 1] + 1) 
                    || (str[i] == str[i - 1] - 1)) { 
                System.out.print(str[i]); 
            } else { 
                System.out.print("\n" + str[i]); 
            } 
        } 
    } 
  
// Driver code 
    public static void main(String[] args) { 
        String str = "ABCXYZACCD"; 
        print(str); 
    } 
}  
  
// This code is contributed by 29AjayKumar 

Python3

# Python3 program to print consecutive characters  
# together in a line. 
def _print(string): 
    print(string[0], end = "") 
  
    for i in range(1, len(string)): 
        if (ord(string[i]) == ord(string[i - 1]) + 1 or 
            ord(string[i]) == ord(string[i - 1]) - 1): 
            print(string[i], end = "") 
        else: 
            print() 
            print(string[i], end = "") 
  
# Driver Code 
if __name__ == "__main__": 
  
    string = "ABCXYZACCD"
    _print(string) 
  
# This code is contributed by 
# sanjeev2552 

C#

// C# program to print consecutive characters 
// together in a line. 
using System; 
  
class GFG  
{ 
  
    static void print(String str1)  
    { 
        char []str = str1.ToCharArray(); 
        Console.Write(str[0]); 
        for (int i = 1; i < str.Length; i++)  
        { 
            if ((str[i] == str[i - 1] + 1) 
                    || (str[i] == str[i - 1] - 1)) 
            { 
                Console.Write(str[i]); 
            }  
            else
            { 
                Console.Write("\n" + str[i]); 
            } 
        } 
    } 
  
    // Driver code 
    public static void Main()  
    { 
        String str = "ABCXYZACCD"; 
        print(str); 
    } 
} 
  
// This code is contributed by PrinciRaj1992 

Output:

ABC
XYZ
A
C
CD

Time Complexity : O(n)
This article is contributed by Rakesh Kumar. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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My Personal Notes

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

C++

Java

Python3

C#

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