Print consecutive characters together in a line

Given a sequence of characters, print consecutive sequence of characters in a line, otherwise
print it in a new line.

Examples:

Input  : ABCXYZACCD
Output : ABC
         XYZ
         A
         C
         CD

Input : ABCZYXACCD
Output: ABC
        ZYX
        A
        C
        CD



The idea is to traverse string from left to right. For every traversed character, print it in a line if it is consecutive to previous one, else print a new line character.

C++

filter_none

edit
close

play_arrow

link
brightness_4
code

// C++ program to print consecutive characters
// together in a line.
#include <iostream>
using namespace std;
  
void print(string str)
{
    cout << str[0];
    for (int i=1; str[i]!='\0'; i++)
    {
        if ((str[i] == str[i-1]+1) ||
            (str[i] == str[i-1]-1))
            cout << str[i];
        else
            cout << "\n" << str[i];;
    }
}
  
// Driver code
int main()
{
    string str = "ABCXYZACCD";
    print(str);
    return 0;
}

chevron_right


Java

filter_none

edit
close

play_arrow

link
brightness_4
code

// Java program to print consecutive characters
// together in a line.
class GFG {
  
    static void print(String str1) {
        char str[] = str1.toCharArray();
        System.out.print(str[0]);
        for (int i = 1; i < str.length; i++) {
            if ((str[i] == str[i - 1] + 1)
                    || (str[i] == str[i - 1] - 1)) {
                System.out.print(str[i]);
            } else {
                System.out.print("\n" + str[i]);
            }
        }
    }
  
// Driver code
    public static void main(String[] args) {
        String str = "ABCXYZACCD";
        print(str);
    }
  
// This code is contributed by 29AjayKumar

chevron_right


Python3

filter_none

edit
close

play_arrow

link
brightness_4
code

# Python3 program to print consecutive characters 
# together in a line.
def _print(string):
    print(string[0], end = "")
  
    for i in range(1, len(string)):
        if (ord(string[i]) == ord(string[i - 1]) + 1 or 
            ord(string[i]) == ord(string[i - 1]) - 1):
            print(string[i], end = "")
        else:
            print()
            print(string[i], end = "")
  
# Driver Code
if __name__ == "__main__":
  
    string = "ABCXYZACCD"
    _print(string)
  
# This code is contributed by
# sanjeev2552

chevron_right


C#

filter_none

edit
close

play_arrow

link
brightness_4
code

// C# program to print consecutive characters
// together in a line.
using System;
  
class GFG 
{
  
    static void print(String str1) 
    {
        char []str = str1.ToCharArray();
        Console.Write(str[0]);
        for (int i = 1; i < str.Length; i++) 
        {
            if ((str[i] == str[i - 1] + 1)
                    || (str[i] == str[i - 1] - 1))
            {
                Console.Write(str[i]);
            
            else
            {
                Console.Write("\n" + str[i]);
            }
        }
    }
  
    // Driver code
    public static void Main() 
    {
        String str = "ABCXYZACCD";
        print(str);
    }
}
  
// This code is contributed by PrinciRaj1992

chevron_right


Output:

ABC
XYZ
A
C
CD

Time Complexity : O(n)
This article is contributed by Rakesh Kumar. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.



My Personal Notes arrow_drop_up



Article Tags :
Practice Tags :


Be the First to upvote.


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.