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Print all root to leaf paths with there relative positions

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Given a binary tree, print the root to the leaf path, but add “_” to indicate the relative position. 

Example: 

Input : Root of below tree
         A 
       /   \  
      B      C 
     / \    / \
    D   E   F  G

Output : All root to leaf paths
_ _ A
_ B
D

_ A
B
_ E

 A
 _ C
 F

A
_ C
_ _ G

Asked In: Google Interview 

The idea base on print path in vertical order
 

vertical_order

Below is complete algorithm : 

  1. We do Preorder traversal of the given Binary Tree. While traversing the tree, we can recursively calculate horizontal distances or HDs. We initially pass the horizontal distance as 0 for root. For left subtree, we pass the Horizontal Distance as Horizontal distance of root minus 1. For right subtree, we pass the Horizontal Distance as Horizontal Distance of root plus 1. For every HD value, we maintain a list of nodes in a vector (” that will store information of current node horizontal distance and key value of root “).we also maintain the order of node (order in which they appear in path from root to leaf). for maintaining the order,here we used vector. 
  2. While we reach to leaf node during traverse we print that path with underscore “_” 

Print_Path_with_underscore function 

print_path

  1. First find the minimum Horizontal distance of the current path. 
  2. After that we traverse current path 
    • First Print number of underscore “_” : abs (current_node_HD – minimum-HD) 
    • Print current node value. 

We do this process for all root to leaf path 

Below is the implementation of the above idea. 

C++




// C++ program to print all root to leaf paths
// with there relative position
#include<bits/stdc++.h>
using namespace std;
 
#define MAX_PATH_SIZE 1000
 
// tree structure
struct Node
{
    char data;
    Node *left, *right;
};
 
// function create new node
Node * newNode(char data)
{
    struct Node *temp = new Node;
    temp->data = data;
    temp->left = temp->right = NULL;
    return temp;
}
 
// store path information
struct PATH
{
    int  Hd; // horizontal distance of node from root.
    char key; // store key
};
 
// Prints given root to leaf path with underscores
void printPath(vector < PATH > path, int size)
{
    // Find the minimum horizontal distance value
    // in current root to leaf path
    int minimum_Hd = INT_MAX;
 
    PATH p;
 
    // find minimum horizontal distance
    for (int it=0; it<size; it++)
    {
        p = path[it];
        minimum_Hd = min(minimum_Hd, p.Hd);
    }
 
    // print the root to leaf path with "_"
    // that indicate the related position
    for (int it=0; it < size; it++)
    {
        // current tree node
        p = path[it];
        int noOfUnderScores = abs(p.Hd - minimum_Hd);
 
        // print underscore
        for (int i = 0; i < noOfUnderScores; i++)
            cout << "_ ";
 
        // print current key
        cout << p.key << endl;
    }
    cout << "==============================" << endl;
}
 
// a utility function print all path from root to leaf
// working of this function is similar to function of
// "Print_vertical_order" : Print paths of binary tree
// in vertical order
void printAllPathsUtil(Node *root,
                       vector < PATH > &AllPath,
                       int HD, int order )
{
    // base case
    if(root == NULL)
        return;
 
    // leaf node
    if (root->left == NULL && root->right == NULL)
    {
        // add leaf node and then print path
        AllPath[order] = (PATH { HD, root->data });
        printPath(AllPath, order+1);
        return;
    }
 
    // store current path information
    AllPath[order] = (PATH { HD, root->data });
 
    // call left sub_tree
    printAllPathsUtil(root->left, AllPath, HD-1, order+1);
 
    //call left sub_tree
    printAllPathsUtil(root->right, AllPath, HD+1, order+1);
}
 
void printAllPaths(Node *root)
{
    // base case
    if (root == NULL)
        return;
 
    vector<PATH> Allpaths(MAX_PATH_SIZE);
    printAllPathsUtil(root, Allpaths, 0, 0);
}
 
// Driver program to test above function
int main()
{
    Node *root = newNode('A');
    root->left = newNode('B');
    root->right = newNode('C');
    root->left->left = newNode('D');
    root->left->right = newNode('E');
    root->right->left = newNode('F');
    root->right->right = newNode('G');
    printAllPaths(root);
    return 0;
}


Java




// Java program to print all root to leaf
// paths with there relative position
import java.util.ArrayList;
 
class Graph{
     
static final int MAX_PATH_SIZE = 1000;
 
// tree structure
static class Node
{
    char data;
    Node left, right;
};
 
// Function create new node
static Node newNode(char data)
{
    Node temp = new Node();
    temp.data = data;
    temp.left = temp.right = null;
    return temp;
}
 
// Store path information
static class PATH
{
     
    // Horizontal distance of node from root.
    int Hd;
     
    // Store key
    char key;
 
    public PATH(int Hd, char key)
    {
        this.Hd = Hd;
        this.key = key;
    }
 
    public PATH()
    {}
};
 
// Prints given root to leaf path with underscores
static void printPath(ArrayList<PATH> path, int size)
{
     
    // Find the minimum horizontal distance value
    // in current root to leaf path
    int minimum_Hd = Integer.MAX_VALUE;
 
    PATH p;
 
    // Find minimum horizontal distance
    for(int it = 0; it < size; it++)
    {
        p = path.get(it);
        minimum_Hd = Math.min(minimum_Hd, p.Hd);
    }
 
    // Print the root to leaf path with "_"
    // that indicate the related position
    for(int it = 0; it < size; it++)
    {
         
        // Current tree node
        p = path.get(it);
        int noOfUnderScores = Math.abs(
            p.Hd - minimum_Hd);
 
        // Print underscore
        for(int i = 0; i < noOfUnderScores; i++)
            System.out.print("_");
 
        // Print current key
        System.out.println(p.key);
    }
    System.out.println("==============================");
}
 
// A utility function print all path from root to leaf
// working of this function is similar to function of
// "Print_vertical_order" : Print paths of binary tree
// in vertical order
static void printAllPathsUtil(Node root,
                              ArrayList<PATH> AllPath,
                              int HD, int order)
{
     
    // Base case
    if (root == null)
        return;
         
    // Leaf node
    if (root.left == null && root.right == null)
    {
         
        // Add leaf node and then print path
        AllPath.set(order, new PATH(HD, root.data));
        // AllPath[order] = (PATH { HD, root.data });
        printPath(AllPath, order + 1);
        return;
    }
     
    // Store current path information
    AllPath.set(order, new PATH(HD, root.data));
    // AllPath[order] = (PATH { HD, root.data });
 
    // Call left sub_tree
    printAllPathsUtil(root.left, AllPath,
                      HD - 1, order + 1);
 
    // Call left sub_tree
    printAllPathsUtil(root.right, AllPath,
                      HD + 1, order + 1);
}
 
static void printAllPaths(Node root)
{
     
    // Base case
    if (root == null)
        return;
 
    ArrayList<PATH> Allpaths = new ArrayList<>();
    for(int i = 0; i < MAX_PATH_SIZE; i++)
    {
        Allpaths.add(new PATH());
    }
    printAllPathsUtil(root, Allpaths, 0, 0);
}
 
// Driver code
public static void main(String[] args)
{
    Node root = newNode('A');
    root.left = newNode('B');
    root.right = newNode('C');
    root.left.left = newNode('D');
    root.left.right = newNode('E');
    root.right.left = newNode('F');
    root.right.right = newNode('G');
     
    printAllPaths(root);
}
}
 
// This code is contributed by sanjeev2552


Python3




# Python3 program to print the longest
# leaf to leaf path
 
# Tree node structure used in the program
MAX_PATH_SIZE = 1000
 
class Node:
     
    def __init__(self, x):
        self.data = x
        self.left = None
        self.right = None
 
# Prints given root to leafAllpaths
# with underscores
def printPath(size):
     
    global Allpaths
     
    # Find the minimum horizontal distance
    # value in current root to leafAllpaths
    minimum_Hd = 10**19
 
    p = []
 
    # Find minimum horizontal distance
    for it in range(size):
        p = Allpaths[it]
        minimum_Hd = min(minimum_Hd, p[0])
 
    # Print the root to leafAllpaths with "_"
    # that indicate the related position
    for it in range(size):
         
        # Current tree node
        p = Allpaths[it]
        noOfUnderScores = abs(p[0] - minimum_Hd)
 
        # Print underscore
        for i in range(noOfUnderScores):
            print(end = "_ ")
 
        # Print current key
        print(p[1])
         
    print("==============================")
 
# A utility function print all path from root to leaf
# working of this function is similar to function of
# "Print_vertical_order" : Print paths of binary tree
# in vertical order
def printAllPathsUtil(root, HD, order):
     
    # Base case
    global Allpaths
 
    if (root == None):
        return
 
    # Leaf node
    if (root.left == None and root.right == None):
         
        # Add leaf node and then print path
        Allpaths[order] = [HD, root.data]
        printPath(order + 1)
        return
 
    # Store current path information
    Allpaths[order] = [HD, root.data]
 
    # Call left sub_tree
    printAllPathsUtil(root.left, HD - 1, order + 1)
 
    # Call left sub_tree
    printAllPathsUtil(root.right, HD + 1, order + 1)
 
def printAllPaths(root):
     
    global Allpaths
     
    # Base case
    if (root == None):
        return
 
    printAllPathsUtil(root, 0, 0)
 
# Driver code
if __name__ == '__main__':
     
    Allpaths = [ [0, 0for i in range(MAX_PATH_SIZE)]
 
    root = Node('A')
    root.left = Node('B')
    root.right = Node('C')
    root.left.left = Node('D')
    root.left.right = Node('E')
    root.right.left = Node('F')
    root.right.right = Node('G')
 
    printAllPaths(root)
 
# This code is contributed by mohit kumar 29


C#




// C# program to print all root to leaf
// paths with there relative position
using System;
using System.Collections.Generic;
public
  class Graph
  {
 
    static readonly int MAX_PATH_SIZE = 1000;
 
    // tree structure
    public
      class Node
      {
        public
          char data;
        public
          Node left, right;
      };
 
    // Function create new node
    static Node newNode(char data)
    {
      Node temp = new Node();
      temp.data = data;
      temp.left = temp.right = null;
      return temp;
    }
 
    // Store path information
    public
 
      class PATH
      {
 
        // Horizontal distance of node from root.
        public
          int Hd;
 
        // Store key
        public
 
          char key;
        public PATH(int Hd, char key)
        {
          this.Hd = Hd;
          this.key = key;
        }
        public PATH()
        {}
      };
 
    // Prints given root to leaf path with underscores
    static void printPath(List<PATH> path, int size)
    {
 
      // Find the minimum horizontal distance value
      // in current root to leaf path
      int minimum_Hd = int.MaxValue;
      PATH p;
 
      // Find minimum horizontal distance
      for(int it = 0; it < size; it++)
      {
        p = path[it];
        minimum_Hd = Math.Min(minimum_Hd, p.Hd);
      }
 
      // Print the root to leaf path with "_"
      // that indicate the related position
      for(int it = 0; it < size; it++)
      {
 
        // Current tree node
        p = path[it];
        int noOfUnderScores = Math.Abs(
          p.Hd - minimum_Hd);
 
        // Print underscore
        for(int i = 0; i < noOfUnderScores; i++)
          Console.Write("_");
 
        // Print current key
        Console.WriteLine(p.key);
      }
      Console.WriteLine("==============================");
    }
 
    // A utility function print all path from root to leaf
    // working of this function is similar to function of
    // "Print_vertical_order" : Print paths of binary tree
    // in vertical order
    static void printAllPathsUtil(Node root,
                                  List<PATH> AllPath,
                                  int HD, int order)
    {
 
      // Base case
      if (root == null)
        return;
 
      // Leaf node
      if (root.left == null && root.right == null)
      {
 
        // Add leaf node and then print path
        AllPath[order] = new  PATH(HD, root.data);
 
        // AllPath[order] = (PATH { HD, root.data });
        printPath(AllPath, order + 1);
        return;
      }
 
      // Store current path information
      AllPath[order]= new PATH(HD, root.data);
 
      // AllPath[order] = (PATH { HD, root.data });
 
      // Call left sub_tree
      printAllPathsUtil(root.left, AllPath,
                        HD - 1, order + 1);
 
      // Call left sub_tree
      printAllPathsUtil(root.right, AllPath,
                        HD + 1, order + 1);
    }
 
    static void printAllPaths(Node root)
    {
 
      // Base case
      if (root == null)
        return;
 
      List<PATH> Allpaths = new List<PATH>();
      for(int i = 0; i < MAX_PATH_SIZE; i++)
      {
        Allpaths.Add(new PATH());
      }
      printAllPathsUtil(root, Allpaths, 0, 0);
    }
 
    // Driver code
    public static void Main(String[] args)
    {
      Node root = newNode('A');
      root.left = newNode('B');
      root.right = newNode('C');
      root.left.left = newNode('D');
      root.left.right = newNode('E');
      root.right.left = newNode('F');
      root.right.right = newNode('G');
 
      printAllPaths(root);
    }
  }
 
// This code is contributed by aashish1995


Javascript




MAX_PATH_SIZE = 1000;
 
class Node {
constructor(x) {
this.data = x;
this.left = null;
this.right = null;
}
}
 
function printPath(size) {
let minimum_Hd = 10**19;
let p = [];
 
for (let it = 0; it < size; it++) {
p = Allpaths[it];
minimum_Hd = Math.min(minimum_Hd, p[0]);
}
 
for (let it = 0; it < size; it++) {
p = Allpaths[it];
let noOfUnderScores = Math.abs(p[0] - minimum_Hd);
for (let i = 0; i < noOfUnderScores; i++) {
  process.stdout.write("_ ");
}
console.log(p[1]);
}
console.log("==============================");
}
 
function printAllPathsUtil(root, HD, order) {
if (root === null) {
return;
}
 
if (root.left === null && root.right === null) {
Allpaths[order] = [HD, root.data];
printPath(order + 1);
return;
}
 
Allpaths[order] = [HD, root.data];
printAllPathsUtil(root.left, HD - 1, order + 1);
printAllPathsUtil(root.right, HD + 1, order + 1);
}
 
function printAllPaths(root) {
if (root === null) {
return;
}
 
Allpaths = new Array(MAX_PATH_SIZE).fill([0, 0]);
 
printAllPathsUtil(root, 0, 0);
}
 
// Driver code
let Allpaths = new Array(MAX_PATH_SIZE).fill([0, 0]);
 
let root = new Node('A');
root.left = new Node('B');
root.right = new Node('C');
root.left.left = new Node('D');
root.left.right = new Node('E');
root.right.left = new Node('F');
root.right.right = new Node('G');
 
printAllPaths(root);


Output

_ _ A
_ B
D
==============================
_ A
B
_ E
==============================
A
_ C
F
==============================
A
_ C
_ _ G
==============================

Time Complexity: O(NH2), where N is the number of nodes and H is the height of the tree.. 
Space Complexity: O(lMAX_PATH_SIZE)

 



Last Updated : 16 Mar, 2023
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