Another interesting question is how can a semicolon be printed without using any semicolon in the program. Here are methods to print “;” :

1. Using printf / putchar in if statement:
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   // CPP program to print  // ; without using ; // using if statement #include <stdio.h> int main() {     // ASCII value of semicolon = 59     if (printf("%c\n", 59))     if (putchar(59))     {     }     return 0; }

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   Output:

   ;
   ;
   

   We can also print the semicolon using switch/ while / for as illustrated in this article.

2. Using macros :
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   // CPP program to print  // ; without using ; // using macros #include <stdio.h> #define GEEK printf("%c",59) int main() {     if (GEEK)     {     } }

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   Output:

   ;
   

Related article: Print Hello World without semicolon in C/C++

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