Another interesting question is how can a semicolon be printed without using any semicolon in the program. Here are methods to print “;” :
- Using printf / putchar in if statement:
// CPP program to print
// ; without using ;
// using if statement
#include <stdio.h>
int
main()
{
// ASCII value of semicolon = 59
if
(
printf
(
"%c\n"
, 59))
if
(
putchar
(59))
{
}
return
0;
}
chevron_rightfilter_noneOutput:
; ;
We can also print the semicolon using switch/ while / for as illustrated in this article.
- Using macros :
// CPP program to print
// ; without using ;
// using macros
#include <stdio.h>
#define GEEK printf("%c",59)
int
main()
{
if
(GEEK)
{
}
}
chevron_rightfilter_noneOutput:
;
Related article: Print Hello World without semicolon in C/C++
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