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How to print a semicolon(;) without using semicolon in C/C++?

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  • Difficulty Level : Easy
  • Last Updated : 14 Jun, 2022

Another interesting question is how can a semicolon be printed without using any semicolon in the program. Here are methods to print “;” :

  1. Using printf / putchar in if statement

CPP




// CPP program to print
// ; without using ;
// using if statement
#include <stdio.h>
int main()
{
    // ASCII value of semicolon = 59
    if (printf("%c\n", 59))
    if (putchar(59))
    {
    }
    return 0;
}

Output:

;
;
  1. We can also print the semicolon using switch/ while / for as illustrated in this article.
  2. Using macros : 

CPP




// CPP program to print
// ; without using ;
// using macros
#include <stdio.h>
#define GEEK printf("%c",59)
int main()
{
    if (GEEK)
    {
    }
}

Output:

;

3. Using std::cout

C++




#include <iostream>
 
// 59 is an ASCII value of the semicolon
#define SEMICOLON 59
 
int main()
{
    if (std::cout << static_cast<char>(SEMICOLON)) {
    }
}

Output

;

Related article: Print Hello World without semicolon in C/C++ If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.


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