Print 2-D co-ordinate points in ascending order followed by their frequencies

Given two arrays x[] and y[] where x[i] represents the x coordinate and y[i] represents the corresponding y coordinate of a 2-D point, the task is to print the co-ordinate points in ascending order followed by their frequencies.

Examples:

Input: x[] = {1, 2, 1, 1, 1}, y[] = {1, 1, 3, 1, 3}
Output:
1 1 2
1 3 2
2 1 1

Input: x[] = {-1, 2, 1, -1, 2}, y[] = {-1, 1, -3, -1, 3}
Output:
-1 -1 2
1 -3 1
2 1 1
2 3 1

Approach: The idea is to use a map having key as pair (x[i], y[i]) and mapped value as integer frequency of the same point. Key value will store the pair of coordinates and mapped value will store their respective frequencies.

Below is the implementation of the above approach:

C++

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// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
  
// Function to print the coordinates along with
// their frequency in ascending order
void Print(int x[], int y[], int n)
{
  
    // map to store the pairs
    // and their frequencies
    map<pair<int, int>, int> m;
  
    // Store the coordinates along
    // with their frequencies
    for (int i = 0; i < n; i++)
        m[make_pair(x[i], y[i])]++;
  
    map<pair<int, int>, int>::iterator i;
  
    for (i = m.begin(); i != m.end(); i++) {
        cout << (i->first).first << " "
             << (i->first).second << " "
             << i->second << "\n";
    }
}
  
// Driver code
int main()
{
    int x[] = { 1, 2, 1, 1, 1 };
    int y[] = { 1, 1, 3, 1, 3 };
    int n = sizeof(x) / sizeof(int);
  
    Print(x, y, n);
  
    return 0;
}

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Python3

# Python3 implementation of the approach

# Function to prthe coordinates along with
# their frequency in ascending order
def Print(x, y, n):

# map to store the pairs
# and their frequencies
m = dict()

# Store the coordinates along
# with their frequencies
for i in range(n):
m[(x[i], y[i])] = m.get((x[i],
y[i]), 0) + 1

e = sorted(m)

for i in e:
print(i[0], i[1], m[i])

# Driver code
x = [1, 2, 1, 1, 1]
y = [1, 1, 3, 1, 3]
n = len(x)

Print(x, y, n)

# This code is contributed
# by mohit kumar

Output:

1 1 2
1 3 2
2 1 1


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Improved By : mohit kumar 29