PHPUnit assertIsNotResource() Function
The assertIsNotResource() function is a builtin function in PHPUnit and is used to assert whether the given variable is not Resource. This assertion will return true in the case if the given variable is not Resource else returns false. In case of true the asserted test case got passed else test case got failed.
Syntax:
assertIsNotResource($actual[, $message = ''])
Parameters: This function accepts two parameters as mentioned above and described below:
- $variable: This parameter is of any type of variable which represents the actual data.
- $message: This parameter takes a string value. When the test case got failed this string message got displayed as error message.
Below examples illustrate the assertIsNotResource() function in PHPUnit:
Example 1:
PHP
<?php
use PHPUnit\Framework\TestCase;
class GeeksPhpunitTestCase extends TestCase
{
public function testNegativeTestcaseForassertIsNotResource()
{
$this ->assertIsNotResource(
$variable ,
"assert variable is not resource"
);
fclose( $variable );
}
}
?>
|
Output:
PHPUnit 8.5.8 by Sebastian Bergmann and contributors.
F 1 / 1 (100%)
Time: 759 ms, Memory: 10.00 MB
There was 1 failure:
1) GeeksPhpunitTestCase::testNegativeTestcaseForassertIsNotResource
assert variable is not resource
Failed asserting that resource(1227) of type (stream) is not of type "resource".
/home/lovely/Documents/php/test.php:14
FAILURES!
Tests: 1, Assertions: 1, Failures: 1.
Example 2:
PHP
<?php
use PHPUnit\Framework\TestCase;
class GeeksPhpunitTestCase extends TestCase
{
public function testNegativeTestcaseForassertIsNotResource()
{
$variable = 555;
$this ->assertIsNotResource(
$variable ,
"assert variable is not resource"
);
}
}
?>
|
Output:
PHPUnit 8.5.8 by Sebastian Bergmann and contributors.
. 1 / 1 (100%)
Time: 88 ms, Memory: 10.00 MB
OK (1 test, 1 assertion)
Last Updated :
07 Aug, 2020
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