Php Program for Maximum difference between groups of size two
Last Updated :
27 Apr, 2023
Given an array of even number of elements, form groups of 2 using these array elements such that the difference between the group with highest sum and the one with lowest sum is maximum.
Note: An element can be a part of one group only and it has to be a part of at least 1 group.
Examples:
Input : arr[] = {1, 4, 9, 6}
Output : 10
Groups formed will be (1, 4) and (6, 9),
the difference between highest sum group
(6, 9) i.e 15 and lowest sum group (1, 4)
i.e 5 is 10.
Input : arr[] = {6, 7, 1, 11}
Output : 11
Groups formed will be (1, 6) and (7, 11),
the difference between highest sum group
(7, 11) i.e 18 and lowest sum group (1, 6)
i.e 7 is 11.
Simple Approach: We can solve this problem by making all possible combinations and checking each set of combination differences between the group with the highest sum and with the lowest sum. A total of n*(n-1)/2 such groups would be formed (nC2).
Time Complexity: O(n^3), because it will take O(n^2) to generate groups and to check against each group n iterations will be needed thus overall it takes O(n^3) time.
Efficient Approach: We can use the greedy approach. Sort the whole array and our result is sum of last two elements minus sum of first two elements.
PHP
<?php
function CalculateMax( $arr , $n )
{
sort( $arr );
$min_sum = $arr [0] +
$arr [1];
$max_sum = $arr [ $n - 1] +
$arr [ $n - 2];
return abs ( $max_sum -
$min_sum );
}
$arr = array (6, 7, 1, 11 );
$n = sizeof( $arr );
echo CalculateMax( $arr , $n ), "
" ;
?>
|
Output:
11
Time Complexity: O (n * log n)
Space Complexity: O(1) as no extra space has been taken.
Further Optimization :
Instead of sorting, we can find a maximum two and minimum of two in linear time and reduce the time complexity to O(n).
Below is the code for the above approach.
PHP
<?php
function CalculateMax( $arr , $n )
{
$first_min = min( $arr );
$second_min = PHP_INT_MAX;
for ( $i = 0; $i < $n ; $i ++)
{
if ( $arr [ $i ] != $first_min )
$second_min = min( $arr [ $i ], $second_min );
}
$first_max = max( $arr );
$second_max = PHP_INT_MIN;
for ( $i = 0; $i < $n ; $i ++)
{
if ( $arr [ $i ] != $first_max )
$second_max = max( $arr [ $i ], $second_max );
}
return abs ( $first_max + $second_max - $first_min - $second_min );
}
$arr = array (6, 7, 1, 11);
$n = sizeof( $arr );
echo CalculateMax( $arr , $n );
?>
|
Time Complexity: O(N)
Auxiliary Space: O(1)
Please refer complete article on Maximum difference between groups of size two for more details!
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