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PHP | Imagick displayImage() Function

  • Last Updated : 17 Sep, 2019

The Imagick::displayImage() function is an inbuilt function in PHP which is used to displays an image object.

Syntax:

bool Imagick::displayImage( $servername )

Parameters: This function accepts a single parameter $servername which is used to specify the server name.

Return Value: This function returns True on success.

Below programs illustrate the Imagick::displayImage() function in PHP:



Program:




<?php
  
// Create an Imagick object
$imagick = new Imagick(
  
// Use displayImage function
$imagick->displayImage(5);
  
header("Content-Type: image/jpg");
  
// Display the output image
echo $imagick->getImageBlob();
?>

Output:
oil paint image

Program 2:




<?php
$string = "Computer Science portal for Geeks!";
  
// creating new image of above String 
// and add color and background 
$im = new Imagick();
$draw = new ImagickDraw();
  
// Fill the color in image 
$draw->setFillColor(new ImagickPixel('green'));
  
// Set the text font size 
$draw->setFontSize(50);
  
$metrix = $im->queryFontMetrics($draw, $string);
$draw->annotation(0, 40, $string);
$im->newImage($metrix['textWidth'], $metrix['textHeight'],
         new ImagickPixel('white'));
  
// Draw the image          
$im->drawImage($draw);
  
$im->setImageFormat('jpeg');
  
header("Content-Type: image/jpg");
  
// Display the output image
echo $im->getImageBlob();
?>

Output:
https://media.geeksforgeeks.org/wp-content/uploads/Screenshot-from-2018-10-16-23-23-54-1.png

Reference: http://php.net/manual/en/imagick.displayimage.php




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