Perfect Square String

Given a String str and the task is to check sum of ASCII value of all characters is a perfect square or not.

Examples :

Input : ddddddddddddddddddddddddd
Output : Yes

Input : GeeksForGeeks
Output : No

Algorithm

  • Calculate the string length
  • Calculate sum of ASCII value of all characters
  • Take the square root of the number sum and store it into variable squareRoot
  • Take floor value of the squareRoot and subtract from squareRoot
  • If the difference of floor value of squareRoot and squareRoot is 0 then print “Yes” otherwise “No”

Below is the implementation of the above approach :

C++

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// C++ program to find if string is a
// perfect square or not.
#include <bits/stdc++.h>
using namespace std;
  
bool isPerfectSquareString(string str)
{
    int sum = 0;
      
    // calculating the length of
    // the string
    int len = str.length();
      
    // calculating the ASCII value
    // of the string
    for (int i = 0; i < len; i++)
        sum += (int)str[i];
      
    // Find floating point value of
    // square root of x.
    long double squareRoot = sqrt(sum);
      
    // If square root is an integer
    return ((squareRoot - 
             floor(squareRoot)) == 0);
}
  
// Driver code
int main()
{
    string str = "d";
      
    if (isPerfectSquareString(str))
        cout << "Yes";
    else
        cout << "No";
}

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Java














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// Java program to find if string 


// is a perfect square or not. 


import java.io.*; 


  


class GFG { 


      


    static boolean isPerfectSquareString(String str) 


    { 


        int sum = 0; 


          


        // calculating the length 


        // of the string 


        int len = str.length(); 


          


        // calculating the ASCII  


        // value of the string 


        for (int i = 0; i < len; i++) 


            sum += (int)str.charAt(i); 


          


        // Find floating point value 


        // of square root of x. 


        long squareRoot = (long)Math.sqrt(sum); 


          


        // If square root is an integer 


        return ((squareRoot -  


                Math.floor(squareRoot)) == 0); 


    } 


  


    // Driver code 


    public static void main (String[] args) 


    { 


        String str = "d"; 


      


        if (isPerfectSquareString(str)) 


            System.out.println("Yes"); 


        else


            System.out.println("No"); 


    } 


} 


  


// This code is contributed by Ajit. 



















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Python3














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# Python3 program to find  


# if string is a perfect  


# square or not. 


import math; 


def isPerfectSquareString(str): 


    sum = 0; 


      


    # calculating the length 


    # of the string 


    l = len(str); 


      


    # calculating the ASCII  


    # value of the string 


    for i in range(l): 


        sum = sum + ord(str[i]); 


      


    # Find floating point value 


    # of square root of x. 


    squareRoot = math.sqrt(sum); 


      


    # If square root is an integer 


    return ((squareRoot -


             math.floor(squareRoot)) == 0); 


  


# Driver code 


str = "d"; 


  


if (isPerfectSquareString(str)): 


    print("Yes"); 


else: 


    print("No"); 


  


# This code is contributed by mits 



















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C#














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// C# program to find if string 


// is a perfect square or not. 


using System; 


  


class GFG 


{ 


    static bool isPerfectSquareString(string str) 


    { 


        int sum = 0; 


          


        // calculating the length 


        // of the string 


        int len = str.Length; 


          


        // calculating the ASCII  


        // value of the string 


        for (int i = 0; i < len; i++) 


            sum += (int)str[i]; 


          


        // Find floating point value 


        // of square root of x. 


        double squareRoot = Math.Sqrt(sum); 


        double F = Math.Floor(squareRoot); 


  


        // If square root is an integer 


        return ((squareRoot - F) == 0); 


    } 


  


    // Driver Code 


    public static void Main() 


    { 


        string str = "d"; 


      


        if (isPerfectSquareString(str)) 


            Console.WriteLine("Yes"); 


        else


            Console.WriteLine("No"); 


    } 


} 


  


// This code is contributed by Sam007 



















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PHP














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<?php 


// PHP program to find if string  


// is a perfect square or not. 


  


function isPerfectSquareString($str) 


{ 


    $sum = 0; 


      


    // calculating the length 


    // of the string 


    $len = strlen($str); 


      


    // calculating the ASCII  


    // value of the string 


    for ($i = 0; $i < $len; $i++) 


        $sum += (int)$str[$i]; 


      


    // Find floating point value  


    // of square root of x. 


    $squareRoot = sqrt($sum); 


      


    // If square root is an integer 


    return (($squareRoot -  


            floor($squareRoot)) == 0); 


} 


  


// Driver code 


$str = "d"; 


  


if (isPerfectSquareString($str)) 


    echo "Yes"; 


else


echo "No"; 


  


// This code is contributed by m_kit 


?> 



















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Output :


Yes






          
          
          
          

            

    

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Improved By :  jit_t, Sam007, Mithun Kumar