# Pandigital number in a given base

• Difficulty Level : Easy
• Last Updated : 20 Oct, 2022

Given an integer n and its base b. The task is to check if given number is Pandigital Number in the given base or not. A Pandigital number is an integer that has each digit of its base at least once.
It may be assumed that base is smaller than or equal to 36. In base 36, digits are [0, 1, …9. A, B, …Z]
Examples :

Input : n = “9651723480”, b = 10
Output : Yes
Given number n has all digits from 0 to 9

Input : n = “23456789ABCDEFGHIJKLMNOPQRSTUVWXYZ”,
b = 36
Output : No
Given number n doesn’t have all digits in base 36. For example 1 is missing.

Make a boolean hash array of size equal to base of the number and initialize it with false. Now, iterate each digit of the number mark its corresponding index value as true in the hash array. In the end, check whether all the value in hash array are marked or not, if marked print “Yes” i.e Pandigital number else print “No”.

Below is the implementation of this approach:

## C++

 `// C++ program to check if a number is pandigital``// in given base.``#include ``using` `namespace` `std;` `// Return true if n is pandigit else return false.``bool` `checkPandigital(``int` `b, ``char` `n[])``{``    ``// Checking length is less than base``    ``if` `(``strlen``(n) < b)``        ``return` `false``;` `    ``bool` `hash[b];``    ``memset``(hash, ``false``, ``sizeof``(hash));` `    ``// Traversing each digit of the number.``    ``for` `(``int` `i = 0; i < ``strlen``(n); i++) {``        ``// If digit is integer``        ``if` `(n[i] >= ``'0'` `&& n[i] <= ``'9'``)``            ``hash[n[i] - ``'0'``] = ``true``;` `        ``// If digit is alphabet``        ``else` `if` `(n[i] - ``'A'` `<= b - 11)``            ``hash[n[i] - ``'A'` `+ 10] = ``true``;``    ``}` `    ``// Checking hash array, if any index is``    ``// unmarked.``    ``for` `(``int` `i = 0; i < b; i++)``        ``if` `(hash[i] == ``false``)``            ``return` `false``;` `    ``return` `true``;``}` `// Driver Program``int` `main()``{``    ``int` `b = 13;``    ``char` `n[] = ``"1298450376ABC"``;` `    ``(checkPandigital(b, n)) ? (cout << ``"Yes"` `<< endl)``                            ``: (cout << ``"No"` `<< endl);` `    ``return` `0;``}`

## Java

 `// Java program to check if a number``// is pandigital in given base.``import` `java.util.*;` `class` `GFG {` `    ``// Return true if n is pandigit``    ``// else return false.``    ``static` `boolean` `checkPandigital(``int` `b, String n)``    ``{` `        ``// Checking length is less than base``        ``if` `(n.length() < b)``            ``return` `false``;` `        ``boolean` `hash[] = ``new` `boolean``[b];``        ``Arrays.fill(hash, ``false``);` `        ``// Traversing each digit of the number.``        ``for` `(``int` `i = ``0``; i < n.length(); i++) {` `            ``// If digit is integer``            ``if` `(n.charAt(i) >= ``'0'` `&& n.charAt(i) <= ``'9'``)``                ``hash[n.charAt(i) - ``'0'``] = ``true``;` `            ``// If digit is alphabet``            ``else` `if` `(n.charAt(i) - ``'A'` `<= b - ``11``)``                ``hash[n.charAt(i) - ``'A'` `+ ``10``] = ``true``;``        ``}` `        ``// Checking hash array, if any``        ``// index is unmarked.``        ``for` `(``int` `i = ``0``; i < b; i++)``            ``if` `(hash[i] == ``false``)``                ``return` `false``;` `        ``return` `true``;``    ``}` `    ``// Driver code``    ``public` `static` `void` `main(String[] args)``    ``{``        ``int` `b = ``13``;``        ``String n = ``"1298450376ABC"``;` `        ``if` `(checkPandigital(b, n))``            ``System.out.println(``"Yes"``);``        ``else``            ``System.out.println(``"No"``);``    ``}``}` `// This code is contributed by Anant Agarwal.`

## Python3

 `# Python3 program to check if a number is``# pandigital in given base.` `# Return true if n is pandigit else return false.`  `def` `checkPandigital(b, n):` `    ``# Checking length is less than base``    ``if` `(``len``(n) < b):``        ``return` `0` `    ``hash` `=` `[``0``] ``*` `b` `    ``# Traversing each digit of the number.``    ``for` `i ``in` `range``(``len``(n)):` `        ``# If digit is integer``        ``if` `(n[i] >``=` `'0'` `and` `n[i] <``=` `'9'``):``            ``hash``[``ord``(n[i]) ``-` `ord``(``'0'``)] ``=` `1` `        ``# If digit is alphabet``        ``else` `if` `(``ord``(n[i]) ``-` `ord``(``'A'``) <``=` `b ``-` `11``):``            ``hash``[``ord``(n[i]) ``-` `ord``(``'A'``) ``+` `10``] ``=` `1` `    ``# Checking hash array, if any index is``    ``# unmarked.``    ``for` `i ``in` `range``(b):``        ``if` `(``hash``[i] ``=``=` `0``):``            ``return` `0` `    ``return` `1`  `# Driver Code``b ``=` `13``n ``=` `"1298450376ABC"` `if``(checkPandigital(b, n)):``    ``print``(``"Yes"``)``else``:``    ``print``(``"No"``)` `# This code is contributed by mits`

## C#

 `// C# program to check if a number``// is pandigital in given base.``using` `System;` `class` `GFG {` `    ``// Return true if n is pandigit``    ``// else return false.``    ``static` `bool` `checkPandigital(``int` `b, ``string` `n)``    ``{` `        ``// Checking length is less than base``        ``if` `(n.Length < b)``            ``return` `false``;` `        ``bool``[] hash = ``new` `bool``[b];``        ``for` `(``int` `i = 0; i < b; i++)``            ``hash[i] = ``false``;` `        ``// Traversing each digit of the number.``        ``for` `(``int` `i = 0; i < n.Length; i++) {` `            ``// If digit is integer``            ``if` `(n[i] >= ``'0'` `&& n[i] <= ``'9'``)``                ``hash[n[i] - ``'0'``] = ``true``;` `            ``// If digit is alphabet``            ``else` `if` `(n[i] - ``'A'` `<= b - 11)``                ``hash[n[i] - ``'A'` `+ 10] = ``true``;``        ``}` `        ``// Checking hash array, if any``        ``// index is unmarked.``        ``for` `(``int` `i = 0; i < b; i++)``            ``if` `(hash[i] == ``false``)``                ``return` `false``;` `        ``return` `true``;``    ``}` `    ``// Driver code``    ``public` `static` `void` `Main()``    ``{``        ``int` `b = 13;``        ``String n = ``"1298450376ABC"``;` `        ``if` `(checkPandigital(b, n))``            ``Console.Write(``"Yes"``);``        ``else``            ``Console.Write(``"No"``);``    ``}``}` `// This code is contributed by nitin mittal.`

## PHP

 `= ``'0'` `&& ``\$n``[``\$i``] <= ``'9'``)``            ``\$hash``[``\$n``[``\$i``] - ``'0'``] = 1;` `        ``// If digit is alphabet``        ``else` `if` `(ord(``\$n``[``\$i``]) - ord(``'A'``) <= ``\$b` `- 11)``            ``\$hash``[ord(``\$n``[``\$i``]) - ord(``'A'``) + 10] = 1;``    ``}` `    ``// Checking hash array, if any index is``    ``// unmarked.``    ``for` `(``\$i` `= 0; ``\$i` `< ``\$b``; ``\$i``++)``        ``if` `(``\$hash``[``\$i``] == 0)``            ``return` `0;` `    ``return` `1;``}` `// Driver Program``\$b` `= 13;``\$n` `= ``"1298450376ABC"``;` `if``(checkPandigital(``\$b``, ``\$n``))``    ``echo` `"Yes"``;``else``    ``echo` `"No"``;``                ` `// This code is contributed by Sam007.``?>`

## Javascript

 ``

Output

```Yes
```

Time Complexity: O(b + strlen(n))
Auxiliary Space: O(b)

Reference:
https://en.wikipedia.org/wiki/Pandigital_number
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