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Output of python program | Set 14 (Dictionary)

  • Difficulty Level : Medium
  • Last Updated : 23 Jun, 2021

Prerequisite: Dictionary 
Note: Output of all these programs is tested on Python3
1) What is the output of the following program? 
 

PYTHON3




D = dict()
for x in enumerate(range(2)):
    D[x[0]] = x[1]
    D[x[1]+7] = x[0]
print(D)

a) KeyError 
b) {0: 1, 7: 0, 1: 1, 8: 0} 
c) {0: 0, 7: 0, 1: 1, 8: 1} 
d) {1: 1, 7: 2, 0: 1, 8: 1} 
Ans. (c) 
Explanation: enumerate() will return a tuple, the loop will have x = (0, 0), (1, 1). Thus D[0] = 0, D[1] = 1, D[0 + 7] = D[7] = 0 and D[1 + 7] = D[8] = 1. 
Note: Dictionary is unordered, so the sequence of the key-value pair may differ in each output.
2) What is the output of the following program? 
 

PYTHON3




D = {1 : 1, 2 : '2', '1' : 2, '2' : 3}
D['1'] = 2
print(D[D[D[str(D[1])]]])

a) 2 
b) 3 
c) ‘2’ 
d) KeyError 
Ans. (b) 
Explanation: Simple key-value pair is used recursively, D[1] = 1, str(1) = ‘1’. So, D[str(D[1])] = D[‘1’] = 2, D[2] = ‘2’ and D[‘2’] = 3.
3) What is the output of the following program? 
 

PYTHON3




D = {1 : {'A' : {1 : "A"}, 2 : "B"}, 3 :"C", 'B' : "D", "D": 'E'}
print(D[D[D[1][2]]], end = " ")
print(D[D[1]["A"][2]])

a) D C 
b) E B 
c) D B 
d) E KeyError 
Ans. (d) 
Explanation: Key-Value Indexing is used in the example above. D[1] = {‘A’ : {1 : “A”}, 2 : “B”}, D[1][2] = “B”, D[D[1][2]] = D[“B”] = “D” and D[“D”] = “E”. D[1] = {‘A’ : {1 : “A”}, 2 : “B”}, D[1][“A”] = {1 : “A”} and D[1][“A”][2] doesn’t exists, thus KeyError.
4) What is the output of the following program? 
 

PYTHON3




D = dict()
for i in range (3):
    for j in range(2):
        D[i] = j
print(D)

a) {0: 0, 1: 0, 2: 0} 
b) {0: 1, 1: 1, 2: 1} 
c) {0: 0, 1: 0, 2: 0, 0: 1, 1: 1, 2: 1} 
d) TypeError: Immutable object 
Ans. (b) 
Explanation: 1st loop will give 3 values to i 0, 1 and 2. In the empty dictionary, valued are added and overwrited in j loop, for eg. D[0] = [0] becomes D[0] = 1, due to overwriting.
5) Which of the options below could possibly be the output of the following program? 
 

PYTHON3




D = {1 : [1, 2, 3], 2: (4, 6, 8)}
D[1].append(4)
print(D[1], end = " ")
L = [D[2]]
L.append(10)
D[2] = tuple(L)
print(D[2])

a) [1, 2, 3, 4] [4, 6, 8, 10] 
b) [1, 2, 3, 4] ((4, 6, 8), 10) 
c) ‘[1, 2, 3, 4] TypeError: tuples are immutable 
d) [1, 2, 3, 4] (4, 6, 8, 10) 
Ans. (b) 
Explanation: In the first part key-value indexing is used and 4 is appended into the list. As tuples are immutable, in the second part the tuple is converted into a list, and value 10 is added finally to the new list ‘L’ then converted back to a tuple.
This article is contributed by Piyush Doorwar. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks. 
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
 




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