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Output of the Program | Use Macros Carefully!

  • Difficulty Level : Easy
  • Last Updated : 27 Dec, 2016

Predict the output of the below program

#define square(x) x*x
int main()
  int x;
  x = 36/square(6);
  return 0;

Output: 36

Preprocessor replaces square(6) by 6*6 and the expression becomes x = 36/6*6 and value of x is calculated as 36. If we want correct behavior from macro square(x), we should declare it as

#define square(x) ((x)*(x)) /* Note that the expression
(x*x) will also fail for square(6-2) */

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