Output of the Program | Use Macros Carefully!
Predict the output of the below program
C++
#include <iostream>
using namespace std;
#define square(x) x*x
int main()
{
int x;
x = 36 / square(6);
cout << x;
return 0;
}
|
C
#include <stdio.h>
#define square(x) x*x
int main()
{
int x;
x = 36/square(6);
printf ( "%d" ,x);
getchar ();
return 0;
}
|
Explanation: Preprocessor replaces square(6) by 6*6 and the expression becomes x = 36/6*6 and value of x is calculated as 36. If we want correct behavior from macro square(x), we should declare it as #define square(x) ((x)*(x)) /* Note that the expression (x*x) will also fail for square(6-2) */
Last Updated :
21 Jun, 2022
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