# Output of C++ programs | Set 48 (Bit Manipulation)

**Q.1** What Is The Output Of this program ?

`#include <iostream>` `using` `namespace` `std;` `int` `main()` `{` ` ` `int` `a = 35;` ` ` `int` `b = 12;` ` ` `printf` `(` `"%d "` `, ~a);` ` ` `printf` `(` `"%d "` `, ~ - b);` ` ` `return` `0;` `}` |

**Option**

a) -36 11

b) -35 -12

c) 220 11

d) 36 11

ans :-a

**Explanation**:- For any integer n, bitwise complement of n always will be -(n+1). so here -(35+1) and-(-12+1).

**Q.2** What Is The Output Of this program ?

`#include <iostream>` `using` `namespace` `std;` `int` `main()` `{` ` ` `int` `a = 12;` ` ` `int` `b = 25;` ` ` `int` `c = 1;` ` ` `printf` `(` `"%d"` `, a ^ b && c);` ` ` `return` `0;` `}` |

**Option**

a) 300

b) 1

c) 25

d) 212

ans :-b

**Explanation**:- In This program, we simple perform a XOR operation between 12(1010) and 25(11001) so result is(10011) equal to the 21, then perform and operation.

**Q.3** What Is The Output Of this program ?

`#include <iostream>` `using` `namespace` `std;` `int` `main()` `{` ` ` `unsigned ` `char` `a = -8;` ` ` `unsigned ` `char` `b = a >> 1;` ` ` `printf` `(` `"%d\n"` `, b);` `}` |

**Option**

a) 128

b) -8

c) -4

d) 124

ans :-d

**Explanation**:- We know that Negative numbers are represented using 2’s complement of its positive equivalent. So the 2’s complement of 8 is (11111000) and we shifted its 1 so its (01111100) is 124.

**Q.4** What Is The Output Of this program ?

`#include <iostream>` `using` `namespace` `std;` `int` `main()` `{` ` ` `signed` `char` `a = -128;` ` ` `signed` `char` `b = a >> 1;` ` ` `printf` `(` `"%d\n"` `, b);` ` ` `return` `0;` `}` |

**Option** c

a) 128

b) 256

c) -64

d) 64

ans :--64

**Explanation**:- In this code, we are right shifting -128 by 1. The result will be “-64”, binary shift is applied since the operand is a signed value are printed.

**Q.5** What Is The Output Of this program ?

`#include <iostream>` `using` `namespace` `std;` `int` `main()` `{` ` ` `unsigned ` `int` `x = 3;` ` ` `x = x | (x << x);` ` ` `cout << x;` ` ` `return` `0;` `}` |

**Option**

a) 27

b) 24

c) 1

d) 0

ans :-a

**Explanation**:- In this program integer a is 3 its binary (011) shifted 3 its(011000) equal to the 24 and add 3 so its equal to the 27.

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