# Order of teams in a tournament such that every team has won against its consecutive team

• Last Updated : 27 Jul, 2020

Given N teams and the results of round-robin tournament in which no match resulted is draw or tie. The task is to find the order of the teams such that every team has won against its consecutive team.

Examples:

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Input: N = 4
results[] = {{1, 4}, {4, 3}, {2, 3}, {1, 2}, {2, 1}, {3, 1}, {2, 4}}
Output: 2 4 3 1
Explanation:
Team-2 has won against Team-4, in the last match.
Team-3 has lost to Team-4 in the 2nd match and
Team-3 won against Team-1 in the second last match.
Therefore, every team has won against the team next to itself.

Input: N = 5
results[] = {{1, 4}, {4, 3}, {2, 3}, {1, 2}, {2, 1},
{3, 1}, {4, 2}, {2, 5}, {5, 3}, {4, 5}, {5, 1}}
Output: 4 2 5 3 1

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: The idea is to maintain a hash-map for every team which stores the teams against which the team has won in the round-robin tournament. This can be done by iterating over the elements of the results and for each winner append it to the list of the hash-map object of that team.

```The hashtable for an example is as follows:

Key          Value

Team-1 => [Team-4, Team-2]
Team-2 => [Team-3, Team-1, Team-4]
Team-3 => [Team-1]
Team-4 => [Team-3]
```

Finally, compute the order of teams using recursively. Below is the illustration of the recursive function:

• Base Case: When the current length of the teams is 1, return the team.
• Recursive Case: Compute the order of the N – 1 team and after the computation of the teams, Iterate over the order of the teams and find a position where the current team has lost against its previous team. If there is no such position append the team at the last position.

Below is the implementation of the above approach:

## Java

 `// Java implementation to find the``// order of the teams in a round``// robin tournament such that every``// team has won against to its next team`` ` `import` `java.util.*;``import` `java.lang.*;`` ` `// A class to represent result``// of a match of a tournament.``class` `Result {``    ``int` `winner;``    ``int` `loser;`` ` `    ``Result(``int` `winner, ``int` `loser)``    ``{``        ``this``.winner = winner;``        ``this``.loser = loser;``    ``}``}`` ` `public` `class` `TeamOrdering {`` ` `    ``// Function to arrange the teams of``    ``// the round-robin tournament``    ``static` `void` `arrangeTeams(``int``[] teams,``                             ``Result[] results)``    ``{``        ``HashMap >``            ``map = ``new` `HashMap<>();``        ``int` `winner = ``0``;`` ` `        ``// Creating a hashmap of teams``        ``// and the opponents against``        ``// which they have won, using``        ``// the results of the tournament``        ``for` `(``int` `i = ``0``; i < results.length; i++) {``            ``winner = results[i].winner;``            ``if` `(map.containsKey(winner)) {``                ``map.get(winner).add(``                    ``results[i].loser);``            ``}``            ``else` `{``                ``List list``                    ``= ``new` `ArrayList();``                ``list.add(results[i].loser);``                ``map.put(winner, list);``            ``}``        ``}``        ``List output = ``new` `ArrayList<>();`` ` `        ``// Arrange the teams in required order``        ``setInOrder(teams, map, teams.length, output);``        ``Iterator it = output.iterator();`` ` `        ``// Displaying the final output``        ``while` `(it.hasNext()) {``            ``System.out.print(it.next());``            ``System.out.print(``" "``);``        ``}``    ``}`` ` `    ``// Function to determine``    ``// the order of teams``    ``static` `void` `setInOrder(``        ``int``[] teams,``        ``HashMap > map,``        ``int` `n, List output)``    ``{``        ``// Base Cases``        ``if` `(n < ``1``) {``            ``return``;``        ``}``        ``// If there is only 1 team,``        ``// add it to the output``        ``else` `if` `(n == ``1``) {``            ``output.add(teams[n - ``1``]);``            ``return``;``        ``}`` ` `        ``// Recursive call to generate``        ``// output for N-1 teams``        ``setInOrder(teams, map, n - ``1``, output);``        ``int` `key = teams[n - ``1``];``        ``int` `i;`` ` `        ``// Finding the position for the``        ``// current team in the output list.``        ``for` `(i = ``0``; i < output.size(); i++) {`` ` `            ``// Obtain the team at current``            ``// index in the list``            ``int` `team = output.get(i);`` ` `            ``// Check if it has lost against``            ``// current team``            ``List losers = map.get(key);``            ``if` `(losers.indexOf(team) != -``1``)``                ``break``;``        ``}``        ``// Add the current team``        ``// to its final position``        ``output.add(i, key);``    ``}`` ` `    ``// Driver Code``    ``public` `static` `void` `main(String[] args)``    ``{``        ``int``[] teams = { ``1``, ``2``, ``3``, ``4` `};``        ``Result[] results = {``            ``new` `Result(``1``, ``4``),``            ``new` `Result(``4``, ``3``),``            ``new` `Result(``2``, ``3``),``            ``new` `Result(``1``, ``2``),``            ``new` `Result(``2``, ``1``),``            ``new` `Result(``3``, ``1``),``            ``new` `Result(``2``, ``4``)``        ``};`` ` `        ``// Function Call``        ``arrangeTeams(teams, results);``    ``}``}`
Output:
```2 4 3 1
```

Performance Analysis:

• Time Complexity: O(N2)
• Auxiliary Space: O(N)

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