# Optimal Strategy for a Game | Special Gold Coin

Given a row of silver coins among which a special gold coin is present. Two players play the game, and with each move, a player has to remove a coin from either the left or the right end of the row and the player who removes the special coin wins the game. The task is to find the winner of the game.

Examples:

Input: str = “GSSS”
Output: First
The first player directly removes the special gold coin.

Input: str = “SGS”
Output: Second
Irrespective of which coin the first player removes, the special
gold coin becomes exposed and is removed by the second player.

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: It can be observed by taking a few examples that if the count of the silver coins is odd then the first player wins the game otherwise the player two wins the game. In special case when Gold coin is in corner, First player will be the winner regardless the count of silver coins.

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach ` `#include ` `using` `namespace` `std; ` ` `  `// Function to return the ` `// winner of the game ` `string getWinner(string str, ``int` `len) ` `{ ` `     `  `    ``// To store the count of silver coins ` `    ``int` `total = 0; ` `     `  `    ``if``(str==``'G'` `||str[len-1]==``'G'``) ` `        ``return` `"First"``; ` `    ``else``{ ` `        ``for` `(``int` `i = 0; i < len; i++) { ` ` `  `            ``// Update the position of ` `           ``// the gold coin ` `            ``if` `(str[i] == ``'S'``) { ` `                ``total++; ` `            ``} ` `        ``} ` ` `  `        ``// First player will win the game ` `        ``if` `((total % 2) == 1) ` `            ``return` `"First"``; ` `        ``return` `"Second"``; ` `    ``} ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``string str = ``"GSSS"``; ` `    ``int` `len = str.length(); ` ` `  `    ``cout << getWinner(str, len); ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java implementation of the approach ` `import` `java.util.*; ` ` `  `class` `GFG ` `{ ` ` `  `// Function to return the ` `// winner of the game ` `static` `String getWinner(String str, ``int` `len) ` `{ ` ` `  `    ``// To store the count of silver coins ` `    ``int` `total = ``0``; ` `    ``for` `(``int` `i = ``0``; i < len; i++)  ` `    ``{ ` ` `  `        ``// Update the position of ` `        ``// the gold coin ` `        ``if` `(str.charAt(i) == ``'S'``) ` `        ``{ ` `            ``total++; ` `        ``} ` `    ``} ` ` `  `    ``// First player will win the game ` `    ``if` `((total % ``2``) == ``1``) ` `        ``return` `"First"``; ` `    ``return` `"Second"``; ` `} ` ` `  `// Driver code ` `public` `static` `void` `main(String []args) ` `{ ` `    ``String str = ``"GSSS"``; ` `    ``int` `len = str.length(); ` ` `  `    ``System.out.println(getWinner(str, len)); ` `} ` `} ` ` `  `// This code is contributed by Surendra_Gangwar `

## Python3

 `# Python3 implementation of the approach  ` ` `  `# Function to return the  ` `# winner of the game  ` `def` `getWinner(string, length) : ` ` `  `    ``# To store the count of silver coins  ` `    ``total ``=` `0``;  ` `    ``for` `i ``in` `range``(length) :  ` ` `  `        ``# Update the position of  ` `        ``# the gold coin  ` `        ``if` `(string[i] ``=``=` `'S'``) : ` `            ``total ``+``=` `1``;  ` ` `  `    ``# First player will win the game  ` `    ``if` `((total ``%` `2``) ``=``=` `1``) : ` `        ``return` `"First"``;  ` `    ``return` `"Second"``;  ` ` `  `# Driver code  ` `if` `__name__ ``=``=` `"__main__"` `:  ` ` `  `    ``string ``=` `"GSSS"``;  ` `    ``length ``=` `len``(string);  ` ` `  `    ``print``(getWinner(string, length));  ` `     `  `# This code is contributed by kanugargng `

Output:

```First
```

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